Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The function will not work as expected because **the recursion does not have a base case**. Without a base case to stop the recursive calls to `make_op_with_history`, the function will keep calling itself indefinitely, eventually leading to a `RecursionError`.
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. The function will not work as expected because **the recursion does not have a base case**. Without a base case to stop the recursive calls to `make_op_with_history`, the function will keep calling itself indefinitely, eventually leading to a `RecursionError`. Answer either 'The student passes' or 'The student fails'.
The student fails.
Testing if the previous output contains the string student passes
: False
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The function will not work as expected because **it does not handle recursive calls on lists within lists within `config`**. The code only iterates through the elements of `args`, which are the direct elements of the `config` list. If an element within `args` is itself a list, the function does not recursively call `make_op_with_history` on that nested list. This means any nested operations will be ignored.
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. The function will not work as expected because **it does not handle recursive calls on lists within lists within `config`**. The code only iterates through the elements of `args`, which are the direct elements of the `config` list. If an element within `args` is itself a list, the function does not recursively call `make_op_with_history` on that nested list. This means any nested operations will be ignored. Answer either 'The student passes' or 'The student fails'.
The student fails.
Testing if the previous output contains the string student passes
: False
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The function uses recursion without a base case. If any `config[1]` is ever not a list with at least one element, the recursion will continue infinitely and eventually cause a stack overflow.
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. The function uses recursion without a base case. If any `config[1]` is ever not a list with at least one element, the recursion will continue infinitely and eventually cause a stack overflow. Answer either 'The student passes' or 'The student fails'.
The student fails. The provided answer does not explicitly state that the code should replace `append` with `extend`. Instead, it discusses an issue with recursion and the lack of a base case, which is unrelated to the specific problem of using `append` instead of `extend`.
Testing if the previous output contains the string student passes
: False
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The function uses recursion without a base case, potentially leading to infinite recursion and a `RecursionError`.
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. The function uses recursion without a base case, potentially leading to infinite recursion and a `RecursionError`. Answer either 'The student passes' or 'The student fails'.
The student fails.
Testing if the previous output contains the string student passes
: False
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The function uses recursion without a base case for non-matching `how` values. If `how.split()[0]` is neither 'dot_from_papers', 'const_add', nor 'const_mul', the function will enter the final `for arg in args` loop and call itself recursively with potentially unchanged arguments, leading to infinite recursion.
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. The function uses recursion without a base case for non-matching `how` values. If `how.split()[0]` is neither 'dot_from_papers', 'const_add', nor 'const_mul', the function will enter the final `for arg in args` loop and call itself recursively with potentially unchanged arguments, leading to infinite recursion. Answer either 'The student passes' or 'The student fails'.
The student fails. While the student correctly identifies an issue with the recursion and the lack of a base case for non-matching `how` values, they do not address the specific problem mentioned in the question, which is the use of `append` instead of `extend`. The answer does not mention that the code should replace `append` with `extend`.
Testing if the previous output contains the string student passes
: False