Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The function `make_op_with_history` will not work as expected because it attempts to concatenate a list (`out`) with a tuple `[(how, make_op(config))]` in the final `return` statement. Specifically, `out` is a list of lists (since `make_op_with_history` returns a list), and you cannot directly concatenate a list of lists with a single list. This will result in a `TypeError`. For example, if `out` is `[[(a, b)], [(c, d)]]` and `[(how, make_op(config))]` is `[(x, y)]`, the concatenation `[(x, y)] + [[(a, b)], [(c, d)]]` is invalid because you cannot mix a list of tuples with a list of lists. To fix this, you would need to flatten `out` or handle the concatenation differently.
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. The function `make_op_with_history` will not work as expected because it attempts to concatenate a list (`out`) with a tuple `[(how, make_op(config))]` in the final `return` statement. Specifically, `out` is a list of lists (since `make_op_with_history` returns a list), and you cannot directly concatenate a list of lists with a single list. This will result in a `TypeError`. For example, if `out` is `[[(a, b)], [(c, d)]]` and `[(how, make_op(config))]` is `[(x, y)]`, the concatenation `[(x, y)] + [[(a, b)], [(c, d)]]` is invalid because you cannot mix a list of tuples with a list of lists. To fix this, you would need to flatten `out` or handle the concatenation differently. Answer either 'The student passes' or 'The student fails'.
The student fails.
Testing if the previous output contains the string student passes
: False