Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Here's a Python program that should do what you're asking for: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

# Query the database to find the youngest person who isn't anyone's favorite friend
query = '''
    SELECT MIN(age) AS min_age
    FROM people
    WHERE favorite_friend IS NULL;
'''
cursor.execute(query)
min_age = cursor.fetchone()[0]

query = '''
    SELECT favorite_friend
    FROM people
    WHERE age = ? AND favorite_friend IS NULL;
'''
cursor.execute(query, (min_age,))
favorite_friend = cursor.fetchone()[0]

# Close the database connection
conn.close()

# Print the result
if favorite_friend is not None:
    print(f'The favorite friend of the youngest person who isn\'t anyone\'s favorite friend is {favorite_friend}.')
else:
    print('There is no such person.')
Note that this program assumes that the `age` column contains unique values for each person, or that there is only one youngest person who isn't anyone's favorite friend. If there are multiple such people, this program will just return the favorite friend of one of them. If you want to handle this case differently, you may need to modify the query. Also, this program assumes that the `favorite_friend` column can contain `NULL` values to indicate that a person does not have a favorite friend. If this is not the case, you may need to modify the query to handle this differently. I hope this helps! Let me know if you have any questions.

Extract Code

I extracted the following code from that output: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

# Query the database to find the youngest person who isn't anyone's favorite friend
query = '''
    SELECT MIN(age) AS min_age
    FROM people
    WHERE favorite_friend IS NULL;
'''
cursor.execute(query)
min_age = cursor.fetchone()[0]

query = '''
    SELECT favorite_friend
    FROM people
    WHERE age = ? AND favorite_friend IS NULL;
'''
cursor.execute(query, (min_age,))
favorite_friend = cursor.fetchone()[0]

# Close the database connection
conn.close()

# Print the result
if favorite_friend is not None:
    print(f'The favorite friend of the youngest person who isn\'t anyone\'s favorite friend is {favorite_friend}.')
else:
    print('There is no such person.')

Run Code Interpreter

Running the following program: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

# Query the database to find the youngest person who isn't anyone's favorite friend
query = '''
    SELECT MIN(age) AS min_age
    FROM people
    WHERE favorite_friend IS NULL;
'''
cursor.execute(query)
min_age = cursor.fetchone()[0]

query = '''
    SELECT favorite_friend
    FROM people
    WHERE age = ? AND favorite_friend IS NULL;
'''
cursor.execute(query, (min_age,))
favorite_friend = cursor.fetchone()[0]

# Close the database connection
conn.close()

# Print the result
if favorite_friend is not None:
    print(f'The favorite friend of the youngest person who isn\'t anyone\'s favorite friend is {favorite_friend}.')
else:
    print('There is no such person.')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 23, in <module> favorite_friend = cursor.fetchone()[0] ~~~~~~~~~~~~~~~~~^^^ TypeError: 'NoneType' object is not subscriptable

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Here is a possible solution to your problem: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')

# Create a cursor object
cur = conn.cursor()

# Execute a query to find the youngest person who isn't anyone's favorite friend
query = '''
SELECT MIN(age)
FROM people
WHERE NOT EXISTS (
  SELECT 1
  FROM people
  WHERE favorite_friend = people.name
)
'''
cur.execute(query)
youngest_age = cur.fetchone()[0]

# Execute a query to find the favorite friend of the youngest person
query = '''
SELECT favorite_friend
FROM people
WHERE age = ?
 AND NOT EXISTS (
   SELECT 1
   FROM people
   WHERE favorite_friend = people.name
 )
'''
cur.execute(query, (youngest_age,))
favorite_friend = cur.fetchone()[0]

# Print the result
print(f'The favorite friend of the youngest person who isn\'t anyone\'s favorite friend is {favorite_friend}.')

# Close the cursor and the connection
cur.close()
conn.close()
Note that this solution assumes that the `name` column contains unique values. If that is not the case, you may need to modify the query to take that into account. Also, please be aware that this solution may not work if there is no one in the database who meets the criteria specified in the query. In that case, the `fetchone()` method will return `None`, and you will need to handle that case appropriately in your code. I hope this helps! Let me know if you have any questions. Edit: I just noticed that you said the `favorite_friend` column is of type `TEXT`, but the query I provided assumes that it is of type `INTEGER`. If the `favorite_friend` column is indeed of type `TEXT`, you will need to modify the `NOT EXISTS` clause in the query to compare the `favorite_friend` column to the `name` column of the `people` table using the `=` operator instead of the `IN` operator. I have updated the query in my solution to reflect this. Additionally, you may want to add a check to ensure that the `favorite_friend` column is not `NULL` before attempting to print it, since a person's favorite friend may not be present in the database. You can do this by adding the following line of code before the `print()` statement: 
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if favorite_friend is not None:
    print(f'The favorite friend of the youngest person who isn\'t anyone\'s favorite friend is {favorite_friend}.')
else:
    print('The youngest person who isn\'t anyone\'s favorite friend does not have a favorite friend.')
This will print a different message if the `favorite_friend` column is `NULL`. I hope this helps! Let me know if you have any further questions.

Extract Code

I extracted the following code from that output: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')

# Create a cursor object
cur = conn.cursor()

# Execute a query to find the youngest person who isn't anyone's favorite friend
query = '''
SELECT MIN(age)
FROM people
WHERE NOT EXISTS (
  SELECT 1
  FROM people
  WHERE favorite_friend = people.name
)
'''
cur.execute(query)
youngest_age = cur.fetchone()[0]

# Execute a query to find the favorite friend of the youngest person
query = '''
SELECT favorite_friend
FROM people
WHERE age = ?
 AND NOT EXISTS (
   SELECT 1
   FROM people
   WHERE favorite_friend = people.name
 )
'''
cur.execute(query, (youngest_age,))
favorite_friend = cur.fetchone()[0]

# Print the result
if favorite_friend is not None:
    print(f'The favorite friend of the youngest person who isn\'t anyone\'s favorite friend is {favorite_friend}.')
else:
    print('The youngest person who isn\'t anyone\'s favorite friend does not have a favorite friend.')

# Close the cursor and the connection
cur.close()
conn.close()

Run Code Interpreter

Running the following program: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')

# Create a cursor object
cur = conn.cursor()

# Execute a query to find the youngest person who isn't anyone's favorite friend
query = '''
SELECT MIN(age)
FROM people
WHERE NOT EXISTS (
  SELECT 1
  FROM people
  WHERE favorite_friend = people.name
)
'''
cur.execute(query)
youngest_age = cur.fetchone()[0]

# Execute a query to find the favorite friend of the youngest person
query = '''
SELECT favorite_friend
FROM people
WHERE age = ?
 AND NOT EXISTS (
   SELECT 1
   FROM people
   WHERE favorite_friend = people.name
 )
'''
cur.execute(query, (youngest_age,))
favorite_friend = cur.fetchone()[0]

# Print the result
if favorite_friend is not None:
    print(f'The favorite friend of the youngest person who isn\'t anyone\'s favorite friend is {favorite_friend}.')
else:
    print('The youngest person who isn\'t anyone\'s favorite friend does not have a favorite friend.')

# Close the cursor and the connection
cur.close()
conn.close()
And got the output: The favorite friend of the youngest person who isn't anyone's favorite friend is Ivy.

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

First, you'll want to establish a connection to the SQLite database and execute a query to find the youngest person who isn't anyone's favorite friend. You can then fetch the result and print out their favorite friend. Here's an example Python program that does this: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = '''
SELECT TEXT, favorite_friend
FROM people
WHERE age = (
    SELECT MIN(age)
    FROM people
    WHERE age > ALL (
        SELECT age
        FROM people
        WHERE TEXT = (
            SELECT favorite_friend
            FROM people
        )
    )
)
'''

# Execute the query and fetch the result
result = cursor.execute(query).fetchone()

# Print out the result
if result:
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is {result[1]}")
else:
    print("No such person exists in the database.")

# Close the database connection
conn.close()
This query first finds the minimum age of all people who are not the favorite friend of anyone else. It then finds the person with that age and returns their favorite friend. If no such person exists in the database, the query will return `None` and the program will print an appropriate message. I hope this helps! Let me know if you have any questions. Note: This query assumes that the `age` column is unique for each person. If there are multiple people with the same age, you may want to modify the query to handle this case appropriately. For example, you could return all of their favorite friends or just return one of them randomly.

Extract Code

I extracted the following code from that output: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = '''
SELECT TEXT, favorite_friend
FROM people
WHERE age = (
    SELECT MIN(age)
    FROM people
    WHERE age > ALL (
        SELECT age
        FROM people
        WHERE TEXT = (
            SELECT favorite_friend
            FROM people
        )
    )
)
'''

# Execute the query and fetch the result
result = cursor.execute(query).fetchone()

# Print out the result
if result:
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is {result[1]}")
else:
    print("No such person exists in the database.")

# Close the database connection
conn.close()

Run Code Interpreter

Running the following program: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = '''
SELECT TEXT, favorite_friend
FROM people
WHERE age = (
    SELECT MIN(age)
    FROM people
    WHERE age > ALL (
        SELECT age
        FROM people
        WHERE TEXT = (
            SELECT favorite_friend
            FROM people
        )
    )
)
'''

# Execute the query and fetch the result
result = cursor.execute(query).fetchone()

# Print out the result
if result:
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is {result[1]}")
else:
    print("No such person exists in the database.")

# Close the database connection
conn.close()
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 27, in <module> result = cursor.execute(query).fetchone() ^^^^^^^^^^^^^^^^^^^^^ sqlite3.OperationalError: near "ALL": syntax error

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

First, let's establish a connection to the SQLite database and retrieve the required data. Here's a Python program that accomplishes this: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

# Find the youngest person who isn't anyone's favorite friend
query = '''
    SELECT MIN(age)
    FROM people
    WHERE favorite_friend IS NULL AND age NOT IN (
        SELECT age
        FROM people
        WHERE favorite_friend IS NOT NULL
    );
'''
cursor.execute(query)
youngest_age = cursor.fetchone()[0]

if youngest_age is not None:
    query = '''
        SELECT favorite_friend
        FROM people
        WHERE age = ? AND favorite_friend IS NOT NULL;
    '''
    cursor.execute(query, (youngest_age,))
    favorite_friend = cursor.fetchone()[0]

    print(f'The favorite friend of the youngest person who is not anyone\'s favorite friend is: {favorite_friend}')
else:
    print('No such person found.')

# Close the database connection
conn.close()
This program first connects to the SQLite database, `people.db`. It then executes two queries using the database cursor. The first query finds the youngest age of a person who isn't anyone's favorite friend. If such a person is found, the second query retrieves their favorite friend. Finally, the program prints the favorite friend of the youngest person who isn't anyone's favorite friend. If no such person is found, the program prints a message indicating that. Note: This solution assumes that there could be multiple youngest people who aren't anyone's favorite friend, and it returns the favorite friend of any one of them. If you want to retrieve the favorite friends of all such youngest people, you can modify the second query accordingly and use a loop to fetch all the results.

Extract Code

I extracted the following code from that output: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

# Find the youngest person who isn't anyone's favorite friend
query = '''
    SELECT MIN(age)
    FROM people
    WHERE favorite_friend IS NULL AND age NOT IN (
        SELECT age
        FROM people
        WHERE favorite_friend IS NOT NULL
    );
'''
cursor.execute(query)
youngest_age = cursor.fetchone()[0]

if youngest_age is not None:
    query = '''
        SELECT favorite_friend
        FROM people
        WHERE age = ? AND favorite_friend IS NOT NULL;
    '''
    cursor.execute(query, (youngest_age,))
    favorite_friend = cursor.fetchone()[0]

    print(f'The favorite friend of the youngest person who is not anyone\'s favorite friend is: {favorite_friend}')
else:
    print('No such person found.')

# Close the database connection
conn.close()

Run Code Interpreter

Running the following program: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

# Find the youngest person who isn't anyone's favorite friend
query = '''
    SELECT MIN(age)
    FROM people
    WHERE favorite_friend IS NULL AND age NOT IN (
        SELECT age
        FROM people
        WHERE favorite_friend IS NOT NULL
    );
'''
cursor.execute(query)
youngest_age = cursor.fetchone()[0]

if youngest_age is not None:
    query = '''
        SELECT favorite_friend
        FROM people
        WHERE age = ? AND favorite_friend IS NOT NULL;
    '''
    cursor.execute(query, (youngest_age,))
    favorite_friend = cursor.fetchone()[0]

    print(f'The favorite friend of the youngest person who is not anyone\'s favorite friend is: {favorite_friend}')
else:
    print('No such person found.')

# Close the database connection
conn.close()
And got the output: No such person found.

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

To achieve this, you'll first need to establish a connection to the SQLite database, query it to find the youngest person who isn't anyone's favorite friend, and then print out their favorite friend. Here's a Python program that accomplishes this: 

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import sqlite3

def get_youngest_non_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect("people.db")
    cursor = conn.cursor()

    # Query to find the youngest person who isn't anyone's favorite friend
    query = '''
        SELECT p1.favorite_friend
        FROM people p1
        LEFT JOIN people p2 ON p1.favorite_friend = p2.name
        WHERE p2.name IS NULL AND p1.age = (
            SELECT MIN(p3.age)
            FROM people p3
            LEFT JOIN people p4 ON p3.name = p4.favorite_friend
            WHERE p4.name IS NULL
        );
    '''
    
    # Execute the query and fetch the result
    result = cursor.execute(query).fetchone()

    # Close the database connection
    conn.close()

    # If a result was found, return it; otherwise, return None
    return result[0] if result else None

# Call the function and print the result
print(get_youngest_non_favorite_friend())
This program defines a function `get_youngest_non_favorite_friend()` that connects to the database, executes an SQL query to find the required information, and returns the favorite friend of the youngest person who isn't anyone's favorite friend. The result is then printed. Make sure to replace the table and column names if they are different in your database.

Extract Code

I extracted the following code from that output: 

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import sqlite3

def get_youngest_non_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect("people.db")
    cursor = conn.cursor()

    # Query to find the youngest person who isn't anyone's favorite friend
    query = '''
        SELECT p1.favorite_friend
        FROM people p1
        LEFT JOIN people p2 ON p1.favorite_friend = p2.name
        WHERE p2.name IS NULL AND p1.age = (
            SELECT MIN(p3.age)
            FROM people p3
            LEFT JOIN people p4 ON p3.name = p4.favorite_friend
            WHERE p4.name IS NULL
        );
    '''
    
    # Execute the query and fetch the result
    result = cursor.execute(query).fetchone()

    # Close the database connection
    conn.close()

    # If a result was found, return it; otherwise, return None
    return result[0] if result else None

# Call the function and print the result
print(get_youngest_non_favorite_friend())

Run Code Interpreter

Running the following program: 

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import sqlite3

def get_youngest_non_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect("people.db")
    cursor = conn.cursor()

    # Query to find the youngest person who isn't anyone's favorite friend
    query = '''
        SELECT p1.favorite_friend
        FROM people p1
        LEFT JOIN people p2 ON p1.favorite_friend = p2.name
        WHERE p2.name IS NULL AND p1.age = (
            SELECT MIN(p3.age)
            FROM people p3
            LEFT JOIN people p4 ON p3.name = p4.favorite_friend
            WHERE p4.name IS NULL
        );
    '''
    
    # Execute the query and fetch the result
    result = cursor.execute(query).fetchone()

    # Close the database connection
    conn.close()

    # If a result was found, return it; otherwise, return None
    return result[0] if result else None

# Call the function and print the result
print(get_youngest_non_favorite_friend())
And got the output: None

Substring Evaluation

Testing if the previous output contains the string Grace: False