Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Sure, I can help you write a Python program to query your SQLite database. Here's a basic example: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # First, we find the ID of the youngest person who isn't anyone's favorite friend
    cursor.execute("""
        SELECT MIN(age), id
        FROM people
        WHERE id NOT IN (SELECT favorite_friend FROM people)
    """)
    youngest_id = cursor.fetchone()[1]

    # Then, we find the favorite friend of that person
    cursor.execute("""
        SELECT favorite_friend
        FROM people
        WHERE id = ?
    """, (youngest_id,))
    favorite_friend = cursor.fetchone()[0]

    conn.close()

    return favorite_friend

print(get_youngest_non_favorite())
This script first connects to the `people.db` database, then it executes two SQL queries. The first query finds the ID of the youngest person who isn't anyone's favorite friend. The second query finds the favorite friend of that person. The result is then printed out. Please note that this script assumes that the `id` column exists and is unique for each person. If that's not the case, you'll need to adjust the script accordingly. Also, it assumes that the `age` column contains integer values. If the ages are stored as strings, you'll need to convert them to integers in the query. Lastly, this script doesn't handle exceptions or edge cases, such as when the database doesn't exist, when the table is empty, or when a person doesn't have a favorite friend. You might want to add some error handling to make the script more robust.

Extract Code

I extracted the following code from that output: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # First, we find the ID of the youngest person who isn't anyone's favorite friend
    cursor.execute("""
        SELECT MIN(age), id
        FROM people
        WHERE id NOT IN (SELECT favorite_friend FROM people)
    """)
    youngest_id = cursor.fetchone()[1]

    # Then, we find the favorite friend of that person
    cursor.execute("""
        SELECT favorite_friend
        FROM people
        WHERE id = ?
    """, (youngest_id,))
    favorite_friend = cursor.fetchone()[0]

    conn.close()

    return favorite_friend

print(get_youngest_non_favorite())

Run Code Interpreter

Running the following program: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # First, we find the ID of the youngest person who isn't anyone's favorite friend
    cursor.execute("""
        SELECT MIN(age), id
        FROM people
        WHERE id NOT IN (SELECT favorite_friend FROM people)
    """)
    youngest_id = cursor.fetchone()[1]

    # Then, we find the favorite friend of that person
    cursor.execute("""
        SELECT favorite_friend
        FROM people
        WHERE id = ?
    """, (youngest_id,))
    favorite_friend = cursor.fetchone()[0]

    conn.close()

    return favorite_friend

print(get_youngest_non_favorite())
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 28, in <module> print(get_youngest_non_favorite()) ^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 9, in get_youngest_non_favorite cursor.execute(""" sqlite3.OperationalError: no such column: id

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

To achieve this, you can use the sqlite3 module in Python. First, you need to import the module and establish a connection with the database. Then, execute SQL queries to find the favorite friend of the youngest person who isn't anyone's favorite friend. Here's a Python script to do this: 

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import sqlite3

def get_youngest_non_fav_friend(db_name, table_name):
    conn = sqlite3.connect(db_name)
    cursor = conn.cursor()

    # Find people who aren't anyone's favorite friend
    cursor.execute(f"SELECT name FROM {table_name} WHERE name NOT IN (SELECT favorite_friend FROM {table_name})")
    non_fav_friends = [row[0] for row in cursor.fetchall()]

    # Find the youngest person among them
    cursor.execute(f"SELECT name, age FROM {table_name} WHERE name IN ({', '.join(['?'] * len(non_fav_friends))}) ORDER BY age ASC LIMIT 1", non_fav_friends)
    youngest_person = cursor.fetchone()

    # Find the favorite friend of the youngest person
    cursor.execute(f"SELECT favorite_friend FROM {table_name} WHERE name = ?", (youngest_person[0],))
    favorite_friend = cursor.fetchone()[0]

    conn.close()

    return favorite_friend

db_name = "people.db"
table_name = "people"
print(get_youngest_non_fav_friend(db_name, table_name))
This script first fetches people who aren't anyone's favorite friend, then finds the youngest person among them and finally retrieves the favorite friend of that youngest person.

Extract Code

I extracted the following code from that output: 

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import sqlite3

def get_youngest_non_fav_friend(db_name, table_name):
    conn = sqlite3.connect(db_name)
    cursor = conn.cursor()

    # Find people who aren't anyone's favorite friend
    cursor.execute(f"SELECT name FROM {table_name} WHERE name NOT IN (SELECT favorite_friend FROM {table_name})")
    non_fav_friends = [row[0] for row in cursor.fetchall()]

    # Find the youngest person among them
    cursor.execute(f"SELECT name, age FROM {table_name} WHERE name IN ({', '.join(['?'] * len(non_fav_friends))}) ORDER BY age ASC LIMIT 1", non_fav_friends)
    youngest_person = cursor.fetchone()

    # Find the favorite friend of the youngest person
    cursor.execute(f"SELECT favorite_friend FROM {table_name} WHERE name = ?", (youngest_person[0],))
    favorite_friend = cursor.fetchone()[0]

    conn.close()

    return favorite_friend

db_name = "people.db"
table_name = "people"
print(get_youngest_non_fav_friend(db_name, table_name))

Run Code Interpreter

Running the following program: 

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import sqlite3

def get_youngest_non_fav_friend(db_name, table_name):
    conn = sqlite3.connect(db_name)
    cursor = conn.cursor()

    # Find people who aren't anyone's favorite friend
    cursor.execute(f"SELECT name FROM {table_name} WHERE name NOT IN (SELECT favorite_friend FROM {table_name})")
    non_fav_friends = [row[0] for row in cursor.fetchall()]

    # Find the youngest person among them
    cursor.execute(f"SELECT name, age FROM {table_name} WHERE name IN ({', '.join(['?'] * len(non_fav_friends))}) ORDER BY age ASC LIMIT 1", non_fav_friends)
    youngest_person = cursor.fetchone()

    # Find the favorite friend of the youngest person
    cursor.execute(f"SELECT favorite_friend FROM {table_name} WHERE name = ?", (youngest_person[0],))
    favorite_friend = cursor.fetchone()[0]

    conn.close()

    return favorite_friend

db_name = "people.db"
table_name = "people"
print(get_youngest_non_fav_friend(db_name, table_name))
And got the output: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Sure, I can help you write a Python program to query your SQLite database. Here's a basic example: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # First, we find the ID of the youngest person who isn't anyone's favorite friend
    cursor.execute("""
        SELECT MIN(age), id
        FROM people
        WHERE id NOT IN (
            SELECT favorite_friend
            FROM people
        )
    """)

    youngest_age, youngest_id = cursor.fetchone()

    # Then, we find the favorite friend of that person
    cursor.execute("""
        SELECT favorite_friend
        FROM people
        WHERE id = ?
    """, (youngest_id,))

    favorite_friend = cursor.fetchone()[0]

    conn.close()

    return favorite_friend

print(get_youngest_non_favorite())
This program connects to your `people.db` database, and then executes two SQL queries. The first query finds the ID of the youngest person who isn't anyone's favorite friend. The second query finds the favorite friend of that person. The result is then printed out. Please note that this code assumes that the `id` column exists and is unique for each person. If that's not the case, you'll need to adjust the SQL queries accordingly. Also, this code doesn't handle the case where a person doesn't have a favorite friend, or where there's no one in the database who isn't someone's favorite friend. You might want to add some error checking to handle these cases.

Extract Code

I extracted the following code from that output: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # First, we find the ID of the youngest person who isn't anyone's favorite friend
    cursor.execute("""
        SELECT MIN(age), id
        FROM people
        WHERE id NOT IN (
            SELECT favorite_friend
            FROM people
        )
    """)

    youngest_age, youngest_id = cursor.fetchone()

    # Then, we find the favorite friend of that person
    cursor.execute("""
        SELECT favorite_friend
        FROM people
        WHERE id = ?
    """, (youngest_id,))

    favorite_friend = cursor.fetchone()[0]

    conn.close()

    return favorite_friend

print(get_youngest_non_favorite())

Run Code Interpreter

Running the following program: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # First, we find the ID of the youngest person who isn't anyone's favorite friend
    cursor.execute("""
        SELECT MIN(age), id
        FROM people
        WHERE id NOT IN (
            SELECT favorite_friend
            FROM people
        )
    """)

    youngest_age, youngest_id = cursor.fetchone()

    # Then, we find the favorite friend of that person
    cursor.execute("""
        SELECT favorite_friend
        FROM people
        WHERE id = ?
    """, (youngest_id,))

    favorite_friend = cursor.fetchone()[0]

    conn.close()

    return favorite_friend

print(get_youngest_non_favorite())
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 33, in <module> print(get_youngest_non_favorite()) ^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 9, in get_youngest_non_favorite cursor.execute(""" sqlite3.OperationalError: no such column: id

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

To achieve this, you'll need to write a Python script using the sqlite3 module. Here's a script that should do what you're looking for: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Find the people who are not anyone's favorite friend
    cursor.execute("""
        SELECT name
        FROM people
        WHERE name NOT IN (SELECT favorite_friend FROM people)
    """)
    non_favorites = [row[0] for row in cursor.fetchall()]

    # Find the youngest person among those who aren't anyone's favorite friend
    if non_favorites:
        cursor.execute("""
            SELECT name, age
            FROM people
            WHERE name IN (?)
            ORDER BY age ASC
            LIMIT 1
        """, (tuple(non_favorites),))

        youngest = cursor.fetchone()
        if youngest:
            youngest_name = youngest[0]

            # Find the favorite friend of the youngest person
            cursor.execute("""
                SELECT favorite_friend
                FROM people
                WHERE name = ?
            """, (youngest_name,))

            favorite_friend = cursor.fetchone()[0]
            return favorite_friend

    conn.close()
    return None

favorite_friend = get_youngest_non_favorite()
if favorite_friend:
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No results found.")
This script first finds the people who aren't anyone's favorite friend, then identifies the youngest among them, and finally prints out their favorite friend. Make sure the database file (people.db) is in the same directory as the script or provide the correct file path when opening the connection.

Extract Code

I extracted the following code from that output: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Find the people who are not anyone's favorite friend
    cursor.execute("""
        SELECT name
        FROM people
        WHERE name NOT IN (SELECT favorite_friend FROM people)
    """)
    non_favorites = [row[0] for row in cursor.fetchall()]

    # Find the youngest person among those who aren't anyone's favorite friend
    if non_favorites:
        cursor.execute("""
            SELECT name, age
            FROM people
            WHERE name IN (?)
            ORDER BY age ASC
            LIMIT 1
        """, (tuple(non_favorites),))

        youngest = cursor.fetchone()
        if youngest:
            youngest_name = youngest[0]

            # Find the favorite friend of the youngest person
            cursor.execute("""
                SELECT favorite_friend
                FROM people
                WHERE name = ?
            """, (youngest_name,))

            favorite_friend = cursor.fetchone()[0]
            return favorite_friend

    conn.close()
    return None

favorite_friend = get_youngest_non_favorite()
if favorite_friend:
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No results found.")

Run Code Interpreter

Running the following program: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Find the people who are not anyone's favorite friend
    cursor.execute("""
        SELECT name
        FROM people
        WHERE name NOT IN (SELECT favorite_friend FROM people)
    """)
    non_favorites = [row[0] for row in cursor.fetchall()]

    # Find the youngest person among those who aren't anyone's favorite friend
    if non_favorites:
        cursor.execute("""
            SELECT name, age
            FROM people
            WHERE name IN (?)
            ORDER BY age ASC
            LIMIT 1
        """, (tuple(non_favorites),))

        youngest = cursor.fetchone()
        if youngest:
            youngest_name = youngest[0]

            # Find the favorite friend of the youngest person
            cursor.execute("""
                SELECT favorite_friend
                FROM people
                WHERE name = ?
            """, (youngest_name,))

            favorite_friend = cursor.fetchone()[0]
            return favorite_friend

    conn.close()
    return None

favorite_friend = get_youngest_non_favorite()
if favorite_friend:
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No results found.")
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 43, in <module> favorite_friend = get_youngest_non_favorite() ^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 18, in get_youngest_non_favorite cursor.execute(""" sqlite3.ProgrammingError: Error binding parameter 1: type 'tuple' is not supported

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

To achieve this, you'll need to perform the following steps: 1. Connect to the SQLite database. 2. Find the youngest person who isn't anyone's favorite friend. 3. Retrieve the favorite friend of that person. Here's a Python program that does this: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect("people.db")
    cursor = conn.cursor()

    # Find the youngest person who isn't anyone's favorite friend
    query = """
        SELECT MIN(age), name
        FROM people
        WHERE name NOT IN (
            SELECT favorite_friend
            FROM people
        )
    """
    cursor.execute(query)
    result = cursor.fetchone()

    youngest_age, youngest_name = result if result else (None, None)
    conn.close()

    return youngest_age, youngest_name

def get_favorite_friend(name):
    conn = sqlite3.connect("people.db")
    cursor = conn.cursor()

    # Retrieve the favorite friend of the given person
    query = "SELECT favorite_friend FROM people WHERE name = ?"
    cursor.execute(query, (name,))
    result = cursor.fetchone()

    favorite_friend = result[0] if result else None
    conn.close()

    return favorite_friend

def main():
    youngest_age, youngest_name = get_youngest_non_favorite()
    if youngest_name:
        favorite_friend = get_favorite_friend(youngest_name)
        if favorite_friend:
            print(f"The favorite friend of the youngest person ({youngest_name}) who isn't anyone's favorite friend is {favorite_friend}.")
        else:
            print(f"The youngest person ({youngest_name}) who isn't anyone's favorite friend doesn't have a favorite friend.")
    else:
        print("There's no person who isn't anyone's favorite friend.")

if __name__ == "__main__":
    main()
This program defines three functions: 1. `get_youngest_non_favorite()`: This function connects to the database and finds the youngest person who isn't anyone's favorite friend. 2. `get_favorite_friend(name)`: This function connects to the database and retrieves the favorite friend of the given person. 3. `main()`: This function calls the previous functions and prints the result.

Extract Code

I extracted the following code from that output: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect("people.db")
    cursor = conn.cursor()

    # Find the youngest person who isn't anyone's favorite friend
    query = """
        SELECT MIN(age), name
        FROM people
        WHERE name NOT IN (
            SELECT favorite_friend
            FROM people
        )
    """
    cursor.execute(query)
    result = cursor.fetchone()

    youngest_age, youngest_name = result if result else (None, None)
    conn.close()

    return youngest_age, youngest_name

def get_favorite_friend(name):
    conn = sqlite3.connect("people.db")
    cursor = conn.cursor()

    # Retrieve the favorite friend of the given person
    query = "SELECT favorite_friend FROM people WHERE name = ?"
    cursor.execute(query, (name,))
    result = cursor.fetchone()

    favorite_friend = result[0] if result else None
    conn.close()

    return favorite_friend

def main():
    youngest_age, youngest_name = get_youngest_non_favorite()
    if youngest_name:
        favorite_friend = get_favorite_friend(youngest_name)
        if favorite_friend:
            print(f"The favorite friend of the youngest person ({youngest_name}) who isn't anyone's favorite friend is {favorite_friend}.")
        else:
            print(f"The youngest person ({youngest_name}) who isn't anyone's favorite friend doesn't have a favorite friend.")
    else:
        print("There's no person who isn't anyone's favorite friend.")

if __name__ == "__main__":
    main()

Run Code Interpreter

Running the following program: 

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import sqlite3

def get_youngest_non_favorite():
    conn = sqlite3.connect("people.db")
    cursor = conn.cursor()

    # Find the youngest person who isn't anyone's favorite friend
    query = """
        SELECT MIN(age), name
        FROM people
        WHERE name NOT IN (
            SELECT favorite_friend
            FROM people
        )
    """
    cursor.execute(query)
    result = cursor.fetchone()

    youngest_age, youngest_name = result if result else (None, None)
    conn.close()

    return youngest_age, youngest_name

def get_favorite_friend(name):
    conn = sqlite3.connect("people.db")
    cursor = conn.cursor()

    # Retrieve the favorite friend of the given person
    query = "SELECT favorite_friend FROM people WHERE name = ?"
    cursor.execute(query, (name,))
    result = cursor.fetchone()

    favorite_friend = result[0] if result else None
    conn.close()

    return favorite_friend

def main():
    youngest_age, youngest_name = get_youngest_non_favorite()
    if youngest_name:
        favorite_friend = get_favorite_friend(youngest_name)
        if favorite_friend:
            print(f"The favorite friend of the youngest person ({youngest_name}) who isn't anyone's favorite friend is {favorite_friend}.")
        else:
            print(f"The youngest person ({youngest_name}) who isn't anyone's favorite friend doesn't have a favorite friend.")
    else:
        print("There's no person who isn't anyone's favorite friend.")

if __name__ == "__main__":
    main()
And got the output: The favorite friend of the youngest person (Judy) who isn't anyone's favorite friend is Grace.

Substring Evaluation

Testing if the previous output contains the string Grace: True