Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

To achieve this task, you'll need to follow these steps in your Python program: 1. Connect to the SQLite database. 2. Fetch the youngest person in the database. 3. Identify the favorite friends of all individuals in the database. 4. Check if the youngest person's favorite friend is not in the list of favorite friends from other individuals. 5. Print the result. Here's a Python program that implements these steps: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
import sqlite3

def get_youngest_non_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Step 1: Get the youngest person's data
    cursor.execute('SELECT favorite_friend FROM people ORDER BY age ASC LIMIT 1')
    youngest_person = cursor.fetchone()

    if youngest_person is None:
        print("No data found in the database.")
        return

    youngest_favorite_friend = youngest_person[0]

    # Step 2: Get the list of favorite friends from all people
    cursor.execute('SELECT DISTINCT favorite_friend FROM people')
    favorite_friends = {row[0] for row in cursor.fetchall()}

    # Step 3: Check if the youngest person's favorite friend is not anyone's favorite friend
    if youngest_favorite_friend not in favorite_friends:
        print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {youngest_favorite_friend}")
    else:
        print(f"The favorite friend of the youngest person is {youngest_favorite_friend}, but they are someone's favorite friend.")

    # Close the database connection
    conn.close()

# Run the function
get_youngest_non_favorite_friend()
### Explanation: 1. **Database Connection**: The program connects to the SQLite database named `people.db`. 2. **Fetch Youngest Person**: It retrieves the `favorite_friend` of the youngest person by ordering the entries by `age` in ascending order and selecting the first entry. 3. **Favorite Friends Extraction**: It collects all distinct favorite friends from the database into a set for efficient lookup. 4. **Check Condition**: It checks if the favorite friend of the youngest person is not in the list of favorite friends of other individuals. 5. **Output**: Finally, it prints the result based on the checks. ### Note: - Make sure that the table `people` in your database has the appropriate columns (`TEXT`, `favorite_friend`, `age`, `profession`) as per your specifications. - This script needs to be run in an environment where the SQLite database `people.db` is accessible.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
import sqlite3

def get_youngest_non_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Step 1: Get the youngest person's data
    cursor.execute('SELECT favorite_friend FROM people ORDER BY age ASC LIMIT 1')
    youngest_person = cursor.fetchone()

    if youngest_person is None:
        print("No data found in the database.")
        return

    youngest_favorite_friend = youngest_person[0]

    # Step 2: Get the list of favorite friends from all people
    cursor.execute('SELECT DISTINCT favorite_friend FROM people')
    favorite_friends = {row[0] for row in cursor.fetchall()}

    # Step 3: Check if the youngest person's favorite friend is not anyone's favorite friend
    if youngest_favorite_friend not in favorite_friends:
        print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {youngest_favorite_friend}")
    else:
        print(f"The favorite friend of the youngest person is {youngest_favorite_friend}, but they are someone's favorite friend.")

    # Close the database connection
    conn.close()

# Run the function
get_youngest_non_favorite_friend()

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
import sqlite3

def get_youngest_non_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Step 1: Get the youngest person's data
    cursor.execute('SELECT favorite_friend FROM people ORDER BY age ASC LIMIT 1')
    youngest_person = cursor.fetchone()

    if youngest_person is None:
        print("No data found in the database.")
        return

    youngest_favorite_friend = youngest_person[0]

    # Step 2: Get the list of favorite friends from all people
    cursor.execute('SELECT DISTINCT favorite_friend FROM people')
    favorite_friends = {row[0] for row in cursor.fetchall()}

    # Step 3: Check if the youngest person's favorite friend is not anyone's favorite friend
    if youngest_favorite_friend not in favorite_friends:
        print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {youngest_favorite_friend}")
    else:
        print(f"The favorite friend of the youngest person is {youngest_favorite_friend}, but they are someone's favorite friend.")

    # Close the database connection
    conn.close()

# Run the function
get_youngest_non_favorite_friend()
And got the output: The favorite friend of the youngest person is Ivy, but they are someone's favorite friend.

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

To achieve the task of finding the favorite friend of the youngest person who isn’t anyone's favorite friend using SQLite and Python, you can follow the steps outlined below. The program will: 1. Connect to the SQLite database. 2. Query the table for the youngest person. 3. Check their favorite friend. 4. Ensure that this favorite friend isn't listed as anyone's favorite friend. 5. Print the result if found. Here is a Python program that implements this logic: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
import sqlite3

def get_youngest_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Step 1: Find the youngest person's age and their favorite friend
    cursor.execute('''
        SELECT favorite_friend
        FROM people
        WHERE age = (SELECT MIN(age) FROM people)
    ''')
    youngest_favorite_friend = cursor.fetchone()

    if youngest_favorite_friend is None:
        print("No entries in the database.")
        conn.close()
        return

    favorite_friend = youngest_favorite_friend[0]

    # Step 2: Check if the favorite friend is anyone's favorite friend
    cursor.execute('''
        SELECT COUNT(*)
        FROM people
        WHERE favorite_friend = ?
    ''', (favorite_friend,))
    count = cursor.fetchone()[0]

    # Step 3: Print the favorite friend if they are not anyone's favorite friend
    if count == 0:
        print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
    else:
        print(f"{favorite_friend} is someone's favorite friend.")

    # Close the database connection
    conn.close()

# Run the function
get_youngest_favorite_friend()
### Explanation: 1. **Database Connection**: The program connects to the `people.db` SQLite database using `sqlite3`. 2. **Query for the Youngest Person**: It retrieves the favorite friend of the youngest person using a subquery to find the minimum age. 3. **Check for Favorite Friendship**: It checks whether the retrieved favorite friend is anyone's favorite friend by counting how many times that name appears in the `favorite_friend` column. 4. **Output**: It prints the favorite friend if they are not anyone's favorite friend, or indicates that they are. ### Note: - Make sure to have the SQLite database and the schema properly set up before running this program. - Error handling can be added to enhance the robustness of the program.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
import sqlite3

def get_youngest_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Step 1: Find the youngest person's age and their favorite friend
    cursor.execute('''
        SELECT favorite_friend
        FROM people
        WHERE age = (SELECT MIN(age) FROM people)
    ''')
    youngest_favorite_friend = cursor.fetchone()

    if youngest_favorite_friend is None:
        print("No entries in the database.")
        conn.close()
        return

    favorite_friend = youngest_favorite_friend[0]

    # Step 2: Check if the favorite friend is anyone's favorite friend
    cursor.execute('''
        SELECT COUNT(*)
        FROM people
        WHERE favorite_friend = ?
    ''', (favorite_friend,))
    count = cursor.fetchone()[0]

    # Step 3: Print the favorite friend if they are not anyone's favorite friend
    if count == 0:
        print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
    else:
        print(f"{favorite_friend} is someone's favorite friend.")

    # Close the database connection
    conn.close()

# Run the function
get_youngest_favorite_friend()

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
import sqlite3

def get_youngest_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Step 1: Find the youngest person's age and their favorite friend
    cursor.execute('''
        SELECT favorite_friend
        FROM people
        WHERE age = (SELECT MIN(age) FROM people)
    ''')
    youngest_favorite_friend = cursor.fetchone()

    if youngest_favorite_friend is None:
        print("No entries in the database.")
        conn.close()
        return

    favorite_friend = youngest_favorite_friend[0]

    # Step 2: Check if the favorite friend is anyone's favorite friend
    cursor.execute('''
        SELECT COUNT(*)
        FROM people
        WHERE favorite_friend = ?
    ''', (favorite_friend,))
    count = cursor.fetchone()[0]

    # Step 3: Print the favorite friend if they are not anyone's favorite friend
    if count == 0:
        print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
    else:
        print(f"{favorite_friend} is someone's favorite friend.")

    # Close the database connection
    conn.close()

# Run the function
get_youngest_favorite_friend()
And got the output: Ivy is someone's favorite friend.

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Certainly! Below is a Python program that connects to a SQLite database named `people.db`, queries the `people` table to find the youngest person who isn't anyone's favorite friend, and prints out their favorite friend. To run this code, ensure you have the SQLite database set up with the appropriate schema and data. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
import sqlite3

def get_youngest_non_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Query to find the favorite friends of all people
    cursor.execute("SELECT DISTINCT favorite_friend FROM people")
    favorite_friends = set(row[0] for row in cursor.fetchall())

    # Query to find the youngest person who isn't anyone's favorite friend
    cursor.execute("""
        SELECT favorite_friend 
        FROM people 
        WHERE age = (SELECT MIN(age) FROM people WHERE favorite_friend NOT IN (?, ?))
    """, (*favorite_friends,))

    # Fetch the result
    result = cursor.fetchone()
    
    # Close the connection
    conn.close()

    # Print the favorite friend of the youngest non-favorite friend
    if result:
        print("The favorite friend of the youngest person who isn't anyone's favorite friend is:", result[0])
    else:
        print("No suitable person found.")

# Call the function
get_youngest_non_favorite_friend()
### Explanation of the Code: 1. **Database Connection**: The program connects to the SQLite database named `people.db`. 2. **Fetch Favorite Friends**: It retrieves all unique favorite friends from the `people` table and stores them in a set. 3. **Find Youngest Non-Favorite Friend**: It constructs and executes a SQL query to find the youngest person whose favorite friend is not in the set of favorite friends. 4. **Fetch and Print Result**: It fetches the result and prints the favorite friend of that youngest person. ### Note: - Make sure the `people.db` database and the `people` table exist, and that the table has the columns specified (`TEXT`, `favorite_friend`, `age`, `profession`). - If the database schema or data is different, you might need to adjust the queries accordingly.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
import sqlite3

def get_youngest_non_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Query to find the favorite friends of all people
    cursor.execute("SELECT DISTINCT favorite_friend FROM people")
    favorite_friends = set(row[0] for row in cursor.fetchall())

    # Query to find the youngest person who isn't anyone's favorite friend
    cursor.execute("""
        SELECT favorite_friend 
        FROM people 
        WHERE age = (SELECT MIN(age) FROM people WHERE favorite_friend NOT IN (?, ?))
    """, (*favorite_friends,))

    # Fetch the result
    result = cursor.fetchone()
    
    # Close the connection
    conn.close()

    # Print the favorite friend of the youngest non-favorite friend
    if result:
        print("The favorite friend of the youngest person who isn't anyone's favorite friend is:", result[0])
    else:
        print("No suitable person found.")

# Call the function
get_youngest_non_favorite_friend()

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
import sqlite3

def get_youngest_non_favorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Query to find the favorite friends of all people
    cursor.execute("SELECT DISTINCT favorite_friend FROM people")
    favorite_friends = set(row[0] for row in cursor.fetchall())

    # Query to find the youngest person who isn't anyone's favorite friend
    cursor.execute("""
        SELECT favorite_friend 
        FROM people 
        WHERE age = (SELECT MIN(age) FROM people WHERE favorite_friend NOT IN (?, ?))
    """, (*favorite_friends,))

    # Fetch the result
    result = cursor.fetchone()
    
    # Close the connection
    conn.close()

    # Print the favorite friend of the youngest non-favorite friend
    if result:
        print("The favorite friend of the youngest person who isn't anyone's favorite friend is:", result[0])
    else:
        print("No suitable person found.")

# Call the function
get_youngest_non_favorite_friend()
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 33, in <module> get_youngest_non_favorite_friend() File "/usr/src/app/main.py", line 14, in get_youngest_non_favorite_friend cursor.execute(""" sqlite3.ProgrammingError: Incorrect number of bindings supplied. The current statement uses 2, and there are 8 supplied.

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

To achieve your goal, we need to write a Python program that interacts with the SQLite database. We'll perform the following steps: 1. Connect to the SQLite database. 2. Query the database to find the youngest person and their favorite friend. 3. Identify friends that are favorites for others. 4. Filter the results to find the youngest person's favorite friend who isn't anyone else's favorite friend. 5. Print the result. Here's a sample Python program that accomplishes this: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
import sqlite3

def main():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    try:
        # Step 1: Get the youngest person
        cursor.execute("SELECT favorite_friend, age FROM people ORDER BY age ASC LIMIT 1")
        youngest_person = cursor.fetchone()
        
        if youngest_person is None:
            print("No data in the database.")
            return
        
        favorite_friend, age = youngest_person

        # Step 2: Get all favorite friends
        cursor.execute("SELECT DISTINCT favorite_friend FROM people")
        favorite_friends = {row[0] for row in cursor.fetchall()}

        # Step 3: Check if the favorite friend of the youngest person is not in the favorite friends list
        if favorite_friend not in favorite_friends:
            print(f"The favorite friend of the youngest person ({age} years old) who isn't anyone's favorite friend is: {favorite_friend}")
        else:
            print(f"The favorite friend of the youngest person ({age} years old) is also someone's favorite friend: {favorite_friend}")

    except sqlite3.Error as e:
        print(f"An error occurred: {e}")
    
    finally:
        # Close the database connection
        conn.close()

if __name__ == "__main__":
    main()
### Explanation of the Code: 1. **Connect to the Database**: We establish a connection to `people.db`. 2. **Query for the Youngest Person**: We retrieve the favorite friend and age of the youngest person by sorting the records by age and limiting the result to one entry. 3. **Gather Favorite Friends**: We query the database to get a distinct list of all favorite friends. 4. **Check for Uniqueness**: We check if the favorite friend of the youngest person is not in the set of favorite friends from other records. 5. **Print the Result**: Based on the checks, we print either the favorite friend or a message indicating they are also someone's favorite friend. 6. **Error Handling**: The program includes basic error handling for database operations. Before running the code, make sure you have the `sqlite3` module available (it is included by default in Python's standard library) and that your database `people.db` and table `people` have the expected schema and data.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
import sqlite3

def main():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    try:
        # Step 1: Get the youngest person
        cursor.execute("SELECT favorite_friend, age FROM people ORDER BY age ASC LIMIT 1")
        youngest_person = cursor.fetchone()
        
        if youngest_person is None:
            print("No data in the database.")
            return
        
        favorite_friend, age = youngest_person

        # Step 2: Get all favorite friends
        cursor.execute("SELECT DISTINCT favorite_friend FROM people")
        favorite_friends = {row[0] for row in cursor.fetchall()}

        # Step 3: Check if the favorite friend of the youngest person is not in the favorite friends list
        if favorite_friend not in favorite_friends:
            print(f"The favorite friend of the youngest person ({age} years old) who isn't anyone's favorite friend is: {favorite_friend}")
        else:
            print(f"The favorite friend of the youngest person ({age} years old) is also someone's favorite friend: {favorite_friend}")

    except sqlite3.Error as e:
        print(f"An error occurred: {e}")
    
    finally:
        # Close the database connection
        conn.close()

if __name__ == "__main__":
    main()

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
import sqlite3

def main():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    try:
        # Step 1: Get the youngest person
        cursor.execute("SELECT favorite_friend, age FROM people ORDER BY age ASC LIMIT 1")
        youngest_person = cursor.fetchone()
        
        if youngest_person is None:
            print("No data in the database.")
            return
        
        favorite_friend, age = youngest_person

        # Step 2: Get all favorite friends
        cursor.execute("SELECT DISTINCT favorite_friend FROM people")
        favorite_friends = {row[0] for row in cursor.fetchall()}

        # Step 3: Check if the favorite friend of the youngest person is not in the favorite friends list
        if favorite_friend not in favorite_friends:
            print(f"The favorite friend of the youngest person ({age} years old) who isn't anyone's favorite friend is: {favorite_friend}")
        else:
            print(f"The favorite friend of the youngest person ({age} years old) is also someone's favorite friend: {favorite_friend}")

    except sqlite3.Error as e:
        print(f"An error occurred: {e}")
    
    finally:
        # Close the database connection
        conn.close()

if __name__ == "__main__":
    main()
And got the output: The favorite friend of the youngest person (25 years old) is also someone's favorite friend: Ivy

Substring Evaluation

Testing if the previous output contains the string Grace: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

To achieve your goal, you'll need to write a Python program that connects to your SQLite database, queries the necessary information, and processes the data to find the favorite friend of the youngest person who isn't anyone's favorite friend. Below is an example of how you can implement this: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
import sqlite3

def get_favorite_friend_of_youngest_non_favorite():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Query to find the youngest person and their favorite friend
    cursor.execute('''
        SELECT TEXT, favorite_friend
        FROM people
        WHERE age = (SELECT MIN(age) FROM people)
    ''')
    
    # Fetch the results
    youngest_person = cursor.fetchone()
    
    if youngest_person:
        youngest_text, favorite_friend_of_youngest = youngest_person
        
        # Query to find all favorite friends
        cursor.execute('SELECT DISTINCT favorite_friend FROM people WHERE favorite_friend IS NOT NULL')
        favorite_friends = set(row[0] for row in cursor.fetchall())
        
        # Check if the favorite friend of the youngest is not in the list of favorite friends
        if favorite_friend_of_youngest not in favorite_friends:
            print(f"The favorite friend of the youngest person ({youngest_text}) who isn't anyone's favorite friend is: {favorite_friend_of_youngest}")
        else:
            print(f"The favorite friend of the youngest person ({youngest_text}) is also someone's favorite friend.")
    else:
        print("No data found in the database.")

    # Close the connection
    conn.close()

# Run the function
get_favorite_friend_of_youngest_non_favorite()
### Explanation of the Code: 1. **Database Connection**: The program connects to the SQLite database `people.db`. 2. **Query for Youngest Person**: It queries the database to find the youngest person's name (`TEXT`) and their favorite friend. 3. **Query for Favorite Friends**: It retrieves a distinct list of all favorite friends from the database. 4. **Check Conditions**: It checks if the favorite friend of the youngest person is not in the list of all favorite friends. If it isn’t, it prints out the result. 5. **Close Connection**: Finally, it closes the connection to the database. ### Note: Make sure that the database file `people.db` and the table `people` exist and are structured as you described. Also, ensure that the program is executed in an environment where the SQLite library is available.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
import sqlite3

def get_favorite_friend_of_youngest_non_favorite():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Query to find the youngest person and their favorite friend
    cursor.execute('''
        SELECT TEXT, favorite_friend
        FROM people
        WHERE age = (SELECT MIN(age) FROM people)
    ''')
    
    # Fetch the results
    youngest_person = cursor.fetchone()
    
    if youngest_person:
        youngest_text, favorite_friend_of_youngest = youngest_person
        
        # Query to find all favorite friends
        cursor.execute('SELECT DISTINCT favorite_friend FROM people WHERE favorite_friend IS NOT NULL')
        favorite_friends = set(row[0] for row in cursor.fetchall())
        
        # Check if the favorite friend of the youngest is not in the list of favorite friends
        if favorite_friend_of_youngest not in favorite_friends:
            print(f"The favorite friend of the youngest person ({youngest_text}) who isn't anyone's favorite friend is: {favorite_friend_of_youngest}")
        else:
            print(f"The favorite friend of the youngest person ({youngest_text}) is also someone's favorite friend.")
    else:
        print("No data found in the database.")

    # Close the connection
    conn.close()

# Run the function
get_favorite_friend_of_youngest_non_favorite()

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
import sqlite3

def get_favorite_friend_of_youngest_non_favorite():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    # Query to find the youngest person and their favorite friend
    cursor.execute('''
        SELECT TEXT, favorite_friend
        FROM people
        WHERE age = (SELECT MIN(age) FROM people)
    ''')
    
    # Fetch the results
    youngest_person = cursor.fetchone()
    
    if youngest_person:
        youngest_text, favorite_friend_of_youngest = youngest_person
        
        # Query to find all favorite friends
        cursor.execute('SELECT DISTINCT favorite_friend FROM people WHERE favorite_friend IS NOT NULL')
        favorite_friends = set(row[0] for row in cursor.fetchall())
        
        # Check if the favorite friend of the youngest is not in the list of favorite friends
        if favorite_friend_of_youngest not in favorite_friends:
            print(f"The favorite friend of the youngest person ({youngest_text}) who isn't anyone's favorite friend is: {favorite_friend_of_youngest}")
        else:
            print(f"The favorite friend of the youngest person ({youngest_text}) is also someone's favorite friend.")
    else:
        print("No data found in the database.")

    # Close the connection
    conn.close()

# Run the function
get_favorite_friend_of_youngest_non_favorite()
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 38, in <module> get_favorite_friend_of_youngest_non_favorite() File "/usr/src/app/main.py", line 10, in get_favorite_friend_of_youngest_non_favorite cursor.execute(''' sqlite3.OperationalError: no such column: TEXT

Substring Evaluation

Testing if the previous output contains the string Grace: False