Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

Output

To accomplish this task, we will use Python's `sqlite3` module to interact with your SQLite database. The program will perform the following steps: 1. Connect to the database `people.db`. 2. Execute an SQL query to find the youngest person who isn't anyone's favorite friend. 3. Print the favorite friend of the found person. Here's the Python code to do this:

import sqlite3

def find_favorite_friend_of_youngest_non_favorite():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()
    
    # SQL query to find the favorite friend of the youngest person who isn't anyone's favorite friend
    query = """
    SELECT favorite_friend
    FROM people
    WHERE name NOT IN (SELECT favorite_friend FROM people)
    ORDER BY age ASC
    LIMIT 1
    """
    
    try:
        cursor.execute(query)
        result = cursor.fetchone()
        
        if result:
            print("Favorite friend of the youngest non-favorite person: ", result[0])
        else:
            print("No person found.")
    except sqlite3.Error as e:
        print("An error occurred:", e)
    finally:
        # Close the database connection
        conn.close()

# Call the function
find_favorite_friend_of_youngest_non_favorite()

This script assumes that your table includes a column named `name` which uniquely identifies each person. If the column is named differently, you'll need to adjust the `WHERE name NOT IN...` part of the query accordingly. Here's a breakdown of what the SQL query does: - `WHERE name NOT IN (SELECT favorite_friend FROM people)`: This part selects people who are not listed as anyone's favorite friend. - `ORDER BY age ASC`: This orders the resulting people by their age in ascending order, ensuring the youngest person comes first. - `LIMIT 1`: This limits the result to just the first row from the sorted list, which corresponds to the youngest person who meets the criteria. Make sure you have the `sqlite3` module installed (it comes with the standard Python distribution, so you should have it by default), and replace `'people.db'` with the correct path to your database file if it's not in the same directory as your script.

Extract Code

I extracted the following code from that output:

import sqlite3

def find_favorite_friend_of_youngest_non_favorite():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()
    
    # SQL query to find the favorite friend of the youngest person who isn't anyone's favorite friend
    query = """
    SELECT favorite_friend
    FROM people
    WHERE name NOT IN (SELECT favorite_friend FROM people)
    ORDER BY age ASC
    LIMIT 1
    """
    
    try:
        cursor.execute(query)
        result = cursor.fetchone()
        
        if result:
            print("Favorite friend of the youngest non-favorite person: ", result[0])
        else:
            print("No person found.")
    except sqlite3.Error as e:
        print("An error occurred:", e)
    finally:
        # Close the database connection
        conn.close()

# Call the function
find_favorite_friend_of_youngest_non_favorite()

Run Code Interpreter

Running the following program:

import sqlite3

def find_favorite_friend_of_youngest_non_favorite():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()
    
    # SQL query to find the favorite friend of the youngest person who isn't anyone's favorite friend
    query = """
    SELECT favorite_friend
    FROM people
    WHERE name NOT IN (SELECT favorite_friend FROM people)
    ORDER BY age ASC
    LIMIT 1
    """
    
    try:
        cursor.execute(query)
        result = cursor.fetchone()
        
        if result:
            print("Favorite friend of the youngest non-favorite person: ", result[0])
        else:
            print("No person found.")
    except sqlite3.Error as e:
        print("An error occurred:", e)
    finally:
        # Close the database connection
        conn.close()

# Call the function
find_favorite_friend_of_youngest_non_favorite()

And got the output: Favorite friend of the youngest non-favorite person: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

To achieve the task you've described, you'll need a Python program that interacts with the SQLite database to query the information. Specifically, the program should find the youngest person (minimum age) who is not listed as anyone's favorite friend, and then print out this person's favorite friend. Here's a Python script that accomplishes this. It uses the `sqlite3` module to interact with your SQLite database:

import sqlite3

def find_special_friend(db_name):
    # Connect to the SQLite database
    conn = sqlite3.connect(db_name)
    cursor = conn.cursor()
    
    try:
        # SQL query to find the favorite friend of the youngest person
        # who isn't anyone's favorite friend
        query = """
        SELECT p.favorite_friend
        FROM people p
        WHERE p.name NOT IN (SELECT DISTINCT favorite_friend FROM people)
        ORDER BY p.age ASC
        LIMIT 1;
        """
        
        # Execute the query
        cursor.execute(query)
        result = cursor.fetchone()
        
        # Check if there's a result and print the favorite friend
        if result:
            print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[0]}")
        else:
            print("No such person found.")
            
    except Exception as e:
        print(f"An error occurred: {e}")
    finally:
        # Close the database connection
        conn.close()

# Replace 'people.db' with the path to your actual SQLite database file if necessary
db_name = "people.db"
find_special_friend(db_name)

This script defines a function `find_special_friend` that takes the database name as an argument. It then connects to the database, executes an SQL query to find the required information, and prints the result. Note: This script assumes that your table and columns are set up as described and that there is a `name` column in your `people` table which uniquely identifies each person. Since the table structure you provided does not include a `name` column explicitly, I assumed its presence for the logic to make sense (i.e., identifying who is not anyone's favorite friend). If your table structure is different, you may need to adjust the SQL query accordingly.

Extract Code

I extracted the following code from that output:

import sqlite3

def find_special_friend(db_name):
    # Connect to the SQLite database
    conn = sqlite3.connect(db_name)
    cursor = conn.cursor()
    
    try:
        # SQL query to find the favorite friend of the youngest person
        # who isn't anyone's favorite friend
        query = """
        SELECT p.favorite_friend
        FROM people p
        WHERE p.name NOT IN (SELECT DISTINCT favorite_friend FROM people)
        ORDER BY p.age ASC
        LIMIT 1;
        """
        
        # Execute the query
        cursor.execute(query)
        result = cursor.fetchone()
        
        # Check if there's a result and print the favorite friend
        if result:
            print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[0]}")
        else:
            print("No such person found.")
            
    except Exception as e:
        print(f"An error occurred: {e}")
    finally:
        # Close the database connection
        conn.close()

# Replace 'people.db' with the path to your actual SQLite database file if necessary
db_name = "people.db"
find_special_friend(db_name)

Run Code Interpreter

Running the following program:

import sqlite3

def find_special_friend(db_name):
    # Connect to the SQLite database
    conn = sqlite3.connect(db_name)
    cursor = conn.cursor()
    
    try:
        # SQL query to find the favorite friend of the youngest person
        # who isn't anyone's favorite friend
        query = """
        SELECT p.favorite_friend
        FROM people p
        WHERE p.name NOT IN (SELECT DISTINCT favorite_friend FROM people)
        ORDER BY p.age ASC
        LIMIT 1;
        """
        
        # Execute the query
        cursor.execute(query)
        result = cursor.fetchone()
        
        # Check if there's a result and print the favorite friend
        if result:
            print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[0]}")
        else:
            print("No such person found.")
            
    except Exception as e:
        print(f"An error occurred: {e}")
    finally:
        # Close the database connection
        conn.close()

# Replace 'people.db' with the path to your actual SQLite database file if necessary
db_name = "people.db"
find_special_friend(db_name)

And got the output: The favorite friend of the youngest person who isn't anyone's favorite friend is: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

To solve this problem, we first need to identify the youngest person who isn't anyone's favorite friend. This involves a few steps: 1. **Identify the favorite friends**: We need to find out who is listed as a favorite friend by anyone. 2. **Find the youngest person not in the favorite list**: From the remaining people (excluding those found in step 1), find the youngest. 3. **Print out the favorite friend of the person identified in step 2**. Here's a Python program that accomplishes this by using the SQLite3 library to interact with your database:

import sqlite3

def get_youngest_nonfavorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    try:
        # Step 1: Identify all unique favorite friends
        cursor.execute("SELECT DISTINCT favorite_friend FROM people")
        favorite_friends = set([row[0] for row in cursor.fetchall()])

        # Step 2: Find the youngest person who isn't anyone's favorite friend
        cursor.execute("""
            SELECT name, favorite_friend 
            FROM people 
            WHERE name NOT IN ('{}') 
            ORDER BY age ASC
            LIMIT 1
        """.format("', '".join(favorite_friends)))
        result = cursor.fetchone()

        if result:
            # Step 3: Print out the favorite friend of the youngest non-favorite person
            print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[1]}")
        else:
            print("Could not find such a person.")
            
    except sqlite3.Error as e:
        print(f"An error occurred: {e}")
    finally:
        # Close the database connection
        conn.close()

# Call the function to execute the program
get_youngest_nonfavorite_friend()

This program does exactly what's needed by: - Making a connection to the `people.db` SQLite database. - Executing SQL queries to find the desired person according to the criteria. - Handling any potential errors that might occur during database operations. - Finally, it closes the database connection to ensure there's no resource leak. Please note, for this example to work, your database and table structure must match exactly what you've described, and your Python environment needs to have SQLite3 available (which is typically included with Python).

Extract Code

I extracted the following code from that output:

import sqlite3

def get_youngest_nonfavorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    try:
        # Step 1: Identify all unique favorite friends
        cursor.execute("SELECT DISTINCT favorite_friend FROM people")
        favorite_friends = set([row[0] for row in cursor.fetchall()])

        # Step 2: Find the youngest person who isn't anyone's favorite friend
        cursor.execute("""
            SELECT name, favorite_friend 
            FROM people 
            WHERE name NOT IN ('{}') 
            ORDER BY age ASC
            LIMIT 1
        """.format("', '".join(favorite_friends)))
        result = cursor.fetchone()

        if result:
            # Step 3: Print out the favorite friend of the youngest non-favorite person
            print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[1]}")
        else:
            print("Could not find such a person.")
            
    except sqlite3.Error as e:
        print(f"An error occurred: {e}")
    finally:
        # Close the database connection
        conn.close()

# Call the function to execute the program
get_youngest_nonfavorite_friend()

Run Code Interpreter

Running the following program:

import sqlite3

def get_youngest_nonfavorite_friend():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()

    try:
        # Step 1: Identify all unique favorite friends
        cursor.execute("SELECT DISTINCT favorite_friend FROM people")
        favorite_friends = set([row[0] for row in cursor.fetchall()])

        # Step 2: Find the youngest person who isn't anyone's favorite friend
        cursor.execute("""
            SELECT name, favorite_friend 
            FROM people 
            WHERE name NOT IN ('{}') 
            ORDER BY age ASC
            LIMIT 1
        """.format("', '".join(favorite_friends)))
        result = cursor.fetchone()

        if result:
            # Step 3: Print out the favorite friend of the youngest non-favorite person
            print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[1]}")
        else:
            print("Could not find such a person.")
            
    except sqlite3.Error as e:
        print(f"An error occurred: {e}")
    finally:
        # Close the database connection
        conn.close()

# Call the function to execute the program
get_youngest_nonfavorite_friend()

And got the output: The favorite friend of the youngest person who isn't anyone's favorite friend is: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

To achieve this, you need a Python program that accesses your SQLite3 database, performs the necessary queries to find the youngest person who isn't anyone's favorite friend, and then prints out their favorite friend. Here's a step-by-step guide to writing such a program. 1. **Connect to the Database**: Use `sqlite3` to connect to `people.db`. 2. **Find the Youngest Person Not a Favorite**: This requires a bit of SQL logic. You need to first find people who are not anyone's favorite friend and then from those, find the youngest. 3. **Print the Favorite Friend of that Person**: Once you've identified the person, retrieve and print their favorite friend's name. Here's how you can write the program:

import sqlite3

def find_favorite_friend_of_youngest_non_favorite():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()
    
    # SQL query to find the youngest person who isn't anyone's favorite friend
    query = """
    SELECT favorite_friend 
    FROM people 
    WHERE name NOT IN (SELECT DISTINCT favorite_friend FROM people) 
    ORDER BY age 
    LIMIT 1;
    """
    
    try:
        cursor.execute(query)
        result = cursor.fetchone()  # Fetches the first row of the query result
        if result:
            favorite_friend = result[0]
            print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
        else:
            print("There was no match found based on the criteria.")
    except sqlite3.Error as e:
        print(f"An error occurred: {e}")
    finally:
        conn.close()  # Ensure the connection is closed

if __name__ == "__main__":
    find_favorite_friend_of_youngest_non_favorite()

**Important Notes:** - Ensure `sqlite3` is already available in your Python environment (it should be, as it's part of the standard library from Python 2.5 onwards). - The SQL query inside the script might need adjustments based on the exact schema of your table. For example, I've assumed the person's name column is called `name`, which was not specified in your description. - This script assumes that the table `people` and the database `people.db` exist and are accessible at the script's execution path. If your database is located elsewhere, you'll need to provide the full path in the `connect` method. - The script uses a simple error handling approach, just printing out any errors encountered. For more complex applications, you might want to implement more sophisticated error handling.

Extract Code

I extracted the following code from that output:

import sqlite3

def find_favorite_friend_of_youngest_non_favorite():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()
    
    # SQL query to find the youngest person who isn't anyone's favorite friend
    query = """
    SELECT favorite_friend 
    FROM people 
    WHERE name NOT IN (SELECT DISTINCT favorite_friend FROM people) 
    ORDER BY age 
    LIMIT 1;
    """
    
    try:
        cursor.execute(query)
        result = cursor.fetchone()  # Fetches the first row of the query result
        if result:
            favorite_friend = result[0]
            print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
        else:
            print("There was no match found based on the criteria.")
    except sqlite3.Error as e:
        print(f"An error occurred: {e}")
    finally:
        conn.close()  # Ensure the connection is closed

if __name__ == "__main__":
    find_favorite_friend_of_youngest_non_favorite()

Run Code Interpreter

Running the following program:

import sqlite3

def find_favorite_friend_of_youngest_non_favorite():
    # Connect to the SQLite database
    conn = sqlite3.connect('people.db')
    cursor = conn.cursor()
    
    # SQL query to find the youngest person who isn't anyone's favorite friend
    query = """
    SELECT favorite_friend 
    FROM people 
    WHERE name NOT IN (SELECT DISTINCT favorite_friend FROM people) 
    ORDER BY age 
    LIMIT 1;
    """
    
    try:
        cursor.execute(query)
        result = cursor.fetchone()  # Fetches the first row of the query result
        if result:
            favorite_friend = result[0]
            print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
        else:
            print("There was no match found based on the criteria.")
    except sqlite3.Error as e:
        print(f"An error occurred: {e}")
    finally:
        conn.close()  # Ensure the connection is closed

if __name__ == "__main__":
    find_favorite_friend_of_youngest_non_favorite()

And got the output: The favorite friend of the youngest person who isn't anyone's favorite friend is: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

To achieve this, first, you need to have SQLite and Python installed on your system. Then, you can use the following Python script to query your SQLite database (`people.db`) for the favorite friend of the youngest person who isn't anyone's favorite friend from the `people` table:

import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

try:
    # Query to find the favorite friend of the youngest person who isn't anyone's favorite friend
    query = """
    WITH NonFavoriteFriends AS (
        SELECT name
        FROM people
        WHERE name NOT IN (
            SELECT DISTINCT favorite_friend
            FROM people
        )
    )
    SELECT favorite_friend
    FROM people, NonFavoriteFriends
    WHERE people.name = NonFavoriteFriends.name
    ORDER BY age ASC
    LIMIT 1;
    """
    
    cursor.execute(query)
    result = cursor.fetchone()
    
    if result:
        print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[0]}")
    else:
        print("No such person found.")
        
except sqlite3.Error as error:
    print("Error while executing the query", error)
finally:
    cursor.close()
    conn.close()

### What this script does: 1. It establishes a connection to the `people.db` SQLite database. 2. It defines a SQL query using a Common Table Expression (CTE) named `NonFavoriteFriends` to: - First, select all the names from the `people` table that are not listed as anyone's favorite friend. - Then, from those results, find the favorite friend of the youngest person by ordering the results by age in ascending order and limiting the result to 1. 3. It executes the query and fetches the first result. 4. If a result is found, it prints the name of the favorite friend of the youngest person who isn't anyone else's favorite friend. If no such person exists, it prints a message indicating that no such person was found. 5. It handles any potential errors that might occur during the execution of the SQL query. 6. Finally, it closes the cursor and the connection to the database. Make sure your Python environment is set up correctly and that you have access to the `people.db` database. Also, ensure that the structure of your `people` table matches the expectations of the script in terms of column names and data types.

Extract Code

I extracted the following code from that output:

import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

try:
    # Query to find the favorite friend of the youngest person who isn't anyone's favorite friend
    query = """
    WITH NonFavoriteFriends AS (
        SELECT name
        FROM people
        WHERE name NOT IN (
            SELECT DISTINCT favorite_friend
            FROM people
        )
    )
    SELECT favorite_friend
    FROM people, NonFavoriteFriends
    WHERE people.name = NonFavoriteFriends.name
    ORDER BY age ASC
    LIMIT 1;
    """
    
    cursor.execute(query)
    result = cursor.fetchone()
    
    if result:
        print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[0]}")
    else:
        print("No such person found.")
        
except sqlite3.Error as error:
    print("Error while executing the query", error)
finally:
    cursor.close()
    conn.close()

Run Code Interpreter

Running the following program:

import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
cursor = conn.cursor()

try:
    # Query to find the favorite friend of the youngest person who isn't anyone's favorite friend
    query = """
    WITH NonFavoriteFriends AS (
        SELECT name
        FROM people
        WHERE name NOT IN (
            SELECT DISTINCT favorite_friend
            FROM people
        )
    )
    SELECT favorite_friend
    FROM people, NonFavoriteFriends
    WHERE people.name = NonFavoriteFriends.name
    ORDER BY age ASC
    LIMIT 1;
    """
    
    cursor.execute(query)
    result = cursor.fetchone()
    
    if result:
        print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[0]}")
    else:
        print("No such person found.")
        
except sqlite3.Error as error:
    print("Error while executing the query", error)
finally:
    cursor.close()
    conn.close()

And got the output: The favorite friend of the youngest person who isn't anyone's favorite friend is: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True