Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Here's a Python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT p.favorite_friend
FROM people p
WHERE p.age = (
    SELECT MIN(age)
    FROM people
    WHERE name NOT IN (
        SELECT favorite_friend
        FROM people
        WHERE favorite_friend IS NOT NULL
    )
)
LIMIT 1;
"""

# Execute the query
c.execute(query)

# Get the result
result = c.fetchone()

# Print the result
if result:
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[0]}")
else:
    print("No matching record found.")

# Close the database connection
conn.close()
Here's how the program works: 1. The program connects to the SQLite database file `people.db`. 2. It constructs a SQL query that does the following: - The subquery `SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL` finds all the distinct favorite friends mentioned in the `people` table. - The main query selects the `favorite_friend` of the person with the minimum `age` from the `people` table, where the `name` is not present in the list of favorite friends obtained from the subquery. - The `LIMIT 1` clause ensures that only one record is returned, which corresponds to the youngest person who isn't anyone's favorite friend. 3. The program executes the query and fetches the result using `c.fetchone()`. 4. If a result is found, it prints the favorite friend of the youngest person who isn't anyone's favorite friend. 5. Finally, the database connection is closed. Note: This program assumes that the `people` table has the columns `name`, `favorite_friend`, `age`, and `profession`, and that the database file `people.db` exists in the same directory as the Python script.

Extract Code

I extracted the following code from that output: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT p.favorite_friend
FROM people p
WHERE p.age = (
    SELECT MIN(age)
    FROM people
    WHERE name NOT IN (
        SELECT favorite_friend
        FROM people
        WHERE favorite_friend IS NOT NULL
    )
)
LIMIT 1;
"""

# Execute the query
c.execute(query)

# Get the result
result = c.fetchone()

# Print the result
if result:
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[0]}")
else:
    print("No matching record found.")

# Close the database connection
conn.close()

Run Code Interpreter

Running the following program: 

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import sqlite3

# Connect to the SQLite database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT p.favorite_friend
FROM people p
WHERE p.age = (
    SELECT MIN(age)
    FROM people
    WHERE name NOT IN (
        SELECT favorite_friend
        FROM people
        WHERE favorite_friend IS NOT NULL
    )
)
LIMIT 1;
"""

# Execute the query
c.execute(query)

# Get the result
result = c.fetchone()

# Print the result
if result:
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {result[0]}")
else:
    print("No matching record found.")

# Close the database connection
conn.close()
And got the output: The favorite friend of the youngest person who isn't anyone's favorite friend is: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Here's a Python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend, using the SQLite3 database `people.db` and the table `people`: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT name, favorite_friend, age
FROM people
WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)
ORDER BY age ASC
LIMIT 1
"""

# Execute the query
c.execute(query)
result = c.fetchone()

if result:
    name, favorite_friend, age = result
    print(f"The favorite friend of the youngest person ({name}, age {age}) who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No one satisfies the condition.")

# Close the database connection
conn.close()
Here's how the program works: 1. We connect to the SQLite3 database `people.db` using the `sqlite3.connect()` function and create a cursor object `c`. 2. We construct an SQL query that finds the youngest person who isn't anyone's favorite friend. The query uses a subquery to get the list of names that are someone's favorite friend, and then selects the name, favorite friend, and age of those people whose names are not in that list. The results are ordered by age in ascending order, and we take only the first row using `LIMIT 1`. 3. We execute the query using `c.execute(query)` and fetch the result using `c.fetchone()`. 4. If a result is returned, we unpack the result tuple into `name`, `favorite_friend`, and `age` variables and print out the desired information. 5. If no result is returned, we print a message indicating that no one satisfies the condition. 6. Finally, we close the database connection using `conn.close()`. Note that this program assumes that the table `people` has the columns `name`, `favorite_friend`, and `age`. If your table has different column names, you'll need to modify the SQL query accordingly.

Extract Code

I extracted the following code from that output: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT name, favorite_friend, age
FROM people
WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)
ORDER BY age ASC
LIMIT 1
"""

# Execute the query
c.execute(query)
result = c.fetchone()

if result:
    name, favorite_friend, age = result
    print(f"The favorite friend of the youngest person ({name}, age {age}) who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No one satisfies the condition.")

# Close the database connection
conn.close()

Run Code Interpreter

Running the following program: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT name, favorite_friend, age
FROM people
WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)
ORDER BY age ASC
LIMIT 1
"""

# Execute the query
c.execute(query)
result = c.fetchone()

if result:
    name, favorite_friend, age = result
    print(f"The favorite friend of the youngest person ({name}, age {age}) who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No one satisfies the condition.")

# Close the database connection
conn.close()
And got the output: The favorite friend of the youngest person (Judy, age 27) who isn't anyone's favorite friend is: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Here's a Python program that should do what you're looking for: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT name, favorite_friend
FROM people
WHERE age = (SELECT MIN(age) FROM people WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL))
"""

# Execute the query
c.execute(query)
result = c.fetchone()

# Print the favorite friend of the youngest person who isn't anyone's favorite friend
if result:
    name, favorite_friend = result
    print(f"The favorite friend of the youngest person ({name}) who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No one matches the criteria.")

# Close the database connection
conn.close()
Here's how the program works: 1. The program connects to the SQLite database file `people.db` using the `sqlite3` module. 2. It then constructs a SQL query using a subquery to find the youngest person whose name is not present in the `favorite_friend` column (i.e., not anyone's favorite friend). 3. The query selects the `name` and `favorite_friend` columns from the `people` table for the record with the minimum age that satisfies the subquery condition. 4. The `c.execute(query)` line executes the SQL query, and `c.fetchone()` retrieves the result. 5. If a result is found, the program prints the favorite friend of the youngest person who isn't anyone's favorite friend. Otherwise, it prints a message indicating that no one matches the criteria. 6. Finally, the program closes the database connection using `conn.close()`. Note that this assumes your database schema matches the one you provided (`name TEXT, favorite_friend TEXT, age INT, profession TEXT`) and that the table name is `people`. If your schema or table name is different, you'll need to modify the code accordingly.

Extract Code

I extracted the following code from that output: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT name, favorite_friend
FROM people
WHERE age = (SELECT MIN(age) FROM people WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL))
"""

# Execute the query
c.execute(query)
result = c.fetchone()

# Print the favorite friend of the youngest person who isn't anyone's favorite friend
if result:
    name, favorite_friend = result
    print(f"The favorite friend of the youngest person ({name}) who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No one matches the criteria.")

# Close the database connection
conn.close()

Run Code Interpreter

Running the following program: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT name, favorite_friend
FROM people
WHERE age = (SELECT MIN(age) FROM people WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL))
"""

# Execute the query
c.execute(query)
result = c.fetchone()

# Print the favorite friend of the youngest person who isn't anyone's favorite friend
if result:
    name, favorite_friend = result
    print(f"The favorite friend of the youngest person ({name}) who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No one matches the criteria.")

# Close the database connection
conn.close()
And got the output: The favorite friend of the youngest person (Judy) who isn't anyone's favorite friend is: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Sure, here's a Python program that solves your problem: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Find the youngest person who isn't anyone's favorite friend
c.execute('''
    SELECT name, favorite_friend, age
    FROM people
    WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)
    ORDER BY age ASC
    LIMIT 1
''')
result = c.fetchone()

if result:
    name, favorite_friend, age = result
    print(f"The youngest person who isn't anyone's favorite friend is {name}, aged {age}, and their favorite friend is {favorite_friend}.")
else:
    print("No one in the database meets the criteria.")

# Close the connection
conn.close()
Here's how the program works: 1. The program connects to the SQLite database file `people.db` using the `sqlite3` module. 2. It then executes a SQL query to find the youngest person who isn't anyone's favorite friend. The query does this by: - Selecting the `name`, `favorite_friend`, and `age` columns from the `people` table. - Using a subquery to find all the distinct `favorite_friend` values that are not `NULL` (i.e., all the names that are someone's favorite friend). - Excluding those names from the main query using the `NOT IN` clause. - Ordering the results by `age` in ascending order. - Taking only the first result using the `LIMIT 1` clause. 3. If there is a result (i.e., if there is at least one person who isn't anyone's favorite friend), the program prints out their name, age, and favorite friend. 4. If there is no result (i.e., if everyone in the database is someone's favorite friend), the program prints out a message indicating that no one meets the criteria. 5. Finally, the program closes the database connection. Note that this program assumes that the `people` table has the columns `name`, `favorite_friend`, `age`, and `profession`, as specified in your question.

Extract Code

I extracted the following code from that output: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Find the youngest person who isn't anyone's favorite friend
c.execute('''
    SELECT name, favorite_friend, age
    FROM people
    WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)
    ORDER BY age ASC
    LIMIT 1
''')
result = c.fetchone()

if result:
    name, favorite_friend, age = result
    print(f"The youngest person who isn't anyone's favorite friend is {name}, aged {age}, and their favorite friend is {favorite_friend}.")
else:
    print("No one in the database meets the criteria.")

# Close the connection
conn.close()

Run Code Interpreter

Running the following program: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Find the youngest person who isn't anyone's favorite friend
c.execute('''
    SELECT name, favorite_friend, age
    FROM people
    WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)
    ORDER BY age ASC
    LIMIT 1
''')
result = c.fetchone()

if result:
    name, favorite_friend, age = result
    print(f"The youngest person who isn't anyone's favorite friend is {name}, aged {age}, and their favorite friend is {favorite_friend}.")
else:
    print("No one in the database meets the criteria.")

# Close the connection
conn.close()
And got the output: The youngest person who isn't anyone's favorite friend is Judy, aged 27, and their favorite friend is Grace.

Substring Evaluation

Testing if the previous output contains the string Grace: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

LLM Generation

Query

I have a sqlite3 database name TEXT, favorite_friend TEXT, age INT, profession TEXT. Write me a python program that prints out the favorite friend of the youngest person who isn't anyone's favorite friend. The database is called people.db and the table is called people.

Output

Here's a Python program that accomplishes the given task: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT name, favorite_friend
FROM people
WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)
ORDER BY age ASC
LIMIT 1;
"""

# Execute the query
c.execute(query)
result = c.fetchone()

# Print the result
if result:
    name, favorite_friend = result
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No results found.")

# Close the database connection
conn.close()
Here's how the program works: 1. First, we import the `sqlite3` module to work with SQLite databases. 2. We connect to the database file `people.db` using `sqlite3.connect('people.db')`. 3. We create a cursor object `c` to execute SQL queries. 4. We construct a SQL query that does the following: - `SELECT name, favorite_friend FROM people`: This selects the `name` and `favorite_friend` columns from the `people` table. - `WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)`: This condition filters out all the people whose names are listed as someone else's favorite friend. This ensures that we only consider people who aren't anyone's favorite friend. - `ORDER BY age ASC`: This orders the results by age in ascending order, so the youngest person comes first. - `LIMIT 1`: This limits the results to just the first row, which will be the youngest person who isn't anyone's favorite friend. 5. We execute the query using `c.execute(query)`. 6. We fetch the result using `c.fetchone()`, which returns a tuple with the `name` and `favorite_friend` values, or `None` if there are no results. 7. If there is a result, we print the favorite friend of the youngest person using an f-string. 8. Finally, we close the database connection using `conn.close()`. Note that this program assumes that the `people` table exists in the `people.db` database and has columns named `name`, `favorite_friend`, `age`, and `profession`.

Extract Code

I extracted the following code from that output: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT name, favorite_friend
FROM people
WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)
ORDER BY age ASC
LIMIT 1;
"""

# Execute the query
c.execute(query)
result = c.fetchone()

# Print the result
if result:
    name, favorite_friend = result
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No results found.")

# Close the database connection
conn.close()

Run Code Interpreter

Running the following program: 

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import sqlite3

# Connect to the database
conn = sqlite3.connect('people.db')
c = conn.cursor()

# Query to find the youngest person who isn't anyone's favorite friend
query = """
SELECT name, favorite_friend
FROM people
WHERE name NOT IN (SELECT favorite_friend FROM people WHERE favorite_friend IS NOT NULL)
ORDER BY age ASC
LIMIT 1;
"""

# Execute the query
c.execute(query)
result = c.fetchone()

# Print the result
if result:
    name, favorite_friend = result
    print(f"The favorite friend of the youngest person who isn't anyone's favorite friend is: {favorite_friend}")
else:
    print("No results found.")

# Close the database connection
conn.close()
And got the output: The favorite friend of the youngest person who isn't anyone's favorite friend is: Grace

Substring Evaluation

Testing if the previous output contains the string Grace: True