Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

The disassembled bytecode corresponds to a function that implements the following operations: 1. Load the parameter a. 2. Load the parameter b. 3. Load the parameter a again. 4. Multiply the second a (from step 3) by b. 5. Add the result of the multiplication to the initial a. 6. Return the computed value. This gives us the function: def foo(a, b): return a + a * b Here’s how the bytecode maps to the function: • LOAD_FAST 0 (a) → Push a on the stack. • LOAD_FAST 1 (b) → Push b on the stack. • LOAD_FAST 0 (a) → Push another a on the stack. • BINARY_MULTIPLY → Multiply the top two values (b and a) → computes a * b. • BINARY_ADD → Add the remaining a on the stack to the multiplication result → computes a + (a * b). • RETURN_VALUE → Return the result. Thus, the function foo is: def foo(a, b): return a + a * b

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return a + a * b

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
def foo(a, b):
    return a + a * b




answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the disassembled code, the function does the following: 1. Loads the variable a. 2. Loads the variable b. 3. Loads the variable a again. 4. Multiplies the two most recent values (b * a). 5. Adds the first a to the product (a + (a * b)). 6. Returns the result. Here's the Python function equivalent to that bytecode: def foo(a, b): return a + a * b This function calculates a + (a * b), which is mathematically equivalent to a * (b + 1).

Extract Code

I extracted the following code from that output: 

1
2
3
4
#!/usr/bin/env python3

def foo(a, b):
    return a + a * b

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
#!/usr/bin/env python3

def foo(a, b):
    return a + a * b




answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True