Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

The given Python bytecode sequence performs the following operations: 1. Loads the value of the first argument (referred to as `a`). 2. Loads the value of the second argument (referred to as `b`). 3. Loads the value of `a` again. 4. Multiplies the two values of `a`. 5. Adds the result of the multiplication to the value of `b`. 6. Returns the result. Translating this into a Python function named `foo`, it would look something like the following: 

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def foo(a, b):
    return a * a + b
This function takes two arguments, `a` and `b`, multiplies `a` by itself, adds `b` to the result of that multiplication, and then returns the final result.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return a * a + b

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return a * a + b





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

The Python bytecode you've provided performs a simple arithmetic operation. It loads two variables, `a` and `b`, multiplies `a` by itself, then adds `b` to the result of the multiplication, and finally returns the result. This can be translated into a Python function as follows: 

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def foo(a, b):
    return a * a + b
This function, `foo`, takes two arguments, `a` and `b`, then it calculates `a * a + b`, and returns the result.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return a * a + b

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return a * a + b





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

The disassembled Python bytecode you've provided corresponds to a function that takes two arguments (let's call them `a` and `b`), performs an operation where it multiplies `a` by itself (`a * a`) and then adds the result to `b`. The bytecode steps through loading the arguments, performing the multiplication, adding the result to `b`, and then returning the result. Here's how you could define the function in Python: 

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def foo(a, b):
    return a * a + b
This function `foo` takes two parameters, `a` and `b`, multiplies `a` by itself, adds `b` to the result of the multiplication, and then returns the final result.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return a * a + b

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return a * a + b





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

The Python bytecode you provided corresponds to a simple function that takes two parameters, multiplies the first parameter by itself, and then adds the second parameter to the result of the multiplication. To convert this bytecode into a Python function, we can follow the instructions step by step: - `LOAD_FAST 0 (a)`: This loads the first argument of the function, let's call it `a`. - `LOAD_FAST 1 (b)`: This loads the second argument of the function, let's call it `b`. - `LOAD_FAST 0 (a)`: This loads the first argument `a` again for the multiplication. - `BINARY_MULTIPLY`: This multiplies the two topmost items on the stack, which are both `a` in this case, effectively calculating `a*a`. - `BINARY_ADD`: This adds the topmost items on the stack, which are `a*a` and `b`, effectively calculating `(a*a) + b`. - `RETURN_VALUE`: This returns the result of the addition. Based on this, the Python function `foo` corresponding to the provided bytecode would look like this: 

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def foo(a, b):
    return (a*a) + b
This function takes two inputs, `a` and `b`, squares `a`, then adds `b` to the result, and finally returns the outcome.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return (a*a) + b

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return (a*a) + b





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the bytecode provided, we can reconstruct the Python function. The bytecode indicates that the function takes two arguments (a and b), multiplies `a` by itself, and then adds `b` to the result. Here's how the function, named `foo`, would look in Python: 

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def foo(a, b):
    return a * a + b
This function corresponds to the bytecode operations as follows: - `LOAD_FAST 0 (a)` and `LOAD_FAST 1 (b)` load the arguments `a` and `b` onto the stack. - `LOAD_FAST 0 (a)` again loads `a` onto the stack for the multiplication operation. - `BINARY_MULTIPLY` then multiplies the two topmost stack items (both `a` in this case). - `BINARY_ADD` adds the result of the multiplication (`a*a`) to `b`. - Finally, `RETURN_VALUE` returns the result of the addition.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return a * a + b

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return a * a + b





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False