Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

1
2
3
4
5
6
7
def foo(a, b):
    """
    This function takes two arguments, a and b, and returns their sum after multiplying a by itself.

    Equivalent to:  a * a + b
    """
    return a * a + b

Extract Code

I extracted the following code from that output:

1
2
3
4
5
6
7
def foo(a, b):
    """
    This function takes two arguments, a and b, and returns their sum after multiplying a by itself.

    Equivalent to:  a * a + b
    """
    return a * a + b

Run Code Interpreter

Running the following program:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
def foo(a, b):
    """
    This function takes two arguments, a and b, and returns their sum after multiplying a by itself.

    Equivalent to:  a * a + b
    """
    return a * a + b






answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 17, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
def foo(a, b):
    """
    This function performs the operation a * a + b.

    Args:
        a: The first number.
        b: The second number.

    Returns:
        The result of a * a + b.
    """
    return a * a + b
**Explanation of the Bytecode:** * **LOAD_FAST 0 (a):** Pushes the value of the local variable `a` onto the stack. * **LOAD_FAST 1 (b):** Pushes the value of the local variable `b` onto the stack. * **LOAD_FAST 0 (a):** Pushes the value of the local variable `a` onto the stack again. * **BINARY_MULTIPLY:** Pops the top two values from the stack (the two `a` values), multiplies them, and pushes the result back onto the stack. * **BINARY_ADD:** Pops the top two values from the stack (the result of `a * a` and `b`), adds them, and pushes the result back onto the stack. * **RETURN_VALUE:** Pops the top value from the stack (the result of `a * a + b`) and returns it as the function's result. The Python code `return a * a + b` directly mirrors the operations performed by the bytecode.

Extract Code

I extracted the following code from that output:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
def foo(a, b):
    """
    This function performs the operation a * a + b.

    Args:
        a: The first number.
        b: The second number.

    Returns:
        The result of a * a + b.
    """
    return a * a + b

Run Code Interpreter

Running the following program:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
def foo(a, b):
    """
    This function performs the operation a * a + b.

    Args:
        a: The first number.
        b: The second number.

    Returns:
        The result of a * a + b.
    """
    return a * a + b





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 21, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
def foo(a, b):
  """
  This function performs the operation a + (a * b) and returns the result.

  Args:
    a: The first number.
    b: The second number.

  Returns:
    The result of a + (a * b).
  """
  return a + (a * b)

Extract Code

I extracted the following code from that output:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
def foo(a, b):
  """
  This function performs the operation a + (a * b) and returns the result.

  Args:
    a: The first number.
    b: The second number.

  Returns:
    The result of a + (a * b).
  """
  return a + (a * b)

Run Code Interpreter

Running the following program:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
def foo(a, b):
  """
  This function performs the operation a + (a * b) and returns the result.

  Args:
    a: The first number.
    b: The second number.

  Returns:
    The result of a + (a * b).
  """
  return a + (a * b)





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
def foo(a, b):
    """
    This function performs the operation a + (a * b).

    Args:
        a: The first number.
        b: The second number.

    Returns:
        The result of a + (a * b).
    """
    return a + (a * b)
**Explanation of the Bytecode** The provided bytecode represents the core logic of the function. Let's break it down step-by-step: 1. **`0 LOAD_FAST 0 (a)`**: Loads the value of the local variable `a` onto the stack. 2. **`2 LOAD_FAST 1 (b)`**: Loads the value of the local variable `b` onto the stack. 3. **`4 LOAD_FAST 0 (a)`**: Loads the value of the local variable `a` onto the stack again. Now the stack contains `a`, `b`, and `a`. 4. **`6 BINARY_MULTIPLY`**: Pops the top two values from the stack (`a` and `b`), multiplies them, and pushes the result (`a * b`) back onto the stack. 5. **`8 BINARY_ADD`**: Pops the top two values from the stack (`a` and `a * b`), adds them, and pushes the result (`a + (a * b)`) back onto the stack. 6. **`10 RETURN_VALUE`**: Returns the value at the top of the stack, which is the result of the calculation. Therefore, the Python code equivalent to this bytecode is `a + (a * b)`, which is precisely what the `foo` function implements. The docstring added to the function explains its purpose and parameters, making the code more understandable.

Extract Code

I extracted the following code from that output:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
def foo(a, b):
    """
    This function performs the operation a + (a * b).

    Args:
        a: The first number.
        b: The second number.

    Returns:
        The result of a + (a * b).
    """
    return a + (a * b)

Run Code Interpreter

Running the following program:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
def foo(a, b):
    """
    This function performs the operation a + (a * b).

    Args:
        a: The first number.
        b: The second number.

    Returns:
        The result of a + (a * b).
    """
    return a + (a * b)





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
def foo(a, b):
    """
    This function adds the product of 'a' and itself to 'b'.

    Disassembled bytecode:
    56           0 LOAD_FAST                0 (a)
                  2 LOAD_FAST                1 (b)
                  4 LOAD_FAST                0 (a)
                  6 BINARY_MULTIPLY
                  8 BINARY_ADD
                 10 RETURN_VALUE
    """
    return b + a * a 
**Explanation of the bytecode:** 1. **`LOAD_FAST 0 (a)`:** Pushes the value of the local variable `a` onto the stack. 2. **`LOAD_FAST 1 (b)`:** Pushes the value of the local variable `b` onto the stack. 3. **`LOAD_FAST 0 (a)`:** Pushes the value of `a` onto the stack again. Now the stack has `a`, `b`, and `a` (from top to bottom). 4. **`BINARY_MULTIPLY`:** Pops the top two values from the stack (`a` and `a`), multiplies them, and pushes the result (a*a) back onto the stack. Now the stack contains `a*a` and `b`. 5. **`BINARY_ADD`:** Pops the top two values (`a*a` and `b`) adds them, and pushes the sum (`b + a*a`) back onto the stack. 6. **`RETURN_VALUE`:** Returns the value at the top of the stack (which is `b + a*a`). Therefore, the Python code equivalent to this bytecode is `return b + a * a`.

Extract Code

I extracted the following code from that output:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
def foo(a, b):
    """
    This function adds the product of 'a' and itself to 'b'.

    Disassembled bytecode:
    56           0 LOAD_FAST                0 (a)
                  2 LOAD_FAST                1 (b)
                  4 LOAD_FAST                0 (a)
                  6 BINARY_MULTIPLY
                  8 BINARY_ADD
                 10 RETURN_VALUE
    """
    return b + a * a

Run Code Interpreter

Running the following program:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
def foo(a, b):
    """
    This function adds the product of 'a' and itself to 'b'.

    Disassembled bytecode:
    56           0 LOAD_FAST                0 (a)
                  2 LOAD_FAST                1 (b)
                  4 LOAD_FAST                0 (a)
                  6 BINARY_MULTIPLY
                  8 BINARY_ADD
                 10 RETURN_VALUE
    """
    return b + a * a 





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 22, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False