Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE
Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE
The given Python bytecode corresponds to a simple mathematical operation. Let's break it down step by step: 1. **`LOAD_FAST 0 (a)`**: Load the value of the local variable `a` onto the stack. 2. **`LOAD_FAST 1 (b)`**: Load the value of the local variable `b` onto the stack. 3. **`LOAD_FAST 0 (a)`**: Load the value of the local variable `a` onto the stack again. 4. **`BINARY_MULTIPLY`**: Multiply the top two values on the stack (which are `a` and `a`), and push the result back onto the stack. 5. **`BINARY_ADD`**: Add the top two values on the stack (which are `b` and `a * a`), and push the result back onto the stack. 6. **`RETURN_VALUE`**: Return the value on the top of the stack. This bytecode essentially computes the expression `b + a * a`. Now, let's write this as a Python function called `foo`:
1 2 | def foo(a, b): return b + a * a |
I extracted the following code from that output:
1 2 | def foo(a, b): return b + a * a |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 | def foo(a, b): return b + a * a answer = foo(5, 7) expected = 5+7*5 assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' print('All tests passed') |
Traceback (most recent call last):
File "/usr/src/app/main.py", line 11, in <module>
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
^^^^^^^^^^^^^^^^^^
AssertionError: Wrong answer; got 32 instead of 40
Testing if the previous output contains the string All tests passed
: False