Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Here's the disassembled Python code transformed into a function called `foo`: 

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def foo(a, b):
    return a + b * a
Explanation: 1. The function takes two parameters, `a` and `b`, corresponding to the `LOAD_FAST` instructions at indices 0 and 1. 2. The first `LOAD_FAST` instruction at index 0 loads the value of `a` onto the stack. 3. The second `LOAD_FAST` instruction at index 1 loads the value of `b` onto the stack. 4. The third `LOAD_FAST` instruction at index 0 loads the value of `a` onto the stack again. 5. The `BINARY_MULTIPLY` instruction multiplies the top two values on the stack, which are `b` and `a`, and pushes the result back onto the stack. 6. The `BINARY_ADD` instruction adds the top two values on the stack, which are `a` (from the first `LOAD_FAST`) and the result of `b * a` (from the `BINARY_MULTIPLY`), and pushes the sum back onto the stack. 7. Finally, the `RETURN_VALUE` instruction returns the value at the top of the stack, which is the result of `a + b * a`. So, the function `foo` takes two parameters `a` and `b`, multiplies `b` by `a`, adds the result to `a`, and returns the final value.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Here's the disassembled Python code as a function called `foo`: 

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def foo(a, b):
    return a + b * a
Explanation: - The function takes two parameters: `a` and `b`. - The first instruction (`LOAD_FAST 0 (a)`) loads the value of `a` onto the stack. - The second instruction (`LOAD_FAST 1 (b)`) loads the value of `b` onto the stack. - The third instruction (`LOAD_FAST 0 (a)`) loads the value of `a` onto the stack again. - The fourth instruction (`BINARY_MULTIPLY`) multiplies the top two values on the stack (`b` and `a`), and replaces them with the result (`b * a`). - The fifth instruction (`BINARY_ADD`) adds the top two values on the stack (`a` and `b * a`), and replaces them with the result (`a + b * a`). - Finally, the `RETURN_VALUE` instruction returns the value at the top of the stack, which is `a + b * a`. So, the function `foo` takes two parameters `a` and `b`, and returns the result of `a + b * a`.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Here's the disassembled code turned into a Python function called `foo`: 

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def foo(a, b):
    return a + b * a
Explanation: - The function takes two arguments, `a` and `b`, as indicated by the `LOAD_FAST` instructions. - The `LOAD_FAST` instruction loads the value of a local variable onto the stack. - The `BINARY_MULTIPLY` instruction multiplies the top two values on the stack (`b` and `a`) and pushes the result back onto the stack. - The `BINARY_ADD` instruction adds the top two values on the stack (`a` and the result of `b * a`) and pushes the result back onto the stack. - Finally, the `RETURN_VALUE` instruction returns the value at the top of the stack, which is the result of the expression `a + b * a`. So, the function `foo` takes two arguments `a` and `b`, and returns the value of `a + b * a`.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Here's the disassembled Python code converted into a function called `foo`: 

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def foo(a, b):
    return a + b * a
Explanation: The disassembled code represents the following operations: 1. `LOAD_FAST 0 (a)`: Load the value of the local variable `a` onto the stack. 2. `LOAD_FAST 1 (b)`: Load the value of the local variable `b` onto the stack. 3. `LOAD_FAST 0 (a)`: Load the value of the local variable `a` onto the stack again. 4. `BINARY_MULTIPLY`: Multiply the top two values on the stack (`b` and `a`), and push the result back onto the stack. 5. `BINARY_ADD`: Add the top two values on the stack (`a` and the result of `b * a`), and push the result back onto the stack. 6. `RETURN_VALUE`: Return the value at the top of the stack, which is the result of `a + b * a`. The function `foo` takes two parameters, `a` and `b`, and returns the result of the expression `a + b * a`.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Here's the disassembled Python code turned into a function called `foo`: 

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def foo(a, b):
    return a + b * a
Explanation: 1. The disassembled code takes two arguments, `a` and `b`, which are loaded onto the stack using `LOAD_FAST` instructions. 2. The `BINARY_MULTIPLY` instruction multiplies the values of `b` and `a` (in that order) and pushes the result onto the stack. 3. The `BINARY_ADD` instruction adds the value of `a` (loaded earlier) with the result of `b * a` from the previous step. 4. Finally, the `RETURN_VALUE` instruction returns the result of the addition, which is equivalent to `a + b * a`. So, the disassembled code represents a function that takes two arguments `a` and `b`, multiplies `b` by `a`, and then adds `a` to the result, effectively calculating `a + b * a`.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True