Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

# Python Bytecode to Function Conversion Looking at the provided bytecode: 

1
2
3
4
5
6
56           0 LOAD_FAST                0 (a)
              2 LOAD_FAST                1 (b)
              4 LOAD_FAST                0 (a)
              6 BINARY_MULTIPLY
              8 BINARY_ADD
             10 RETURN_VALUE
Let me trace through the stack operations: 1. Load value of `a` onto stack: [a] 2. Load value of `b` onto stack: [a, b] 3. Load value of `a` onto stack again: [a, b, a] 4. BINARY_MULTIPLY: Pop top two values (b and a), multiply them, push result: [a, b*a] 5. BINARY_ADD: Pop top two values (a and b*a), add them, push result: [a + b*a] 6. RETURN_VALUE: Return top of stack This translates to the following Python function: 
1
2
def foo(a, b):
    return a + b * a
Since multiplication is commutative (a*b = b*a), this could also be written as: 
1
2
def foo(a, b):
    return a + a * b
Both implementations will produce the same result for all inputs.

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
def foo(a, b):
    return a + b * a




answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the disassembly, I can reconstruct the original Python function: 

1
2
def foo(a, b):
    return b + a * a
The bytecode shows: 1. Load parameter `a` onto the stack 2. Load parameter `b` onto the stack 3. Load parameter `a` again 4. Multiply the top two values (a * a) 5. Add the result to b 6. Return the final value So the function calculates `b + a * a` (or equivalently, b + a²).

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return b + a * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return b + a * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False