Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

This bytecode represents a simple Python function that performs multiplication and addition. Here's the equivalent Python function: 

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def foo(a, b):
    return b + (a * a)
Let's break down how I reconstructed this from the bytecode: 1. `LOAD_FAST 0 (a)` - Loads the first parameter 'a' 2. `LOAD_FAST 1 (b)` - Loads the second parameter 'b' 3. `LOAD_FAST 0 (a)` - Loads 'a' again 4. `BINARY_MULTIPLY` - Multiplies the two top values on the stack (a * a) 5. `BINARY_ADD` - Adds the multiplication result to b 6. `RETURN_VALUE` - Returns the final result So the function takes two parameters (a and b) and returns b + (a * a).

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return b + (a * a)

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return b + (a * a)





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the bytecode, here's the Python function `foo`: 

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def foo(a, b):
    return b + (a * a)
Let's break down how I reconstructed this from the bytecode: 1. `LOAD_FAST 0 (a)` - Loads the first parameter 'a' 2. `LOAD_FAST 1 (b)` - Loads the second parameter 'b' 3. `LOAD_FAST 0 (a)` - Loads 'a' again 4. `BINARY_MULTIPLY` - Multiplies the two top stack values (a * a) 5. `BINARY_ADD` - Adds the results (b + (a * a)) 6. `RETURN_VALUE` - Returns the result The function takes two parameters 'a' and 'b', and returns b plus a squared (a * a). You can verify this by running: 
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def foo(a, b):
    return b + (a * a)

import dis
dis.dis(foo)
This should produce the same bytecode as shown in your question.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return b + (a * a)

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return b + (a * a)





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

This bytecode corresponds to a Python function that takes two parameters (a and b) and performs multiplication and addition. Here's the reconstructed function: 

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def foo(a, b):
    return b + (a * a)
The bytecode operations indicate that: 1. It loads parameter 'a' twice and parameter 'b' once 2. Multiplies a by a (a * a) 3. Adds b to the result of (a * a) 4. Returns the final value So the function takes two inputs a and b, and returns b + (a * a).

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return b + (a * a)

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return b + (a * a)





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Looking at the bytecode, this function takes two parameters (a and b) and performs operations. The function would look like this: 

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def foo(a, b):
    return b + (a * a)
Let's break down how I got this from the bytecode: 1. `LOAD_FAST 0 (a)` - Loads the first parameter 'a' 2. `LOAD_FAST 1 (b)` - Loads the second parameter 'b' 3. `LOAD_FAST 0 (a)` - Loads 'a' again 4. `BINARY_MULTIPLY` - Multiplies the two top stack values (a * a) 5. `BINARY_ADD` - Adds the results of (a * a) with b 6. `RETURN_VALUE` - Returns the final result So the function takes two parameters and returns b + (a * a). You can verify this is correct by disassembling the function: 
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import dis
dis.dis(foo)

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return b + (a * a)

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return b + (a * a)





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

This bytecode can be assembled into the following Python function: 

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def foo(a, b):
    return b + (a * a)
Let's break down how I converted the bytecode: 1. From the bytecode, we can see there are two parameters being loaded (`a` and `b`), so the function takes two parameters. 2. The operations happen in this order: * `LOAD_FAST 0` loads parameter `a` * `LOAD_FAST 1` loads parameter `b` * `LOAD_FAST 0` loads parameter `a` again * `BINARY_MULTIPLY` multiplies the two most recent values (a * a) * `BINARY_ADD` adds the earlier loaded `b` with the result of (a * a) * `RETURN_VALUE` returns the final result 3. When written as a mathematical expression, this becomes: `b + (a * a)` You can verify this is correct by disassembling the function: 
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import dis
dis.dis(foo)
This should produce the same bytecode as shown in your original question.

Extract Code

I extracted the following code from that output: 

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def foo(a, b):
    return b + (a * a)

Run Code Interpreter

Running the following program: 

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def foo(a, b):
    return b + (a * a)





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False