Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the provided bytecode, I can reconstruct the Python function `foo` as follows: 

1
2
def foo(a, b):
    return b + a * a
Let's break down how this function corresponds to the given bytecode: 1. `LOAD_FAST 0 (a)`: Loads the first argument `a` 2. `LOAD_FAST 1 (b)`: Loads the second argument `b` 3. `LOAD_FAST 0 (a)`: Loads the first argument `a` again 4. `BINARY_MULTIPLY`: Multiplies the two top items on the stack (a * a) 5. `BINARY_ADD`: Adds the result of (a * a) to b 6. `RETURN_VALUE`: Returns the result of the addition The function takes two parameters, `a` and `b`, multiplies `a` by itself, adds the result to `b`, and returns this sum. This function essentially computes the expression `b + a * a`.

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return b + a * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return b + a * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the provided bytecode, I can reconstruct the Python function `foo` as follows: 

1
2
def foo(a, b):
    return b + a * a
Let's break down how this function corresponds to the given bytecode: 1. `LOAD_FAST 0 (a)`: Loads the first argument `a` 2. `LOAD_FAST 1 (b)`: Loads the second argument `b` 3. `LOAD_FAST 0 (a)`: Loads the first argument `a` again 4. `BINARY_MULTIPLY`: Multiplies the two top values on the stack (a * a) 5. `BINARY_ADD`: Adds the two top values on the stack (b + (a * a)) 6. `RETURN_VALUE`: Returns the result of the addition The function takes two parameters, `a` and `b`. It multiplies `a` by itself (a * a), then adds `b` to the result, and finally returns this sum. This function is equivalent to the mathematical expression: b + a²

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return b + a * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return b + a * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the provided bytecode, I can reconstruct a Python function called `foo` that would generate this bytecode. Here's the function: 

1
2
def foo(a, b):
    return b + a * a
Let's break down how this function corresponds to the given bytecode: 1. `LOAD_FAST 0 (a)`: Loads the first argument `a` 2. `LOAD_FAST 1 (b)`: Loads the second argument `b` 3. `LOAD_FAST 0 (a)`: Loads the first argument `a` again 4. `BINARY_MULTIPLY`: Multiplies the two top items on the stack (a * a) 5. `BINARY_ADD`: Adds the result of (a * a) to b 6. `RETURN_VALUE`: Returns the result of the addition The function takes two parameters, `a` and `b`, multiplies `a` by itself, adds the result to `b`, and then returns this sum. This matches exactly with the operations described in the bytecode.

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return b + a * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return b + a * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the provided bytecode, I can reconstruct a Python function called `foo` that would generate this bytecode. Here's the function: 

1
2
def foo(a, b):
    return b + a * a
Let's break down how this function corresponds to the bytecode: 1. `LOAD_FAST 0 (a)`: Loads the first argument `a`. 2. `LOAD_FAST 1 (b)`: Loads the second argument `b`. 3. `LOAD_FAST 0 (a)`: Loads the first argument `a` again. 4. `BINARY_MULTIPLY`: Multiplies the two top items on the stack (a * a). 5. `BINARY_ADD`: Adds the result of (a * a) to b. 6. `RETURN_VALUE`: Returns the result of the addition. This function takes two parameters, `a` and `b`, multiplies `a` by itself, adds the result to `b`, and returns this sum. The operation performed is equivalent to the mathematical expression b + a².

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return b + a * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return b + a * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the provided bytecode, I can reconstruct a Python function called `foo` that would produce this bytecode. Here's the disassembled function: 

1
2
def foo(a, b):
    return b + a * a
Let's break down how this function corresponds to the given bytecode: 1. `LOAD_FAST 0 (a)`: Loads the first argument `a` 2. `LOAD_FAST 1 (b)`: Loads the second argument `b` 3. `LOAD_FAST 0 (a)`: Loads the first argument `a` again 4. `BINARY_MULTIPLY`: Multiplies the two top items on the stack (a * a) 5. `BINARY_ADD`: Adds the result of (a * a) to b 6. `RETURN_VALUE`: Returns the result of the addition The function takes two parameters, `a` and `b`, multiplies `a` by itself, adds the result to `b`, and then returns this sum. This exactly matches the operations described in the bytecode. You can verify this by using the `dis` module in Python to disassemble the function: 
1
2
3
4
5
6
import dis

def foo(a, b):
    return b + a * a

dis.dis(foo)
This should produce bytecode very similar to what you provided in your question.

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return b + a * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return b + a * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' AssertionError: Wrong answer; got 32 instead of 40

Substring Evaluation

Testing if the previous output contains the string All tests passed: False