Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Here's the Python function equivalent of the given bytecode: 

1
2
def foo(a, b):
    return a + b * a
This function takes two parameters `a` and `b`, multiplies `b` by `a`, and then adds the result back to `a`. The bytecode breakdown: - `LOAD_FAST 0 (a)` loads the first parameter `a` - `LOAD_FAST 1 (b)` loads the second parameter `b` - `LOAD_FAST 0 (a)` loads `a` again - `BINARY_MULTIPLY` multiplies `b` by `a` - `BINARY_ADD` adds the result to `a` - `RETURN_VALUE` returns the final result So, for example: 
1
result = foo(3, 4)  # Would return 3 + (4 * 3) = 15

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Here's a Python function equivalent to the given bytecode disassembly: 

1
2
def foo(a, b):
    return a + b * a
This function: 1. Takes two parameters `a` and `b` 2. Multiplies `b` by `a` 3. Adds the result to `a` 4. Returns the final value The bytecode shows the sequence of operations: - `LOAD_FAST 0 (a)`: Load the first parameter `a` - `LOAD_FAST 1 (b)`: Load the second parameter `b` - `LOAD_FAST 0 (a)`: Load `a` again - `BINARY_MULTIPLY`: Multiply `b` by `a` - `BINARY_ADD`: Add the result to `a` - `RETURN_VALUE`: Return the final result

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Based on the Python bytecode, here's a possible implementation of the function `foo`: 

1
2
def foo(a, b):
    return a + b * a
This function takes two parameters `a` and `b`, and returns the result of `a + (b * a)`. The bytecode shows: - Load `a` first (LOAD_FAST 0) - Load `b` second (LOAD_FAST 1) - Load `a` again (LOAD_FAST 0) - Multiply `b` and `a` (BINARY_MULTIPLY) - Add the result to `a` (BINARY_ADD) - Return the result (RETURN_VALUE) The corresponding Python code matches this sequence of operations precisely.

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Here's the Python function that corresponds to the given bytecode disassembly: 

1
2
def foo(a, b):
    return a + b * a
This function takes two parameters `a` and `b`, multiplies `b` by `a`, and then adds the result to `a`. The bytecode shows the sequence of operations: 1. Load `a` 2. Load `b` 3. Load `a` again 4. Multiply `b` and `a` 5. Add the result to `a` 6. Return the final value The function follows the exact sequence of operations shown in the bytecode disassembly.

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

LLM Generation

Query

Disassemble the following python into a function called foo: 56 0 LOAD_FAST 0 (a) 2 LOAD_FAST 1 (b) 4 LOAD_FAST 0 (a) 6 BINARY_MULTIPLY 8 BINARY_ADD 10 RETURN_VALUE

Output

Here's the Python function equivalent of the given bytecode: 

1
2
def foo(a, b):
    return a + b * a
This function takes two parameters `a` and `b`, multiplies `b` by `a`, and then adds `a` to the result. The bytecode instructions correspond to these operations: - `LOAD_FAST 0 (a)` - Load the first parameter `a` - `LOAD_FAST 1 (b)` - Load the second parameter `b` - `LOAD_FAST 0 (a)` - Load `a` again - `BINARY_MULTIPLY` - Multiply `b` and `a` - `BINARY_ADD` - Add the result to `a` - `RETURN_VALUE` - Return the final result So, for example: 
1
result = foo(3, 4)  # This would return 15 (3 + 4 * 3)

Extract Code

I extracted the following code from that output: 

1
2
def foo(a, b):
    return a + b * a

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(a, b):
    return a + b * a





answer = foo(5, 7)
expected = 5+7*5
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True