Initial Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

LLM Generation

Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

Output

Here's the equivalent C code for the provided Python program: 

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#include <stdio.h>
#include <math.h>

// Function to calculate the square root using the Babylonian method
float my_sqrt(float number, float precision) {
    float guess = number / 2;

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;
    }

    return guess;
}

int main() {
    float number = 25.0;
    float precision = 0.0001;

    printf("Square root of %.2f with a precision of %.4f is: %.4f\n", number, precision, my_sqrt(number, precision));

    return 0;
}
Note that in C, the `fabs()` function from the `math.h` library is used instead of Python's built-in `abs()` function to calculate the absolute value of a floating-point number.

Extract Code

I extracted the following code from that output: 

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#include <stdio.h>
#include <math.h>

// Function to calculate the square root using the Babylonian method
float my_sqrt(float number, float precision) {
    float guess = number / 2;

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;
    }

    return guess;
}

int main() {
    float number = 25.0;
    float precision = 0.0001;

    printf("Square root of %.2f with a precision of %.4f is: %.4f\n", number, precision, my_sqrt(number, precision));

    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <stdio.h>
#include <math.h>

// Function to calculate the square root using the Babylonian method
float my_sqrt(float number, float precision) {
    float guess = number / 2;

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;
    }

    return guess;
}

int __delete_this__main() {
    float number = 25.0;
    float precision = 0.0001;

    printf("Square root of %.2f with a precision of %.4f is: %.4f\n", number, precision, my_sqrt(number, precision));

    return 0;
}



#include<stdio.h>
#include<stdlib.h>
int main() {


int answer = (int)(my_sqrt(12345, .001)*10);
int expected = 1111;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

LLM Generation

Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

Output

Here's a possible C implementation of the provided Python code. The function `my_sqrt` takes in a floating-point number and a precision value, and returns the square root of the number using the Babylonian method. 

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#include <stdio.h>
#include <math.h>

// Function to compute the square root of a number using the Babylonian method
float my_sqrt(float number, float precision) {
    float guess = number / 2.0; // Start with an initial guess

    // Improve the guess using the Babylonian method
    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2.0;
    }

    return guess;
}

int main() {
    float number = 25.0;
    float precision = 0.0001;
    float result = my_sqrt(number, precision);
    printf("Square root of %.2f with precision %.4f is %.4f\n", number, precision, result);
    return 0;
}
Note that the `fabs` function from the `math.h` header is used to compute the absolute value of a floating-point number. The `printf` format specifiers are also adjusted to display the desired number of decimal places.

Extract Code

I extracted the following code from that output: 

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#include <stdio.h>
#include <math.h>

// Function to compute the square root of a number using the Babylonian method
float my_sqrt(float number, float precision) {
    float guess = number / 2.0; // Start with an initial guess

    // Improve the guess using the Babylonian method
    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2.0;
    }

    return guess;
}

int main() {
    float number = 25.0;
    float precision = 0.0001;
    float result = my_sqrt(number, precision);
    printf("Square root of %.2f with precision %.4f is %.4f\n", number, precision, result);
    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <stdio.h>
#include <math.h>

// Function to compute the square root of a number using the Babylonian method
float my_sqrt(float number, float precision) {
    float guess = number / 2.0; // Start with an initial guess

    // Improve the guess using the Babylonian method
    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2.0;
    }

    return guess;
}

int __delete_this__main() {
    float number = 25.0;
    float precision = 0.0001;
    float result = my_sqrt(number, precision);
    printf("Square root of %.2f with precision %.4f is %.4f\n", number, precision, result);
    return 0;
}



#include<stdio.h>
#include<stdlib.h>
int main() {


int answer = (int)(my_sqrt(12345, .001)*10);
int expected = 1111;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

LLM Generation

Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

Output

Here's a possible C implementation of the same function: 

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#include <stdio.h>
#include <math.h>

float my_sqrt(float number, float precision) {
    float guess = number / 2;  // Start with an initial guess

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;  // Improve the guess using the Babylonian method
    }

    return guess;
}

int main() {
    float number = 25.0;
    float precision = 0.0001;
    float result = my_sqrt(number, precision);
    printf("Square root of %.2f is approximately %.4f\n", number, result);
    return 0;
}
Note that the `fabs` function from the `math.h` header is used to compute the absolute value of a floating-point number, and the `printf` function is used to print the result with a specified format. Also, the type signature of the function is changed to `float my_sqrt(float, float)` as requested.

Extract Code

I extracted the following code from that output: 

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#include <stdio.h>
#include <math.h>

float my_sqrt(float number, float precision) {
    float guess = number / 2;  // Start with an initial guess

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;  // Improve the guess using the Babylonian method
    }

    return guess;
}

int main() {
    float number = 25.0;
    float precision = 0.0001;
    float result = my_sqrt(number, precision);
    printf("Square root of %.2f is approximately %.4f\n", number, result);
    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <stdio.h>
#include <math.h>

float my_sqrt(float number, float precision) {
    float guess = number / 2;  // Start with an initial guess

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;  // Improve the guess using the Babylonian method
    }

    return guess;
}

int __delete_this__main() {
    float number = 25.0;
    float precision = 0.0001;
    float result = my_sqrt(number, precision);
    printf("Square root of %.2f is approximately %.4f\n", number, result);
    return 0;
}



#include<stdio.h>
#include<stdlib.h>
int main() {


int answer = (int)(my_sqrt(12345, .001)*10);
int expected = 1111;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

LLM Generation

Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

Output

Here is the equivalent C code for the given Python program: 

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#include <stdio.h>
#include <math.h>

float my_sqrt(float number, float precision) {
    float guess = number / 2;

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;
    }

    return guess;
}

int main() {
    float number = 25.0;
    float precision = 0.0001;

    float result = my_sqrt(number, precision);
    printf("The square root of %.2f with a precision of %.4f is: %.4f\n", number, precision, result);

    return 0;
}
In this C code, the `my_sqrt` function takes two floating-point arguments: `number` and `precision`. The `guess` variable holds the initial estimate of the square root, and the while loop iterates until the square of the guess is close enough to the input number (within a certain precision). The Babylonian method is used to improve the guess with each iteration. Note that I have included the `<math.h>` header to use the `fabs()` function for floating-point absolute values. Also, the `main()` function demonstrates how to use the `my_sqrt()` function to compute the square root of a number with a given precision.

Extract Code

I extracted the following code from that output: 

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#include <stdio.h>
#include <math.h>

float my_sqrt(float number, float precision) {
    float guess = number / 2;

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;
    }

    return guess;
}

int main() {
    float number = 25.0;
    float precision = 0.0001;

    float result = my_sqrt(number, precision);
    printf("The square root of %.2f with a precision of %.4f is: %.4f\n", number, precision, result);

    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <stdio.h>
#include <math.h>

float my_sqrt(float number, float precision) {
    float guess = number / 2;

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;
    }

    return guess;
}

int __delete_this__main() {
    float number = 25.0;
    float precision = 0.0001;

    float result = my_sqrt(number, precision);
    printf("The square root of %.2f with a precision of %.4f is: %.4f\n", number, precision, result);

    return 0;
}



#include<stdio.h>
#include<stdlib.h>
int main() {


int answer = (int)(my_sqrt(12345, .001)*10);
int expected = 1111;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

LLM Generation

Query

Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess

Output

Here's the equivalent C code for the provided Python function: 

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#include <stdio.h>
#include <math.h>

float my_sqrt(float number, float precision) {
    float guess = number / 2;  // Start with an initial guess

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;  // Improve the guess using the Babylonian method
    }

    return guess;
}

int main() {
    float input_number = 25.0f;
    float input_precision = 0.0001f;
    float result = my_sqrt(input_number, input_precision);
    printf("Square root of %.2f with a precision of %.4f is: %.4f\n", input_number, input_precision, result);
    return 0;
}
This C code defines a function `my_sqrt` with the type signature `float my_sqrt(float, float)` that calculates the square root of a number using the Babylonian method. The `fabs` function is used instead of the Python `abs` function to get the absolute value of a floating-point number. The `main` function demonstrates how to use the `my_sqrt` function with sample inputs.

Extract Code

I extracted the following code from that output: 

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#include <stdio.h>
#include <math.h>

float my_sqrt(float number, float precision) {
    float guess = number / 2;  // Start with an initial guess

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;  // Improve the guess using the Babylonian method
    }

    return guess;
}

int main() {
    float input_number = 25.0f;
    float input_precision = 0.0001f;
    float result = my_sqrt(input_number, input_precision);
    printf("Square root of %.2f with a precision of %.4f is: %.4f\n", input_number, input_precision, result);
    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <stdio.h>
#include <math.h>

float my_sqrt(float number, float precision) {
    float guess = number / 2;  // Start with an initial guess

    while (fabs(guess * guess - number) >= precision) {
        guess = (guess + number / guess) / 2;  // Improve the guess using the Babylonian method
    }

    return guess;
}

int __delete_this__main() {
    float input_number = 25.0f;
    float input_precision = 0.0001f;
    float result = my_sqrt(input_number, input_precision);
    printf("Square root of %.2f with a precision of %.4f is: %.4f\n", input_number, input_precision, result);
    return 0;
}



#include<stdio.h>
#include<stdlib.h>
int main() {


int answer = (int)(my_sqrt(12345, .001)*10);
int expected = 1111;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True