Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { float num, prec, result; printf("Enter the number: "); scanf("%f", &num); printf("Enter the precision: "); scanf("%f", &prec); result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.6f\n", num, result); return 0; } |
1 2 | gcc my_sqrt.c -o my_sqrt -lm // -lm links the math library |
1 2 | ./my_sqrt |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; } return guess; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; } return guess; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage: float num = 16.0f; float prec = 0.0001f; float result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); num = 2.0f; result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); num = 0.0f; // Test with 0 result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); //Note: Handling negative inputs is important for a robust sqrt function. //For real square roots, negative inputs are invalid. Here's how to handle it: num = -16.0f; if (num < 0) { printf("Cannot calculate the square root of a negative number.\n"); // return 1; // Indicate an error. You could also return NaN (Not a Number) // if your environment supports it. } else { result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); } return 0; } |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage: float num = 16.0f; float prec = 0.0001f; float result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); num = 2.0f; result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); num = 0.0f; // Test with 0 result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); //Note: Handling negative inputs is important for a robust sqrt function. //For real square roots, negative inputs are invalid. Here's how to handle it: num = -16.0f; if (num < 0) { printf("Cannot calculate the square root of a negative number.\n"); // return 1; // Indicate an error. You could also return NaN (Not a Number) // if your environment supports it. } else { result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); } return 0; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int __delete_this__main() { // Example usage: float num = 16.0f; float prec = 0.0001f; float result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); num = 2.0f; result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); num = 0.0f; // Test with 0 result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); //Note: Handling negative inputs is important for a robust sqrt function. //For real square roots, negative inputs are invalid. Here's how to handle it: num = -16.0f; if (num < 0) { printf("Cannot calculate the square root of a negative number.\n"); // return 1; // Indicate an error. You could also return NaN (Not a Number) // if your environment supports it. } else { result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.4f\n", num, result); } return 0; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 | #include <stdio.h> #include <math.h> // For fabs() float my_sqrt(float number, float precision) { if (number < 0) { return -1.0f; // Indicate an error for negative input (could also use NAN) } if(number == 0) { return 0.0f; // Handle the 0 case directly } float guess = number / 2.0f; while (fabs(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; } return guess; } int main() { float num, prec; printf("Enter a number: "); scanf("%f", &num); printf("Enter the desired precision: "); scanf("%f", &prec); float result = my_sqrt(num, prec); if (result < 0) { printf("Cannot calculate square root of a negative number.\n"); } else { printf("The square root of %.2f is approximately %.6f\n", num, result); } // Test cases (optional) you can uncomment these to test the function: //printf("sqrt(2) = %.6f\n", my_sqrt(2.0f, 0.0001f)); //printf("sqrt(9) = %.6f\n", my_sqrt(9.0f, 0.0001f)); //printf("sqrt(0) = %.6f\n", my_sqrt(0.0f, 0.0001f)); return 0; } |
1 2 | gcc my_sqrt.c -o my_sqrt -lm // -lm links the math library |
1 2 | ./my_sqrt |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | #include <stdio.h> #include <math.h> // For fabs() float my_sqrt(float number, float precision) { if (number < 0) { return -1.0f; // Indicate an error for negative input (could also use NAN) } if(number == 0) { return 0.0f; // Handle the 0 case directly } float guess = number / 2.0f; while (fabs(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; } return guess; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 | #include <stdio.h> #include <math.h> // For fabs() float my_sqrt(float number, float precision) { if (number < 0) { return -1.0f; // Indicate an error for negative input (could also use NAN) } if(number == 0) { return 0.0f; // Handle the 0 case directly } float guess = number / 2.0f; while (fabs(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; } return guess; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage: float num = 16.0f; float prec = 0.0001f; float result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.6f\n", num, result); // Test with a negative number (should handle gracefully due to fabsf) num = -9.0f; result = my_sqrt(num, prec); // Result will be NaN (Not a Number) printf("The square root of %.2f is approximately %.6f\n", num, result); // Will print NaN // Test with zero num = 0.0f; result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.6f\n", num, result); // Will print 0 return 0; } |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage: float num = 16.0f; float prec = 0.0001f; float result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.6f\n", num, result); // Test with a negative number (should handle gracefully due to fabsf) num = -9.0f; result = my_sqrt(num, prec); // Result will be NaN (Not a Number) printf("The square root of %.2f is approximately %.6f\n", num, result); // Will print NaN // Test with zero num = 0.0f; result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.6f\n", num, result); // Will print 0 return 0; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int __delete_this__main() { // Example usage: float num = 16.0f; float prec = 0.0001f; float result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.6f\n", num, result); // Test with a negative number (should handle gracefully due to fabsf) num = -9.0f; result = my_sqrt(num, prec); // Result will be NaN (Not a Number) printf("The square root of %.2f is approximately %.6f\n", num, result); // Will print NaN // Test with zero num = 0.0f; result = my_sqrt(num, prec); printf("The square root of %.2f is approximately %.6f\n", num, result); // Will print 0 return 0; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage: float num = 16.0f; float precision = 0.0001f; float result = my_sqrt(num, precision); printf("Square root of %.2f is approximately %.4f\n", num, result); num = 2.0f; result = my_sqrt(num, precision); printf("Square root of %.2f is approximately %.4f\n", num, result); // Test with zero input: num = 0.0f; result = my_sqrt(num, precision); printf("Square root of %.2f is approximately %.4f\n", num, result); return 0; } |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage: float num = 16.0f; float precision = 0.0001f; float result = my_sqrt(num, precision); printf("Square root of %.2f is approximately %.4f\n", num, result); num = 2.0f; result = my_sqrt(num, precision); printf("Square root of %.2f is approximately %.4f\n", num, result); // Test with zero input: num = 0.0f; result = my_sqrt(num, precision); printf("Square root of %.2f is approximately %.4f\n", num, result); return 0; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int __delete_this__main() { // Example usage: float num = 16.0f; float precision = 0.0001f; float result = my_sqrt(num, precision); printf("Square root of %.2f is approximately %.4f\n", num, result); num = 2.0f; result = my_sqrt(num, precision); printf("Square root of %.2f is approximately %.4f\n", num, result); // Test with zero input: num = 0.0f; result = my_sqrt(num, precision); printf("Square root of %.2f is approximately %.4f\n", num, result); return 0; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True