Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Certainly! Here's the equivalent C program with the function signature `float my_sqrt(float, float)`:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int __delete_this__main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's the equivalent C program with the function signature `float my_sqrt(float, float)`:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } // Example usage int main() { float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } // Example usage int main() { float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } // Example usage int __delete_this__main() { float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Certainly! Here's the equivalent C program with the function signature `float my_sqrt(float, float)`:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %f with precision %f is approximately %f\n", number, precision, result); return 0; } |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %f with precision %f is approximately %f\n", number, precision, result); return 0; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int __delete_this__main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %f with precision %f is approximately %f\n", number, precision, result); return 0; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Certainly! Here's the equivalent C program with the function signature `float my_sqrt(float, float)`:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int __delete_this__main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Here's a python program. Please rewrite it in c with the type signature float my_sqrt(float, float). def my_sqrt(number, precision=0.0001): guess = number / 2 # Start with an initial guess while abs(guess * guess - number) >= precision: guess = (guess + number / guess) / 2 # Improve the guess using the Babylonian method return guess
Certainly! Here's the equivalent C program with the function signature `float my_sqrt(float, float)`:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 | #include <stdio.h> #include <math.h> float my_sqrt(float number, float precision) { float guess = number / 2.0f; // Start with an initial guess while (fabsf(guess * guess - number) >= precision) { guess = (guess + number / guess) / 2.0f; // Improve the guess using the Babylonian method } return guess; } int __delete_this__main() { // Example usage float number = 16.0f; float precision = 0.0001f; float result = my_sqrt(number, precision); printf("Square root of %.2f (with precision %.6f) is approximately %.6f\n", number, precision, result); return 0; } #include<stdio.h> #include<stdlib.h> int main() { int answer = (int)(my_sqrt(12345, .001)*10); int expected = 1111; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True