What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
The expression `-~++*x--` evaluates to `*x`.
Below is a student's answer to a question about what a particular C expression evaluates to: The expression `-~++*x--` evaluates to `*x`. Does the student's final answer say that the expression evaluates to *x+2? Ignore their reasoning. Just look at the final answer, if they say **EXPLICITLY** that the answer is *x+2. Giving something that's equal but more complicated is wrong. If the answer is correct say "The student passes" otherwise "The student fails".
The student fails.
Testing if the previous output contains the string student passes
: False
What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
The expression `-~++*x--` evaluates to `x` in its simplest form.
Below is a student's answer to a question about what a particular C expression evaluates to: The expression `-~++*x--` evaluates to `x` in its simplest form. Does the student's final answer say that the expression evaluates to *x+2? Ignore their reasoning. Just look at the final answer, if they say **EXPLICITLY** that the answer is *x+2. Giving something that's equal but more complicated is wrong. If the answer is correct say "The student passes" otherwise "The student fails".
The student fails.
Testing if the previous output contains the string student passes
: False
What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
`-~++*x--` can be simplified as follows: 1. `*x--` - Dereference the value of `x` and then decrement `x`. 2. `++*x--` - Increment the dereferenced value of `x`. 3. `-~++*x--` - One's complement of the result of the previous step. Therefore, in simplest form, `-~++*x--` evaluates to `-*x-- + 1`.
Below is a student's answer to a question about what a particular C expression evaluates to: `-~++*x--` can be simplified as follows: 1. `*x--` - Dereference the value of `x` and then decrement `x`. 2. `++*x--` - Increment the dereferenced value of `x`. 3. `-~++*x--` - One's complement of the result of the previous step. Therefore, in simplest form, `-~++*x--` evaluates to `-*x-- + 1`. Does the student's final answer say that the expression evaluates to *x+2? Ignore their reasoning. Just look at the final answer, if they say **EXPLICITLY** that the answer is *x+2. Giving something that's equal but more complicated is wrong. If the answer is correct say "The student passes" otherwise "The student fails".
The student fails.
Testing if the previous output contains the string student passes
: False
What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
The expression `-~++*x--` can be broken down as follows: 1. `*x`: Dereference the pointer `x`, which means we are accessing the value that `x` points to. 2. `++*x`: Increment the value that `x` points to. 3. `-~++*x`: Increment the result of `++*x` and then negate it. So, in simplest form, the expression `-~++*x--` evaluates to `-(1 + (++*x))`.
Below is a student's answer to a question about what a particular C expression evaluates to: The expression `-~++*x--` can be broken down as follows: 1. `*x`: Dereference the pointer `x`, which means we are accessing the value that `x` points to. 2. `++*x`: Increment the value that `x` points to. 3. `-~++*x`: Increment the result of `++*x` and then negate it. So, in simplest form, the expression `-~++*x--` evaluates to `-(1 + (++*x))`. Does the student's final answer say that the expression evaluates to *x+2? Ignore their reasoning. Just look at the final answer, if they say **EXPLICITLY** that the answer is *x+2. Giving something that's equal but more complicated is wrong. If the answer is correct say "The student passes" otherwise "The student fails".
The student fails.
Testing if the previous output contains the string student passes
: False
What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
What does the c expression `-~++*x--` evaluate to in simplest form? Ignore side effects.
The expression `-~++*x--` evaluates to `x`.
Below is a student's answer to a question about what a particular C expression evaluates to: The expression `-~++*x--` evaluates to `x`. Does the student's final answer say that the expression evaluates to *x+2? Ignore their reasoning. Just look at the final answer, if they say **EXPLICITLY** that the answer is *x+2. Giving something that's equal but more complicated is wrong. If the answer is correct say "The student passes" otherwise "The student fails".
The student fails.
Testing if the previous output contains the string student passes
: False