Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

Output

You can use the `ls` command with the `-S` option to sort by file size, and then pipe the output to `awk` to extract the least significant digit of the size and sort again based on that digit. Finally, you can use `cut` to extract only the file names. Here's an example:

ls -S foo/ | awk '{print substr($5, length($5), 1)}' | sort -n | awk 'BEGIN{FS="[ /]"}{print $NF}'

Explanation: 1. `ls -S foo/`: List all files in the `foo/` directory and sort them by size. 2. `| awk '{print substr($5, length($5), 1)}'`: Extract the least significant digit of the size by using `awk` to print the last character of the fifth field (`$5`), which is the size. 3. `| sort -n`: Sort the output numerically based on the least significant digit of the size. 4. `| awk 'BEGIN{FS="[ /]"}{print $NF}'`: Extract only the file names by using `awk` to set the field separator to a space or a slash (`FS="[ /]"`), and then print the last field (`$NF`), which is the file name. Note that the `awk` commands can be combined into a single command to make the command shorter and more efficient:

ls -S foo/ | awk '{print substr($5, length($5), 1)}' | sort -n | awk -F'[ /]' '{print $NF}'

Or even:

ls -S foo/ | awk '{print substr($5, length($5), 1)}' | sort -n | awk -F'[ /]' '{print $NF}' | cut -d' ' -f2-

This last command uses `cut` to remove the first field (the size) from the output of the second `awk` command.

Extract Code

I extracted the following code from that output:

#!/bin/bash

# List all files in the foo/ directory and sort them by size
# Then extract the least significant digit of the size using awk
# Sort the output numerically based on the least significant digit of the size
# Extract only the file names using awk and set the field separator to a space or a slash
ls -S foo/ | awk '{print substr($5, length($5), 1)}' | sort -n | awk -F'[ /]' '{print $NF}'

Run Code Interpreter

Running the following program:

#!/bin/bash

# List all files in the foo/ directory and sort them by size
# Then extract the least significant digit of the size using awk
# Sort the output numerically based on the least significant digit of the size
# Extract only the file names using awk and set the field separator to a space or a slash
ls -S foo/ | awk '{print substr($5, length($5), 1)}' | sort -n | awk -F'[ /]' '{print $NF}'

And got the output:

PyFunc

Resulting in output:

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

In bash, you can use the `ls` command with the `--sort` option to sort files by size. To sort files by the least significant digit of their size, you can pipe the output of `ls` to `awk` and `sort` commands and then use `cut` to remove unnecessary information. Here's an example:

ls -lR foo/ | awk '{print $5, $9}' | sort -nk1 | cut -d' ' -f2

Let me explain the command step by step: 1. `ls -lR foo/`: This lists all the files in the `foo/` directory and its subdirectories in a long format. The `-R` option is used to list files in subdirectories recursively. 2. `awk '{print $5, $9}'`: This uses the `awk` command to print the fifth and ninth columns of the output of the `ls` command. The fifth column contains the file size in bytes, and the ninth column contains the file name. We print both columns separated by a space. 3. `sort -nk1`: This sorts the output of the `awk` command numerically based on the first column (file size) using the `sort` command. 4. `cut -d' ' -f2`: This uses the `cut` command to remove the first column (file size) of the sorted output using a space as the delimiter. We only want the file name, so we print the second column (`-f2`). The final output will be a list of file names sorted by the least significant digit of their size.

Extract Code

I extracted the following code from that output:

ls -lR foo/ | awk '{print $5, $9}' | sort -nk1 | cut -d' ' -f2

Run Code Interpreter

Running the following program:

ls -lR foo/ | awk '{print $5, $9}' | sort -nk1 | cut -d' ' -f2

And got the output:

PyFunc

Resulting in output: 8 2 9 6 4 7 3 5 1 0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

You can use the `ls` command with the `-S` option to sort files by size, and then pipe the output to the `awk` command to extract the least significant digit of the size and sort by that value. Finally, use the `cut` command to extract only the file names. Here is the command:

ls -S foo/ | awk '{print $5}' | awk -F' ' '{print $1}' | awk '{print $NF}' | awk '{print substr($1, length($1), 1)}' | sort -n | awk 'NR==FNR{a[$1]=$0;next}!a[$1]++{print $0}' foo/

Explanation: 1. `ls -S foo/`: list all files in the `foo/` directory and sort them by size. 2. `awk '{print $5}'`: print the 5th field of the output (which is the size of the file). 3. `awk -F' ' '{print $1}'`: separate the fields by space and print the first field (which is the size of the file without the suffix). 4. `awk '{print $NF}'`: print the last field (which is the file name). 5. `awk '{print substr($1, length($1), 1)}'`: extract the least significant digit of the file size. 6. `sort -n`: sort the output numerically. 7. The final `awk` command uses an associative array to remove duplicate file names from the output. The `FNR` variable is used to iterate over the input files, and the `a` array is used to store the least significant digit of the file size as the key and the file name as the value. If the key already exists in the array, the file name is not printed. Otherwise, the file name is printed only once. Note: this command assumes that the file names do not contain any spaces. If they do, you may need to modify the `awk` commands to handle them properly.

Extract Code

I extracted the following code from that output:

ls -S foo/ | awk '{print $5}' | awk -F' ' '{print $1}' | awk '{print $NF}' | awk '{print substr($1, length($1), 1)}' | sort -n | awk 'NR==FNR{a[$1]=$0;next}!a[$1]++{print $0}' foo/

Run Code Interpreter

Running the following program:

ls -S foo/ | awk '{print $5}' | awk -F' ' '{print $1}' | awk '{print $NF}' | awk '{print substr($1, length($1), 1)}' | sort -n | awk 'NR==FNR{a[$1]=$0;next}!a[$1]++{print $0}' foo/

And got the output: awk: read error (Is a directory)

PyFunc

Resulting in output: awk: read error (Is a directory)

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

You can use the `ls` command with the `-S` option to sort by file size, and then pipe the output to `awk` and `sort` to sort by the least significant digit of the file size. Here's an example command:

ls -S foo/ | awk '{print $NF}' | sort -k 1.2n

Here's what each part of the command does: * `ls -S foo/`: list all files in the `foo` directory, sorted by file size * `awk '{print $NF}'`: print the last field (i.e., the filename) for each line of output from `ls` * `sort -k 1.2n`: sort the output by the second character of the first field (i.e., the least significant digit of the file size) in numeric order This will give you a list of file names sorted by the least significant digit of their file size. Note: The above command will work if the file size is less than 10GB. If the file size is more than 10GB, you may need to customize the awk command to extract the least significant digit of the file size. Also, the above command will work if your ls command is displaying file size in bytes otherwise you might have to use `--block-size=1` with ls command to display the file size in bytes.

ls -S --block-size=1 foo/ | awk '{print $NF}' | sort -k 1.2n

Hope this helps! Let me know if you have any questions.

Extract Code

I extracted the following code from that output:

#!/bin/bash

# Sort files in a directory by the least significant digit of their file size

# Usage: ./ls\_sort\_by\_lsd.sh <directory>

# Example: ./ls\_sort\_by\_lsd.sh foo/

# Note: The following command will work if the file size is less than 10GB. If the file
# size is more than 10GB, you may need to customize the awk command to extract the
# least significant digit of the file size.

# Also, the following command will work if your ls command is displaying file size in
# bytes. Otherwise, you might have to use --block-size=1 with ls command to display
# the file size in bytes.

ls -S --block-size=1 "$1" | awk '{print $NF}' | sort -k 1.2n

Run Code Interpreter

Running the following program:

#!/bin/bash

# Sort files in a directory by the least significant digit of their file size

# Usage: ./ls\_sort\_by\_lsd.sh <directory>

# Example: ./ls\_sort\_by\_lsd.sh foo/

# Note: The following command will work if the file size is less than 10GB. If the file
# size is more than 10GB, you may need to customize the awk command to extract the
# least significant digit of the file size.

# Also, the following command will work if your ls command is displaying file size in
# bytes. Otherwise, you might have to use --block-size=1 with ls command to display
# the file size in bytes.

ls -S --block-size=1 "$1" | awk '{print $NF}' | sort -k 1.2n

And got the output: ls: cannot access '': No such file or directory

PyFunc

Resulting in output: ls: cannot access '': No such file or directory

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

You can use the `ls` command with the `-lSr` options to list the files in the `foo/` directory, sorted by size in reverse order (largest to smallest), and then pipe the output to the `awk` command to extract the filenames and sort them by the least significant digit of their size. Here's an example:

ls -lSr foo/ | awk '{print $NF}' | sort -k2 -n | cut -d' ' -f1

Explanation: * `ls -lSr foo/`: lists the files in the `foo/` directory in reverse order by size, and also includes additional information such as file permissions, number of links, owner, group, size, and modification time. * `awk '{print $NF}'`: extracts the last field (filename) from each line of the output from the previous command. * `sort -k2 -n`: sorts the filenames by the second field (size) in numerical order. * `cut -d' ' -f1`: extracts the first field (filename) from each line of the output from the previous command. Note that the `-k2` option specifies that the second field should be used for sorting, and the `-n` option specifies that the sorting should be done numerically. This ensures that the sizes are sorted correctly, even if they have different numbers of digits. Also note that this command assumes that the filenames do not contain spaces or other special characters that could interfere with the parsing or sorting. If your filenames do contain such characters, you may need to modify the command to handle them properly.

Extract Code

I extracted the following code from that output:

ls -lSr foo/ | awk '{print $NF}' | sort -k2 -n | cut -d' ' -f1

Run Code Interpreter

Running the following program:

ls -lSr foo/ | awk '{print $NF}' | sort -k2 -n | cut -d' ' -f1

And got the output:

PyFunc

Resulting in output: 0 1 2 3 4 40 5 6 7 8 9

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False