Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

You can achieve this by using the `ls`, `awk`, `sort`, and `cut` commands in a pipeline. Here's a command that should do what you want:

1
ls -l foo/ | awk '{print $5, $9}' | sort -k1.4n -k1.5n | cut -d' ' -f2
Here's what each part does: 1. `ls -l foo/`: Lists all files in the `foo/` directory in long format, which includes the file size. 2. `awk '{print $5, $9}'`: Uses `awk` to print the 5th and 9th fields of each line. The 5th field is the file size and the 9th field is the file name. 3. `sort -k1.4n -k1.5n`: Sorts the output of the previous command. The `-k1.4n` option sorts by the 4th digit of the first field (the file size), and the `-k1.5n` option sorts by the 5th digit of the first field. Both sorts are numerical sorts (`n`). 4. `cut -d' ' -f2`: Uses `cut` to print only the second field of each line, which is the file name. The `-d' '` option sets the delimiter to a space character.

Extract Code

I extracted the following code from that output:

1
ls -l foo/ | awk '{print $5, $9}' | sort -k1.4n -k1.5n | cut -d' ' -f2

Run Code Interpreter

Running the following program:

1
ls -l foo/ | awk '{print $5, $9}' | sort -k1.4n -k1.5n | cut -d' ' -f2
And got the output: 0 1 2 3 4 5 6 7 8 9

PyFunc

Resulting in output: 0 1 2 3 4 5 6 7 8 9

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in a directory, sort them by the least significant digit of their size, and print only the file names, you can use the `ls`, `awk`, `sort`, and `cut` commands in bash. Here's a command that should accomplish what you want:

1
ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.lengthnr | cut -d' ' -f2
Explanation: * `ls -l foo/`: lists all files in the `foo` directory in long format, which includes the file size in bytes. * `awk '{print $5, $9}'`: extracts the file size (5th field) and the file name (9th field) from the output of `ls -l`. * `sort -k1.1n -k1.lengthnr`: sorts the output of `awk` first by the least significant digit (1st character) of the file size, and then by the length of the file size in reverse order. This ensures that files with smaller sizes come before files with larger sizes, even if the larger sizes have fewer digits. * `cut -d' ' -f2`: extracts only the file names from the sorted output of `sort`. The final output should be a list of file names in `foo/`, sorted by the least significant digit of their sizes. Note: This command assumes that the file names do not contain spaces. If your file names can contain spaces, you may need to modify the `awk` and `cut` commands accordingly.

Extract Code

I extracted the following code from that output:

1
ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.lengthnr | cut -d' ' -f2

Run Code Interpreter

Running the following program:

1
ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.lengthnr | cut -d' ' -f2
And got the output: sort: invalid number after '.': invalid count at start of 'lengthnr'

PyFunc

Resulting in output: sort: invalid number after '.': invalid count at start of 'lengthnr'

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

You can achieve this by using the `ls` command with `awk` and `sort`. Here's a one-liner that should do the trick:

1
ls -l fou | awk '{print $5, $9}' | sort -k1. length -k1.nr | cut -d' ' -f2
Here's what each part does: - `ls -l fou` lists all files in the `fou` directory in long format. - `awk '{print $5, $9}'` prints the size (5th field) and the filename (9th field). - `sort -k1. length -k1.nr` sorts first by the length of the size field, then by the size field itself, numerically. This effectively sorts by the least significant digit. - `cut -d' ' -f2` cuts out the size field, leaving only the filenames. Please note that this command will work well if the directory doesn't have subdirectories. If there are subdirectories, the command will also list them, and if the subdirectories have spaces in their names, the command might not work as expected. Also, this command sorts files by the least significant digit first, then the second least significant digit, and so on. This means that a file of size 2820 will come before a file of size 2279, because 0 is less than 9. If you want to sort files so that 2279 comes before 2820, you would need a different approach.

Extract Code

I extracted the following code from that output:

1
ls -l fou | awk '{print $5, $9}' | sort -k1. length -k1.nr | cut -d' ' -f2

Run Code Interpreter

Running the following program:

1
ls -l fou | awk '{print $5, $9}' | sort -k1. length -k1.nr | cut -d' ' -f2
And got the output: sort: invalid number after '.': invalid count at start of '' ls: cannot access 'fou': No such file or directory

PyFunc

Resulting in output: sort: invalid number after '.': invalid count at start of '' ls: cannot access 'fou': No such file or directory

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To achieve this, you can use the `ls`, `awk`, and `sort` commands in bash. Here's a command that should do what you want:

1
ls -lR foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.length,1nr | cut -d' ' -f2
Here's what each part of the command does: 1. `ls -lR foo/`: Lists all files in the `foo/` directory in the long format, which includes the file size. 2. `awk '{print $5, $9}'`: Uses `awk` to print the 5th and 9th fields of the output from `ls`. The 5th field is the file size, and the 9th field is the file name. 3. `sort -k1.1n -k1.length,1nr`: Sorts the output from `awk`. The `-k1.1n` option sorts by the first digit of the file size, and the `-k1.length,1nr` option sorts by the length of the file size, in reverse order. This has the effect of sorting by the least significant digit of the file size. 4. `cut -d' ' -f2`: Uses `cut` to print only the second field of the output from `sort`, which is the file name. This command will print the file names in the order specified, with the file size as the secondary sort key. If two files have the same least significant digit in their size, the one with the smaller size will be listed first.

Extract Code

I extracted the following code from that output:

1
ls -lR foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.length,1nr | cut -d' ' -f2

Run Code Interpreter

Running the following program:

1
ls -lR foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.length,1nr | cut -d' ' -f2
And got the output: sort: invalid number after '.': invalid count at start of 'length,1nr'

PyFunc

Resulting in output: sort: invalid number after '.': invalid count at start of 'length,1nr'

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To sort files by the least significant digit of their size, you can use the `ls` command with `awk` and `sort` in a pipeline. Here's a command that should work for you:

1
ls -l foo/ | awk '{print $5, $9}' | sort -k1.5n -k1.1n | cut -d' ' -f2
Let's break down this command: 1. `ls -l foo/`: This lists all files in the `foo/` directory in the long format, which includes file size. 2. `awk '{print $5, $9}'`: This uses `awk` to print the 5th field (file size) and the 9th field (file name) from the output of the `ls` command. 3. `sort -k1.5n -k1.1n`: This sorts the output of the previous command. The `-k1.5n` option sorts by the 5th digit of the first field (file size) numerically. The `-k1.1n` option sorts by the first digit of the first field (file size) numerically. This ensures that files are sorted by the least significant digit of their size. 4. `cut -d' ' -f2`: This uses `cut` to print only the second field (file name) from the sorted output. Please note that this command assumes that file sizes do not exceed 999999 bytes. If your files are larger, you may need to adjust the `awk` and `sort` commands accordingly. Also, this command will not work correctly if any file names contain spaces. If your file names can contain spaces, you may need to use a different approach, such as using a script to read the output of `ls` line by line and extract the file size and name for each file.

Extract Code

I extracted the following code from that output:

1
ls -l foo/ | awk '{print $5, $9}' | sort -k1.5n -k1.1n | cut -d' ' -f2

Run Code Interpreter

Running the following program:

1
ls -l foo/ | awk '{print $5, $9}' | sort -k1.5n -k1.1n | cut -d' ' -f2
And got the output: 8 0 1 2 3 4 5 6 7 9

PyFunc

Resulting in output: 8 0 1 2 3 4 5 6 7 9

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False