Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

You can achieve this by using the `ls` command with `awk` and `sort`. Here's how you can do it:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.3n | cut -d' ' -f2
Let's break down this command: 1. `ls -l foo/`: This lists all files in the `foo` directory in long format, which includes the size of each file. 2. `awk '{print $5, $9}'`: This uses `awk` to print the 5th and 9th fields of each line. The 5th field is the size of the file, and the 9th field is the file name. 3. `sort -k1.3n`: This sorts the output of the previous command. The `-k1.3n` option tells `sort` to sort on the 3rd character of the 1st field (the size of the file), treating it as a number. This effectively sorts the files based on the least significant digit of their size. 4. `cut -d' ' -f2`: Finally, this uses `cut` to print only the 2nd field of each line (the file name), using a space as the field delimiter.

Extract Code

I extracted the following code from that output:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.3n | cut -d' ' -f2

Run Code Interpreter

Running the following program:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.3n | cut -d' ' -f2
And got the output: 2 0 5 7 1 6 4 3 9 8

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Equal Evaluation

Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

You can achieve this by using the `ls` command with `awk` and `sort`. Here's a command that should work:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.length -k1n -k2 | cut -d' ' -f2
Here's what each part does: - `ls -l foo/` lists all files in the `foo` directory in long format, which includes the file size. - `awk '{print $5, $9}'` extracts the file size (5th field) and the file name (9th field). This assumes that there are no spaces in your file names. If there can be spaces, you might need a more complex `awk` command. - `sort -k1.length -k1n -k2` sorts the output. The `-k1.length` option sorts by the length of the first field first (so that 2820 comes before 281771), the `-k1n` option sorts the first field numerically, and the `-k2` option sorts the second field lexicographically (this is to ensure the sort is stable). - `cut -d' ' -f2` extracts the file names from the sorted output. Please note that this command will include directories as well as files. If you want to include only files, you can use `find` command instead of `ls`:
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find foo/ -type f -exec ls -l {} \; | awk '{print $5, $9}' | sort -k1.length -k1n -k2 | cut -d' ' -f2
This command will only list regular files (`-type f`) in the `foo` directory.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

# Use find command to list only files in the 'foo' directory
find foo/ -type f -exec ls -l {} \; | awk '{print $5, $9}' | sort -k1.length -k1n -k2 | cut -d' ' -f2

Run Code Interpreter

Running the following program:

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#!/bin/bash

# Use find command to list only files in the 'foo' directory
find foo/ -type f -exec ls -l {} \; | awk '{print $5, $9}' | sort -k1.length -k1n -k2 | cut -d' ' -f2
And got the output: sort: invalid number after '.': invalid count at start of 'length'

PyFunc

Resulting in output: sort: invalid number after '.': invalid count at start of 'length'

Equal Evaluation

Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To sort files by the least significant digit of their size, you can use the `ls` command with `awk` and `sort`. Here's a command that should work:

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ls -lR foo/ | awk '(/^-/) {print $5, $9}' | sort -k1.0n -k1.1n | cut -d' ' -f2
Here's what each part does: - `ls -lR foo/`: Lists all files in the `foo/` directory in the long format. The `-R` option is used to list files in subdirectories recursively. - `awk '(/^-/) {print $5, $9}'`: Filters out directories and only keeps files. It then prints the size (5th field) and the name (9th field). - `sort -k1.0n -k1.1n`: Sorts the output first by the whole number (least significant digit first) and then by the last digit. - `cut -d' ' -f2`: Removes the size information and only keeps the file names. This command will print the file names sorted by the least significant digit of their size. If you want to remove the directory names from the output, you can use the `basename` command:
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ls -lR foo/ | awk '(/^-/) {print $5, $9}' | sort -k1.0n -k1.1n | cut -d' ' -f2 | while read file; do basename "$file"; done
This command will only print the file names without directory information.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

# This script sorts files by the least significant digit of their size

# Lists all files in the foo/ directory in the long format
# Filters out directories and only keeps files
# Prints the size (5th field) and the name (9th field)
# Sorts the output first by the whole number (least significant digit first) and then by the last digit
# Removes the size information and only keeps the file names
ls -lR foo/ | awk '(/^-/) {print $5, $9}' | sort -k1.0n -k1.1n | cut -d' ' -f2 | while read file; do basename "$file"; done

Run Code Interpreter

Running the following program:

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#!/bin/bash

# This script sorts files by the least significant digit of their size

# Lists all files in the foo/ directory in the long format
# Filters out directories and only keeps files
# Prints the size (5th field) and the name (9th field)
# Sorts the output first by the whole number (least significant digit first) and then by the last digit
# Removes the size information and only keeps the file names
ls -lR foo/ | awk '(/^-/) {print $5, $9}' | sort -k1.0n -k1.1n | cut -d' ' -f2 | while read file; do basename "$file"; done
And got the output: sort: character offset is zero: invalid field specification '1.0n'

PyFunc

Resulting in output: sort: character offset is zero: invalid field specification '1.0n'

Equal Evaluation

Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

You can achieve this by using the `ls` and `sort` commands in bash. Here's a command that should do what you're asking for:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.length,1.lengthr | cut -d' ' -f2
Here's what each part of the command does: 1. `ls -l foo/`: Lists all files in the directory `foo/` in long format, which includes file size. 2. `awk '{print $5, $9}'`: Uses `awk` to print the 5th (file size) and 9th (file name) fields. 3. `sort -k1.1n -k1.length,1.lengthr`: Sorts the output. The `-k1.1n` option sorts numerically by the first character of the first field (file size). The `-k1.length,1.lengthr` option sorts by the length of the first field in reverse order, effectively sorting by the least significant digit. 4. `cut -d' ' -f2`: Uses `cut` to print only the second field (file name) of the sorted output.

Extract Code

I extracted the following code from that output:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.length,1.lengthr | cut -d' ' -f2

Run Code Interpreter

Running the following program:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.length,1.lengthr | cut -d' ' -f2
And got the output: sort: invalid number after '.': invalid count at start of 'length,1.lengthr'

PyFunc

Resulting in output: sort: invalid number after '.': invalid count at start of 'length,1.lengthr'

Equal Evaluation

Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

You can achieve this by using the `ls`, `awk`, `sort`, and `cut` commands in a pipeline. Here's a command that should work:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1. length | cut -d' ' -f2
Here's what each part does: 1. `ls -l foo/`: Lists all files in the `foo` directory in long format, which includes the file size. 2. `awk '{print $5, $9}'`: Uses `awk` to print the 5th and 9th fields of each line. The 5th field is the file size and the 9th field is the file name. 3. `sort -k1.1n -k1. length`: Sorts the output. The `-k1.1n` option sorts numerically by the first digit of the first field (the file size). The `-k1. length` option sorts by the length of the first field, which effectively sorts by the number of digits in the file size. This ensures that files with fewer digits in their size come first. 4. `cut -d' ' -f2`: Uses `cut` to print only the second field of each line, which is the file name. Please note that this command assumes that there are no spaces or newlines in your file names. If there are, the command will not work correctly. Also, this command sorts files by the first digit of their size and then by the length of their size, which is not exactly the same as sorting by the least significant digit. However, it should produce the same result for the example you gave. If you want to sort by the least significant digit, you would need to reverse the size, sort, and then reverse again, which is a bit more complex and may not be possible with standard Unix tools.

Extract Code

I extracted the following code from that output:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1. length | cut -d' ' -f2

Run Code Interpreter

Running the following program:

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ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1. length | cut -d' ' -f2
And got the output: sort: invalid number after '.': invalid count at start of ''

PyFunc

Resulting in output: sort: invalid number after '.': invalid count at start of ''

Equal Evaluation

Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8: False