I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this by using the `ls` command with `awk` and `sort`. Here's how you can do it:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.3n | cut -d' ' -f2 |
I extracted the following code from that output:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.3n | cut -d' ' -f2 |
Running the following program:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.3n | cut -d' ' -f2 |
2
0
5
7
1
6
4
3
9
8
Resulting in output: 2 0 5 7 1 6 4 3 9 8
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: True
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this by using the `ls` command with `awk` and `sort`. Here's a command that should work:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.length -k1n -k2 | cut -d' ' -f2 |
1 | find foo/ -type f -exec ls -l {} \; | awk '{print $5, $9}' | sort -k1.length -k1n -k2 | cut -d' ' -f2 |
I extracted the following code from that output:
1 2 3 4 | #!/bin/bash # Use find command to list only files in the 'foo' directory find foo/ -type f -exec ls -l {} \; | awk '{print $5, $9}' | sort -k1.length -k1n -k2 | cut -d' ' -f2 |
Running the following program:
1 2 3 4 | #!/bin/bash # Use find command to list only files in the 'foo' directory find foo/ -type f -exec ls -l {} \; | awk '{print $5, $9}' | sort -k1.length -k1n -k2 | cut -d' ' -f2 |
sort: invalid number after '.': invalid count at start of 'length'
Resulting in output: sort: invalid number after '.': invalid count at start of 'length'
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
To sort files by the least significant digit of their size, you can use the `ls` command with `awk` and `sort`. Here's a command that should work:
1 | ls -lR foo/ | awk '(/^-/) {print $5, $9}' | sort -k1.0n -k1.1n | cut -d' ' -f2 |
1 | ls -lR foo/ | awk '(/^-/) {print $5, $9}' | sort -k1.0n -k1.1n | cut -d' ' -f2 | while read file; do basename "$file"; done |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 | #!/bin/bash # This script sorts files by the least significant digit of their size # Lists all files in the foo/ directory in the long format # Filters out directories and only keeps files # Prints the size (5th field) and the name (9th field) # Sorts the output first by the whole number (least significant digit first) and then by the last digit # Removes the size information and only keeps the file names ls -lR foo/ | awk '(/^-/) {print $5, $9}' | sort -k1.0n -k1.1n | cut -d' ' -f2 | while read file; do basename "$file"; done |
Running the following program:
1 2 3 4 5 6 7 8 9 10 | #!/bin/bash # This script sorts files by the least significant digit of their size # Lists all files in the foo/ directory in the long format # Filters out directories and only keeps files # Prints the size (5th field) and the name (9th field) # Sorts the output first by the whole number (least significant digit first) and then by the last digit # Removes the size information and only keeps the file names ls -lR foo/ | awk '(/^-/) {print $5, $9}' | sort -k1.0n -k1.1n | cut -d' ' -f2 | while read file; do basename "$file"; done |
sort: character offset is zero: invalid field specification '1.0n'
Resulting in output: sort: character offset is zero: invalid field specification '1.0n'
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this by using the `ls` and `sort` commands in bash. Here's a command that should do what you're asking for:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.length,1.lengthr | cut -d' ' -f2 |
I extracted the following code from that output:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.length,1.lengthr | cut -d' ' -f2 |
Running the following program:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1.length,1.lengthr | cut -d' ' -f2 |
sort: invalid number after '.': invalid count at start of 'length,1.lengthr'
Resulting in output: sort: invalid number after '.': invalid count at start of 'length,1.lengthr'
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this by using the `ls`, `awk`, `sort`, and `cut` commands in a pipeline. Here's a command that should work:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1. length | cut -d' ' -f2 |
I extracted the following code from that output:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1. length | cut -d' ' -f2 |
Running the following program:
1 | ls -l foo/ | awk '{print $5, $9}' | sort -k1.1n -k1. length | cut -d' ' -f2 |
sort: invalid number after '.': invalid count at start of ''
Resulting in output: sort: invalid number after '.': invalid count at start of ''
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: False