Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory and sort them by the least significant digit of their sizes in Bash, you can use a combination of `ls`, `awk`, `sort`, and `cut`. Here's a step-by-step command to achieve this:

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ls -lS foo/ | awk '{print $5, $9}' | sort -k 1.4,1n | cut -d' ' -f2
Explanation: 1. `ls -lS foo/`: This lists all files in the `foo/` directory with detailed information, sorted by size. 2. `awk '{print $5, $9}'`: This extracts the size (`$5`) and the filename (`$9`) columns from the `ls` output. 3. `sort -k 1.4,1n`: This sorts the output based on the 4th character of the size field, which corresponds to the least significant digit of the size. 4. `cut -d' ' -f2`: This extracts just the filename from the sorted output. This command should give you a list of filenames sorted by the least significant digit of their sizes. Note that `ls -lS` may include directories and other non-file entries; if you want to exclude these, you may want to filter the output further or use `find` to list only regular files:
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find foo/ -type f -exec ls -lS {} + | awk '{print $5, $9}' | sort -k 1.4,1n | cut -d' ' -f2
This command ensures that only regular files are considered.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

# List all files in the `foo/` directory and sort them by the least significant digit of their sizes
ls -lS foo/ | awk '{print $5, $9}' | sort -k 1.4,1n | cut -d' ' -f2

Run Code Interpreter

Running the following program:

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#!/bin/bash

# List all files in the `foo/` directory and sort them by the least significant digit of their sizes
ls -lS foo/ | awk '{print $5, $9}' | sort -k 1.4,1n | cut -d' ' -f2
And got the output: 2 9 6 4 7 8 3 5 1 0

PyFunc

Resulting in output: 2 9 6 4 7 8 3 5 1 0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the directory `foo/` and sort them by the least significant digit of their size, you can use the following Bash command:

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ls -lS foo/ | grep -v '^d' | awk '{print $5 " " $9}' | sort -k1,1n -k1.1,1.1n | cut -d' ' -f2-
Here's a step-by-step breakdown of what this command does: 1. `ls -lS foo/`: Lists all files in `foo/` in long format and sorts them by size in descending order. 2. `grep -v '^d'`: Filters out directories from the list. 3. `awk '{print $5 " " $9}'`: Extracts the size (5th field) and the filename (9th field). 4. `sort -k1,1n -k1.1,1.1n`: Sorts the output numerically by the size and then by the least significant digit of the size. 5. `cut -d' ' -f2-`: Removes the size from the output, leaving just the file names. This will give you the file names sorted by the least significant digit of their sizes.

Extract Code

I extracted the following code from that output:

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ls -lS foo/ | grep -v '^d' | awk '{print $5 " " $9}' | sort -k1,1n -k1.1,1.1n | cut -d' ' -f2-

Run Code Interpreter

Running the following program:

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ls -lS foo/ | grep -v '^d' | awk '{print $5 " " $9}' | sort -k1,1n -k1.1,1.1n | cut -d' ' -f2-
And got the output: 8 2 9 6 4 7 3 5 1 0

PyFunc

Resulting in output: 8 2 9 6 4 7 3 5 1 0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To achieve this in bash, you can use a combination of `ls`, `awk`, and `sort` to list the files in the `foo/` directory and sort them by the least significant digit of their sizes. Here's a step-by-step command to do this: 1. Use `ls -l` to list the files along with their sizes. 2. Use `awk` to print the size and the file name. 3. Use `sort` to sort the output by the least significant digit of the size. 4. Use `awk` again to print just the file names. Here's the complete command:

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ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.0n,1.1 | awk '{print $2}'
Explanation: - `ls -l foo/`: Lists all files in the `foo/` directory with details. - `awk 'NR>1 {print $5, $9}'`: Filters out the header line (NR>1) and prints the file size (`$5`) and the file name (`$9`). - `sort -k1.0n,1.1`: Sorts the files based on the least significant digit of the size. The `-k1.0n,1.1` specifies sorting by the numeric value starting from the first character of the first field. - `awk '{print $2}'`: Prints just the file names from the sorted list. You should run this command in a terminal that is in the directory containing `foo/`, or you can modify the `ls -l foo/` part to include the full path to `foo/` if necessary. Note: The sorting by the least significant digit of the size is a bit tricky and might need adjustments based on specific requirements or edge cases. The above command aims to give a basic implementation of sorting by the least significant digit.

Extract Code

I extracted the following code from that output:

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ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.0n,1.1 | awk '{print $2}'

Run Code Interpreter

Running the following program:

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ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.0n,1.1 | awk '{print $2}'
And got the output: sort: character offset is zero: invalid field specification '1.0n,1.1'

PyFunc

Resulting in output: sort: character offset is zero: invalid field specification '1.0n,1.1'

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

You can achieve this by using a combination of `ls`, `awk`, and `sort` in bash. Here's a step-by-step solution: 1. Use `ls -l` to list files with their sizes. 2. Use `awk` to extract the file sizes and filenames. 3. Use `sort` to sort the lines based on the least significant digit of the file size. 4. Use `awk` again to print only the filenames. Here’s a command that does this:

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ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.1 | awk '{print $2}'
Here's a breakdown of the command: 1. `ls -l foo/`: Lists all files in the `foo/` directory with detailed information. 2. `awk 'NR>1 {print $5, $9}'`: Skips the first line (which is the total number of blocks) and prints the file size (`$5`) and the filename (`$9`). 3. `sort -k1.1`: Sorts the output based on the first character of the size field, effectively sorting by the least significant digit. 4. `awk '{print $2}'`: Prints only the filenames from the sorted output. This should give you the filenames sorted by the least significant digit of their sizes.

Extract Code

I extracted the following code from that output:

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ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.1 | awk '{print $2}'

Run Code Interpreter

Running the following program:

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ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.1 | awk '{print $2}'
And got the output: 2 9 6 4 7 8 3 5 1 0

PyFunc

Resulting in output: 2 9 6 4 7 8 3 5 1 0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

You can achieve this using a combination of `ls`, `awk`, `sort`, and `cut` commands in Bash. Here is a command you can use:

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ls -lS foo/ | awk 'NR > 1 {print $5, $9}' | sort -k1.2,1n | cut -d' ' -f2
Here's a breakdown of what each part does: 1. `ls -lS foo/`: List files in the `foo/` directory sorted by size in descending order. 2. `awk 'NR > 1 {print $5, $9}'`: Skip the first line (header) and print the 5th and 9th fields (size and filename). 3. `sort -k1.2,1n`: Sort the output by the least significant digit of the size (`-k1.2,1n` specifies to sort from the second character onward in a numeric fashion). 4. `cut -d' ' -f2`: Extract the second field (filename). Put together, this command will list the files in `foo/`, sorted by the least significant digit of their size, and output only the filenames. Let's go through an example: Assume the contents of `foo/` are:
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-rw-r--r-- 1 user group 2820 Oct  7 10:00 file1
-rw-r--r-- 1 user group 281771 Oct  7 10:00 otherfile
-rw-r--r-- 1 user group 2279 Oct  7 10:00 lastfile
Running the command:
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ls -lS foo/ | awk 'NR > 1 {print $5, $9}' | sort -k1.2,1n | cut -d' ' -f2
Will produce the output:
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file1
lastfile
otherfile
This is because: - `2820` (least significant digit is 0) - `2279` (least significant digit is 9) - `281771` (least significant digit is 1) So `file1` comes first, then `lastfile`, and then `otherfile`, sorted by smallest to largest least significant digit of their sizes.

Extract Code

I extracted the following code from that output:

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ls -lS foo/ | awk 'NR > 1 {print $5, $9}' | sort -k1.2,1n | cut -d' ' -f2

Run Code Interpreter

Running the following program:

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ls -lS foo/ | awk 'NR > 1 {print $5, $9}' | sort -k1.2,1n | cut -d' ' -f2
And got the output: 7 6 8 1 2 0 3 9 5 4

PyFunc

Resulting in output: 7 6 8 1 2 0 3 9 5 4

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False