I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
To list all files in the `foo/` directory and sort them by the least significant digit of their sizes in Bash, you can use a combination of `ls`, `awk`, `sort`, and `cut`. Here's a step-by-step command to achieve this:
1 | ls -lS foo/ | awk '{print $5, $9}' | sort -k 1.4,1n | cut -d' ' -f2 |
1 | find foo/ -type f -exec ls -lS {} + | awk '{print $5, $9}' | sort -k 1.4,1n | cut -d' ' -f2 |
I extracted the following code from that output:
1 2 3 4 | #!/bin/bash # List all files in the `foo/` directory and sort them by the least significant digit of their sizes ls -lS foo/ | awk '{print $5, $9}' | sort -k 1.4,1n | cut -d' ' -f2 |
Running the following program:
1 2 3 4 | #!/bin/bash # List all files in the `foo/` directory and sort them by the least significant digit of their sizes ls -lS foo/ | awk '{print $5, $9}' | sort -k 1.4,1n | cut -d' ' -f2 |
2
9
6
4
7
8
3
5
1
0
Resulting in output: 2 9 6 4 7 8 3 5 1 0
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
To list all files in the directory `foo/` and sort them by the least significant digit of their size, you can use the following Bash command:
1 | ls -lS foo/ | grep -v '^d' | awk '{print $5 " " $9}' | sort -k1,1n -k1.1,1.1n | cut -d' ' -f2- |
I extracted the following code from that output:
1 | ls -lS foo/ | grep -v '^d' | awk '{print $5 " " $9}' | sort -k1,1n -k1.1,1.1n | cut -d' ' -f2- |
Running the following program:
1 | ls -lS foo/ | grep -v '^d' | awk '{print $5 " " $9}' | sort -k1,1n -k1.1,1.1n | cut -d' ' -f2- |
8
2
9
6
4
7
3
5
1
0
Resulting in output: 8 2 9 6 4 7 3 5 1 0
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
To achieve this in bash, you can use a combination of `ls`, `awk`, and `sort` to list the files in the `foo/` directory and sort them by the least significant digit of their sizes. Here's a step-by-step command to do this: 1. Use `ls -l` to list the files along with their sizes. 2. Use `awk` to print the size and the file name. 3. Use `sort` to sort the output by the least significant digit of the size. 4. Use `awk` again to print just the file names. Here's the complete command:
1 | ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.0n,1.1 | awk '{print $2}' |
I extracted the following code from that output:
1 | ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.0n,1.1 | awk '{print $2}' |
Running the following program:
1 | ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.0n,1.1 | awk '{print $2}' |
sort: character offset is zero: invalid field specification '1.0n,1.1'
Resulting in output: sort: character offset is zero: invalid field specification '1.0n,1.1'
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this by using a combination of `ls`, `awk`, and `sort` in bash. Here's a step-by-step solution: 1. Use `ls -l` to list files with their sizes. 2. Use `awk` to extract the file sizes and filenames. 3. Use `sort` to sort the lines based on the least significant digit of the file size. 4. Use `awk` again to print only the filenames. Here’s a command that does this:
1 | ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.1 | awk '{print $2}' |
I extracted the following code from that output:
1 | ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.1 | awk '{print $2}' |
Running the following program:
1 | ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1.1 | awk '{print $2}' |
2
9
6
4
7
8
3
5
1
0
Resulting in output: 2 9 6 4 7 8 3 5 1 0
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this using a combination of `ls`, `awk`, `sort`, and `cut` commands in Bash. Here is a command you can use:
1 | ls -lS foo/ | awk 'NR > 1 {print $5, $9}' | sort -k1.2,1n | cut -d' ' -f2 |
1 2 3 | -rw-r--r-- 1 user group 2820 Oct 7 10:00 file1 -rw-r--r-- 1 user group 281771 Oct 7 10:00 otherfile -rw-r--r-- 1 user group 2279 Oct 7 10:00 lastfile |
1 | ls -lS foo/ | awk 'NR > 1 {print $5, $9}' | sort -k1.2,1n | cut -d' ' -f2 |
1 2 3 | file1 lastfile otherfile |
I extracted the following code from that output:
1 | ls -lS foo/ | awk 'NR > 1 {print $5, $9}' | sort -k1.2,1n | cut -d' ' -f2 |
Running the following program:
1 | ls -lS foo/ | awk 'NR > 1 {print $5, $9}' | sort -k1.2,1n | cut -d' ' -f2 |
7
6
8
1
2
0
3
9
5
4
Resulting in output: 7 6 8 1 2 0 3 9 5 4
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False