I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
To achieve the task of listing all files in a directory (`foo/` in your case), and sorting them by the least significant digit of their sizes, you can use a combination of shell commands and scripting techniques. Here's a way to do it using `ls`, `awk`, `sort`, and `cut` in a bash environment.
1 2 3 4 5 6 7 8 | #!/bin/bash # Navigate to the directory (optional, you can also work with absolute paths) cd foo/ # List files and their sizes using `ls` and `-l`, then process the list ls -l | grep '^-' | awk '{print $5 " " $9}' | \ awk '{print $1 % 10, $0}' | sort -n | cut -d' ' -f3- |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 | #!/bin/bash # Navigate to the directory (optional, you can also work with absolute paths) cd foo/ # List files and their sizes using `ls` and `-l`, then process the list ls -l | grep '^-' | awk '{print $5 " " $9}' | \ awk '{print $1 % 10, $0}' | sort -n | cut -d' ' -f3- |
Running the following program:
1 2 3 4 5 6 7 8 | #!/bin/bash # Navigate to the directory (optional, you can also work with absolute paths) cd foo/ # List files and their sizes using `ls` and `-l`, then process the list ls -l | grep '^-' | awk '{print $5 " " $9}' | \ awk '{print $1 % 10, $0}' | sort -n | cut -d' ' -f3- |
2
0
5
7
1
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9
8
Resulting in output: 2 0 5 7 1 6 4 3 9 8
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
To achieve this in bash, you can leverage the `ls` and `awk` commands, combined with sorting functionalities. However, the exact behavior you're asking for – sorting by the least significant digit of their size – isn't directly available through standard command line tools like `ls` or `sort`. You would need a custom command pipeline to extract file sizes, sort by the desired criteria, and then list the files. Here's a bash script that does what you want:
1 2 3 4 5 6 7 8 9 10 11 | #!/bin/bash # Navigate to the directory, replace 'foo/' with your actual directory path cd foo/ # List files and their sizes using stat, sort by the least significant digit of their sizes, and then print file names stat --format="%s %n" * | \ awk '{ print $1 " " $2 }' | \ sort -k1,1 -g | \ sort -k1.1,1.1 | \ awk '{ print $2 }' |
1 2 3 4 5 6 7 8 9 10 | #!/bin/bash cd foo/ # List files, get their sizes, and sort by the least significant digit stat --format="%s %n" * | \ awk '{ print $1 " " $2 }' | \ awk '{print substr($1,length($1),1) " " $0}' | \ sort -k1,1n | \ awk '{print $3}' |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 | #!/bin/bash cd foo/ # List files, get their sizes, and sort by the least significant digit stat --format="%s %n" * | \ awk '{ print $1 " " $2 }' | \ awk '{print substr($1,length($1),1) " " $0}' | \ sort -k1,1n | \ awk '{print $3}' |
Running the following program:
1 2 3 4 5 6 7 8 9 10 | #!/bin/bash cd foo/ # List files, get their sizes, and sort by the least significant digit stat --format="%s %n" * | \ awk '{ print $1 " " $2 }' | \ awk '{print substr($1,length($1),1) " " $0}' | \ sort -k1,1n | \ awk '{print $3}' |
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0
5
7
1
6
4
3
9
8
Resulting in output: 2 0 5 7 1 6 4 3 9 8
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
To achieve this in bash, you can use a combination of commands to list the files in `foo/`, obtain their sizes, sort them by the least significant digit of their size, and then extract the filenames. Here's a way to do it:
1 | ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1,1n -k2,2 | awk '{print $2}' |
1 2 3 | ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1,1n | awk '{print $2}' | while read filename; do echo "$(stat -c %s foo/"$filename" | awk '{print substr($1,length($1),1)}') $filename"; done | sort -k1,1n | cut -d' ' -f2- |
1 2 3 4 5 6 7 | #!/bin/bash while IFS= read -r -d '' file; do size=$(stat --format="%s" "$file") least_significant_digit=$(echo $size | grep -o . | tail -1) echo "$least_significant_digit $file" done < <(find foo/ -type f -print0) | sort -k1,1n -k2,2 | awk '{print substr($0, index($0, $2))}' |
I extracted the following code from that output:
1 2 3 4 5 6 7 | #!/bin/bash while IFS= read -r -d '' file; do size=$(stat --format="%s" "$file") least_significant_digit=$(echo $size | grep -o . | tail -1) echo "$least_significant_digit $file" done < <(find foo/ -type f -print0) | sort -k1,1n -k2,2 | awk '{print substr($0, index($0, $2))}' |
Running the following program:
1 2 3 4 5 6 7 | #!/bin/bash while IFS= read -r -d '' file; do size=$(stat --format="%s" "$file") least_significant_digit=$(echo $size | grep -o . | tail -1) echo "$least_significant_digit $file" done < <(find foo/ -type f -print0) | sort -k1,1n -k2,2 | awk '{print substr($0, index($0, $2))}' |
foo/2
foo/0
foo/5
foo/7
foo/1
foo/6
foo/4
foo/3
foo/9
foo/8
Resulting in output: foo/2 foo/0 foo/5 foo/7 foo/1 foo/6 foo/4 foo/3 foo/9 foo/8
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
To achieve the sorting of files in `foo/` by the least significant digit of their size and then output just the file names, you can use a combination of shell commands. The `ls` command alone won't suffice for this sort of customized sorting. Instead, you'll need to use `stat` to get the file sizes, `sort` to sort by the desired criteria, and `awk` or `cut` for parsing and formatting the output. Here's how you can do it:
1 2 3 4 5 6 7 | #!/bin/bash # Navigate to the directory (if needed, remove if you're already in the correct directory) cd foo/ # List files, get their sizes, sort by the least significant digit, and extract the names stat --format="%s %n" * | sort -k1,1n -k2,2 | awk '{ size=$1; name=$2; least_significant_digit=size%10; print least_significant_digit, name }' | sort -n | cut -d" " -f2- |
I extracted the following code from that output:
1 2 3 4 5 6 7 | #!/bin/bash # Navigate to the directory (if needed, remove if you're already in the correct directory) cd foo/ # List files, get their sizes, sort by the least significant digit, and extract the names stat --format="%s %n" * | sort -k1,1n -k2,2 | awk '{ size=$1; name=$2; least_significant_digit=size%10; print least_significant_digit, name }' | sort -n | cut -d" " -f2- |
Running the following program:
1 2 3 4 5 6 7 | #!/bin/bash # Navigate to the directory (if needed, remove if you're already in the correct directory) cd foo/ # List files, get their sizes, sort by the least significant digit, and extract the names stat --format="%s %n" * | sort -k1,1n -k2,2 | awk '{ size=$1; name=$2; least_significant_digit=size%10; print least_significant_digit, name }' | sort -n | cut -d" " -f2- |
2
0
5
7
1
6
4
3
9
8
Resulting in output: 2 0 5 7 1 6 4 3 9 8
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
To achieve the listing of files in `foo/` directory, sorted by the least significant digit of their size and then output just the file names (without paths or sizes), you can use the following approach in bash. This task requires a bit of command-line creativity, combining `ls`, `awk`, and `sort` commands, among possible other utilities. Here's a step-by-step approach using `ls`, `awk`, `sort`, and `cut`: 1. **List files with their sizes**: Use `ls` with the `-l` and `-S` options to list files along with their sizes. The `-S` option is not necessary for the sorting requirement but is often used in size-related listings. Since we're focusing on the least significant digit, we won't use `-S` in this solution. 2. **Extract the filename and size**: You can use `awk` to print the filename and its size. 3. **Sort by the least significant digit of their size**: Use `sort` based on the custom requirement. 4. **Extract the sorted filenames**: Finally, use `cut` or `awk` to extract and display only the filenames. Here is a command that combines these steps. This command assumes that you are dealing with regular files (not directories, symbolic links, etc.) and that filenames do not contain newline characters:
1 | find foo/ -type f -printf "%s %f\n" | awk '{print $1 " " $NF}' | sort -k1,1n -k2,2 | awk '{print substr($1, length($1), 1) " " $2}' | sort -n | cut -d' ' -f2- |
I extracted the following code from that output:
1 | find foo/ -type f -printf "%s %f\n" | awk '{print $1 " " $NF}' | sort -k1,1n -k2,2 | awk '{print substr($1, length($1), 1) " " $2}' | sort -n | cut -d' ' -f2- |
Running the following program:
1 | find foo/ -type f -printf "%s %f\n" | awk '{print $1 " " $NF}' | sort -k1,1n -k2,2 | awk '{print substr($1, length($1), 1) " " $2}' | sort -n | cut -d' ' -f2- |
2
0
5
7
1
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4
3
9
8
Resulting in output: 2 0 5 7 1 6 4 3 9 8
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True