Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

Output

To list all files in a directory `foo/` and sort them by the least significant digit of their size, you can use a combination of shell commands in Bash. The approach involves getting the file size, extracting the least significant digit of each file size, and then sorting the files based on that digit. Here is a command pipeline that does this:

for file in foo/*; do
  echo "$(stat --format="%s %n" "$file" | awk '{print $1 % 10, $0}')" | sed 's/^[0-9]\+ //'
done | sort -n | cut -d' ' -f2-

Explanation of the command: 1. `for file in foo/*; do ... done`: This iterates over all files in the directory `foo/`. 2. `stat --format="%s %n" "$file"`: For each file, this command prints its size in bytes (`%s`) and its name (`%n`). 3. `awk '{print $1 % 10, $0}'`: This AWK command takes the output of `stat`, calculates the least significant digit of the file size (`$1 % 10`), and prints this digit followed by the original `stat` output. 4. `sed 's/^[0-9]\+ //'`: This `sed` command removes the leading digits (the original file size and the least significant digit used for sorting) from the line, leaving the formatted size and the file name. 5. The entire output of the loop is then piped to `sort -n`, which sorts the lines numerically based on the leading number (the least significant digit of the file size). 6. `cut -d' ' -f2-`: Finally, `cut` is used to remove the sorting key (the least significant digit), leaving only the size and file name. To only display the file names, modifying the final `awk` or `sed` command to output just the file name instead of the file size and name can achieve this. For example, if you only want file names, you could adjust the `awk` command inside the loop:

for file in foo/*; do
  echo "$(stat --format="%s %n" "$file" | awk '{print $1 % 10, $NF}')" 
done | sort -n | cut -d' ' -f2-

In this modified version, `$NF` in the `awk` command ensures that only the file name is printed alongside the least significant digit of the file size for sorting. This way, after sorting and cutting, you end up with just the file names, sorted as required.

Extract Code

I extracted the following code from that output:

#!/bin/bash

for file in foo/*; do
  echo "$(stat --format="%s %n" "$file" | awk '{print $1 % 10, $0}')" | sed 's/^[0-9]\+ //'
done | sort -n | cut -d' ' -f2-

Run Code Interpreter

Running the following program:

#!/bin/bash

for file in foo/*; do
  echo "$(stat --format="%s %n" "$file" | awk '{print $1 % 10, $0}')" | sed 's/^[0-9]\+ //'
done | sort -n | cut -d' ' -f2-

And got the output:

foo/8
foo/2
foo/9
foo/6
foo/4
foo/7
foo/3
foo/5
foo/1
foo/0

PyFunc

Resulting in output: foo/8 foo/2 foo/9 foo/6 foo/4 foo/7 foo/3 foo/5 foo/1 foo/0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

To achieve this task in Bash, you can use a combination of commands to list all files in the directory `foo/`, obtain their sizes, sort them by the least significant digit of their sizes, and finally print their names. The following Bash script accomplishes this:

#!/bin/bash

# Navigate to the directory, if needed
# cd foo/

# List files, get their sizes with stat, sort by the least significant digit, then extract the filename
find foo/ -type f -exec stat --format="%s %n" {} \; | 
awk '{print $1 " " $NF}' | 
sort -k1,1 -n | 
sort -k1.1,1.1 -n | 
awk '{print $2}' |
sed 's!.*/!!'

Here's a breakdown of the script: 1. `find foo/ -type f -exec stat --format="%s %n" {} \;`: - This command finds all files (`-type f`) in the `foo/` directory and executes (`-exec`) the `stat` command for each file. - `--format="%s %n"` formats the output to show the size (`%s`) and the name (`%n`) of each file. 2. `awk '{print $1 " " $NF}'`: - This `awk` command simply ensures the output format is "<size> <filename>", which might be redundant in this context given the `stat` format but is useful for clarity. 3. `sort -k1,1 -n | sort -k1.1,1.1 -n`: - The first `sort` command sorts the output numerically (`-n`) based on the first field (`-k1,1`), which is the size of the files. This step might not be strictly necessary for the final sorting requirement but can be useful for intermediate sorting. - The second `sort` command focuses on sorting based on the least significant digit of the file sizes. It sorts numerically on the first character of the first field. 4. `awk '{print $2}'`: - This extracts and prints just the filename from the sorted output. 5. `sed 's!.*/!!'`: - This `sed` command strips the directory path from the filenames, leaving only the file names themselves. This step is necessary if the `find` command returns full paths, which it does by default. Remember to give execution permission to your script using `chmod +x scriptname.sh` and then run it with `./scriptname.sh`. Please note, the approach to sort by the least significant digit of the file size directly is a bit unconventional. The script first sorts by the full size to ensure a consistent order before applying the least significant digit sorting. Adjustments might be required based on the exact output format and requirements.

Extract Code

I extracted the following code from that output:

#!/bin/bash

# Navigate to the directory, if needed
# cd foo/

# List files, get their sizes with stat, sort by the least significant digit, then extract the filename
find foo/ -type f -exec stat --format="%s %n" {} \; | 
awk '{print $1 " " $NF}' | 
sort -k1,1 -n | 
sort -k1.1,1.1 -n | 
awk '{print $2}' |
sed 's!.*/!!'

Run Code Interpreter

Running the following program:

#!/bin/bash

# Navigate to the directory, if needed
# cd foo/

# List files, get their sizes with stat, sort by the least significant digit, then extract the filename
find foo/ -type f -exec stat --format="%s %n" {} \; | 
awk '{print $1 " " $NF}' | 
sort -k1,1 -n | 
sort -k1.1,1.1 -n | 
awk '{print $2}' |
sed 's!.*/!!'

And got the output:

PyFunc

Resulting in output: 2 9 6 4 7 8 3 5 1 0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

To achieve this task in Bash, you will first need to list all files in the `foo/` directory, then obtain their sizes, sort them based on the least significant digit of their sizes, and finally extract and print just the file names in the sorted order. This task can be broken into several steps and can be accomplished using a combination of Bash commands and scripting features. Here is a step-by-step guide and a combined command that does this: 1. **List files and their sizes**: Use `find` to list all files in the `foo/` directory and `stat` to get their sizes. 2. **Sort by least significant digit**: Use `sort` and `awk` to sort the files based on the least significant digit of their sizes. 3. **Extract and print filenames**: Use `awk` or `cut` to extract and print just the filenames. Below is a Bash command that performs the above steps:

find foo/ -type f -exec stat --format="%s %n" {} + | \
awk '{print $1 " " $NF}' | \
sort -k1,1 -g | \
awk '{size=$1; name=$2; least_significant_digit=size%10; print least_significant_digit " " name;}' | \
sort -k1,1n -k2 | \
cut -d ' ' -f2-

Here's a breakdown of what each part does: - `find foo/ -type f -exec stat --format="%s %n" {} +`: This command finds all files (`-type f`) within the `foo/` directory and executes (`-exec`) `stat` on them to get their sizes (`%s`) and names (`%n`). The `{}` is replaced by the found file names. - `awk '{print $1 " " $NF}'`: Although not strictly necessary given the direct output of `stat`, this is a placeholder for potentially more complex manipulations. It prints the size and the filename. - `sort -k1,1 -g`: This sorts the output based on the file size. It's primarily to organize data before the main sorting and might be optional depending on the exact requirements for the least significant digit sorting. - `awk '{size=$1; name=$2; least_significant_digit=size%10; print least_significant_digit " " name;}'`: This `awk` command calculates the least significant digit of the size and prints it along with the file name. - `sort -k1,1n -k2`: This sorts the output first by the least significant digit (numerically) and then by the file name if you need a secondary sorting criterion. - `cut -d ' ' -f2-`: Finally, this command cuts out the least significant digit (and the space), leaving only the sorted file names. **Note:** This solution assumes that your filenames do not contain newline characters. Handling filenames with special characters (spaces, newlines, etc.) requires additional considerations in shell scripts. Let's simplify and correct the script focusing strictly on sorting by the least significant digit of the file sizes:

find foo/ -type f -printf "%s %p\n" | \
awk '{print $1 " " $NF}' | \
awk '{print ($1 % 10) " " $2}' | \
sort -k1,1n | \
cut -d ' ' -f2-

- `find foo/ -type f -printf "%s %p\n"`: Directly prints file sizes and paths, simplifying the initial steps. - The rest of the pipeline processes these outputs as described, focused on sorting by the least significant digit of the size.

Extract Code

I extracted the following code from that output:

#!/bin/bash

# This script lists all files in the `foo/` directory, sorts them by the least significant digit of their sizes, and prints the filenames in sorted order.

find foo/ -type f -printf "%s %p\n" | \
awk '{print $1 " " $NF}' | \
awk '{print ($1 % 10) " " $2}' | \
sort -k1,1n | \
cut -d ' ' -f2-

Run Code Interpreter

Running the following program:

#!/bin/bash

# This script lists all files in the `foo/` directory, sorts them by the least significant digit of their sizes, and prints the filenames in sorted order.

find foo/ -type f -printf "%s %p\n" | \
awk '{print $1 " " $NF}' | \
awk '{print ($1 % 10) " " $2}' | \
sort -k1,1n | \
cut -d ' ' -f2-

And got the output:

foo/2
foo/0
foo/5
foo/7
foo/1
foo/6
foo/4
foo/3
foo/9
foo/8

PyFunc

Resulting in output: foo/2 foo/0 foo/5 foo/7 foo/1 foo/6 foo/4 foo/3 foo/9 foo/8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

To list all files in the directory `foo/` sorted by the least significant digit of their size, you can use a combination of `ls`, `awk`, and `sort`. Here's a command pipeline that achieves this:

ls -l foo/ | awk 'NR>1 {print $5 " " $9}' | sort -k1,1n -k2,2 | awk '{print $2}'

However, this command does not precisely fulfill the requirement of sorting only by the least significant digit of their size. To achieve that specific requirement, we can use a more sophisticated approach that extracts the least significant digit of the file size and then sorts based on that. Here's an approach using `find`, `stat`, `sort`, and `awk`:

find foo/ -type f -exec stat --format '%s %n' {} + | \
awk '{print $1 " " $2}' | \
awk '{size=$1; file=$2; lsd=size%10; print lsd " " size " " file}' | \
sort -k1,1n -k2,2n | \
awk '{print $3}'

This pipeline explained: 1. `find foo/ -type f -exec stat --format '%s %n' {} +`: This command finds all files (`-type f`) under `foo/`, and for each file, it executes `stat` to print its size in bytes (`%s`) followed by its name (`%n`). 2. The first `awk '{print $1 " " $2}'` is actually redundant in this context because the output of `stat` already has the desired format. I included it for clarity, but it can be omitted. 3. The second `awk` command processes each line, extracts the file size and the file path, calculates the least significant digit of the file size (`lsd=size%10`), and prints the least significant digit, the original size, and the file path. 4. `sort -k1,1n -k2,2n` sorts the output first by the least significant digit (numerically) and then by the original size as a secondary sort key, also numerically. 5. The final `awk '{print $3}'` extracts and prints just the file paths/names, which are now sorted as required. Note: This will list files with their relative paths from `foo/`. If you want just the filenames without the path, you might need to adjust the `stat` command or add an additional `awk` or `sed` command to strip the path information, depending on your exact requirements and the structure of your directory. For a purely filename output, assuming paths don't contain newline characters, you might do something like:

... | awk '{gsub(/^.*\//, "", $3); print $3}'

This uses `gsub` to replace everything up to and including the last slash in the file path with nothing, effectively leaving just the filename. This would replace the final `awk '{print $3}'` command in the pipeline.

Extract Code

I extracted the following code from that output:

#!/bin/bash

# First Approach: Sorting by the full size, not just the least significant digit
ls -l foo/ | awk 'NR>1 {print $5 " " $9}' | sort -k1,1n -k2,2 | awk '{print $2}'

# Second Approach: Sorting by the least significant digit of the file size
find foo/ -type f -exec stat --format '%s %n' {} + | \
awk '{print $1 " " $2}' | \
awk '{size=$1; file=$2; lsd=size%10; print lsd " " size " " file}' | \
sort -k1,1n -k2,2n | \
awk '{print $3}'

Run Code Interpreter

Running the following program:

#!/bin/bash

# First Approach: Sorting by the full size, not just the least significant digit
ls -l foo/ | awk 'NR>1 {print $5 " " $9}' | sort -k1,1n -k2,2 | awk '{print $2}'

# Second Approach: Sorting by the least significant digit of the file size
find foo/ -type f -exec stat --format '%s %n' {} + | \
awk '{print $1 " " $2}' | \
awk '{size=$1; file=$2; lsd=size%10; print lsd " " size " " file}' | \
sort -k1,1n -k2,2n | \
awk '{print $3}'

And got the output:

8
2
9
6
4
7
3
5
1
0
foo/2
foo/0
foo/5
foo/7
foo/1
foo/6
foo/4
foo/3
foo/9
foo/8

PyFunc

Resulting in output: 8 2 9 6 4 7 3 5 1 0 foo/2 foo/0 foo/5 foo/7 foo/1 foo/6 foo/4 foo/3 foo/9 foo/8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

LLM Generation

Query

Output

You can achieve this using a combination of shell commands in Bash. The basic idea is to list all files in the directory `foo/`, get their sizes using `stat`, sort them based on the least significant digit of their size, and then extract and print the filenames. Here's a command pipeline that does exactly that:

ls -1 foo/ | while read filename; do
    echo "$(stat --printf="%s %n\n" "foo/$filename")";
done | sort -k1,1n -k2,2 | awk '{print substr($1, length($1), 1), $2}' | sort -k1,1n | cut -d' ' -f2- | awk -F'/' '{print $NF}'

Here's a breakdown of how this works: 1. `ls -1 foo/`: Lists all files in directory `foo/`, one file per line. 2. `while read filename; do ... done`: This reads each filename output by `ls` and processes it in the loop. 3. `echo "$(stat --printf="%s %n\n" "foo/$filename")"`: For each file, this uses `stat` to print its size (`%s`) and name (`%n`), separated by a space. The format is `<size> <filename>`. 4. `sort -k1,1n -k2,2`: First sorts the output by size to ensure that files with the same least significant digit in their size are then sorted by their full size or name. This might be necessary if you want that secondary level of sorting for files whose sizes end with the same digit. 5. `awk '{print substr($1, length($1), 1), $2}'`: This extracts the least significant digit of the size and prints it along with the filename. 6. `sort -k1,1n`: Sorts the output by the least significant digit of the file size. 7. `cut -d' ' -f2-`: Removes the least significant digit from the output, leaving just the file paths. 8. `awk -F'/' '{print $NF}'`: Extracts just the filename from the path, assuming `foo/` prefix is present in the output. Adjust the `cut` and `awk` usage as necessary depending on the exact format of the filenames you're dealing with. Note: This pipeline assumes that filenames do not contain newline characters. Handling filenames with special characters (including spaces, newlines, etc.) in shell scripts requires careful consideration, especially when parsing `ls` output. For scripts dealing with arbitrary filenames, it's safer to use `find ... -exec` or `find ... -print0 | xargs -0`, etc., which can handle unusual filenames more robustly. However, for most conventional uses, the above pipeline offers a practical solution to the task described.

Extract Code

I extracted the following code from that output:

ls -1 foo/ | while read filename; do
    echo "$(stat --printf="%s %n\n" "foo/$filename")";
done | sort -k1,1n -k2,2 | awk '{print substr($1, length($1), 1), $2}' | sort -k1,1n | cut -d' ' -f2- | awk -F'/' '{print $NF}'

Run Code Interpreter

Running the following program:

ls -1 foo/ | while read filename; do
    echo "$(stat --printf="%s %n\n" "foo/$filename")";
done | sort -k1,1n -k2,2 | awk '{print substr($1, length($1), 1), $2}' | sort -k1,1n | cut -d' ' -f2- | awk -F'/' '{print $NF}'

And got the output:

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True