Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To achieve the task of listing all files in a directory (`foo/` in your case), and sorting them by the least significant digit of their sizes, you can use a combination of shell commands and scripting techniques. Here's a way to do it using `ls`, `awk`, `sort`, and `cut` in a bash environment.

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#!/bin/bash

# Navigate to the directory (optional, you can also work with absolute paths)
cd foo/

# List files and their sizes using `ls` and `-l`, then process the list
ls -l | grep '^-' | awk '{print $5 " " $9}' | \
    awk '{print $1 % 10, $0}' | sort -n | cut -d' ' -f3-
Here's a breakdown of how this works: 1. `ls -l`: Lists files in long format, which includes file sizes. 2. `grep '^-'`: Filters out directories, symbolic links, etc., so only regular files are processed. 3. The first `awk '{print $5 " " $9}'` prints the size of the file and the filename. `$5` is typically the column for size, and `$9` is the filename in the output of `ls -l`. 4. The second `awk '{print $1 % 10, $0}'` appends the least significant digit of the file size (size modulo 10) to the start of each line for sorting purposes. 5. `sort -n`: Sorts the output numerically based on the first field, which is now the least significant digit of the file size. 6. `cut -d' ' -f3-`: Removes the first two fields (the least significant digit and the full size) from the line, leaving only the filenames. Note: This script assumes that filenames do not contain newline characters. **Important Considerations:** - Parsing `ls` can be problematic, especially with filenames that include unusual characters (e.g., newlines, spaces). Whenever possible, use tools like `find` or `stat` in combination with `xargs` or `while read` loops for more robust filename handling. - This approach does not handle subdirectories named in `foo/` (because of `grep '^-'`), and it assumes your filenames don't contain spaces. If your filenames might contain spaces or other special characters, consider a different approach or modify the script to handle these cases correctly. - The behavior of `awk '{print $5 " " $9}'` depends on the specific format of `ls -l` output, which can vary between systems and locales. Always test scripts on your target environment. For environments or situations where filenames may contain spaces or special characters, a more robust approach using `find`, `stat`, and a more complex sorting mechanism might be necessary.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

# Navigate to the directory (optional, you can also work with absolute paths)
cd foo/

# List files and their sizes using `ls` and `-l`, then process the list
ls -l | grep '^-' | awk '{print $5 " " $9}' | \
    awk '{print $1 % 10, $0}' | sort -n | cut -d' ' -f3-

Run Code Interpreter

Running the following program:

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#!/bin/bash

# Navigate to the directory (optional, you can also work with absolute paths)
cd foo/

# List files and their sizes using `ls` and `-l`, then process the list
ls -l | grep '^-' | awk '{print $5 " " $9}' | \
    awk '{print $1 % 10, $0}' | sort -n | cut -d' ' -f3-
And got the output: 2 0 5 7 1 6 4 3 9 8

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To achieve this in bash, you can leverage the `ls` and `awk` commands, combined with sorting functionalities. However, the exact behavior you're asking for – sorting by the least significant digit of their size – isn't directly available through standard command line tools like `ls` or `sort`. You would need a custom command pipeline to extract file sizes, sort by the desired criteria, and then list the files. Here's a bash script that does what you want:

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#!/bin/bash

# Navigate to the directory, replace 'foo/' with your actual directory path
cd foo/

# List files and their sizes using stat, sort by the least significant digit of their sizes, and then print file names
stat --format="%s %n" * | \
awk '{ print $1 " " $2 }' | \
sort -k1,1 -g | \
sort -k1.1,1.1 | \
awk '{ print $2 }'
Here's what each part does: 1. `stat --format="%s %n" *` lists all files (*) in the current directory, outputting their size (`%s`) and name (`%n`). 2. The first `awk '{ print $1 " " $2 }'` is actually redundant in this context since `stat` already provides the needed format. It's just for illustration; you could skip this step. 3. `sort -k1,1 -g` sorts the list numerically by the file size (entire size, not just the least significant digit). This step is necessary to organize the list before applying the final sorting based on the least significant digit. 4. `sort -k1.1,1.1` attempts to sort by the first character of the key, which doesn't directly apply to sorting by the least significant digit of the file size. Instead, you would need a custom sorting method for the least significant digit. This step doesn't achieve the intended effect and needs modification. To properly sort by the least significant digit of the file sizes, you would need a more customized approach, as the direct use of `sort` like this won't achieve the desired outcome. Here's a revised approach:
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#!/bin/bash

cd foo/

# List files, get their sizes, and sort by the least significant digit
stat --format="%s %n" * | \
awk '{ print $1 " " $2 }' | \
awk '{print substr($1,length($1),1) " " $0}' | \
sort -k1,1n | \
awk '{print $3}'
This script does the following: 1. `stat --format="%s %n" *` lists all files with their sizes. 2. The first `awk` command is again just for illustration and can be omitted. 3. The second `awk '{print substr($1,length($1),1) " " $0}'` command extracts the least significant digit of the size and prepends it to the line for sorting. 4. `sort -k1,1n` then sorts the lines numerically by the least significant digit (now the first field). 5. The final `awk '{print $3}'` command strips off the sorting keys, leaving just the file names. This approach should give you the filenames sorted by the least significant digit of their sizes. Note that complex file naming or unusual file sizes might require adjustments to the script.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

cd foo/

# List files, get their sizes, and sort by the least significant digit
stat --format="%s %n" * | \
awk '{ print $1 " " $2 }' | \
awk '{print substr($1,length($1),1) " " $0}' | \
sort -k1,1n | \
awk '{print $3}'

Run Code Interpreter

Running the following program:

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#!/bin/bash

cd foo/

# List files, get their sizes, and sort by the least significant digit
stat --format="%s %n" * | \
awk '{ print $1 " " $2 }' | \
awk '{print substr($1,length($1),1) " " $0}' | \
sort -k1,1n | \
awk '{print $3}'
And got the output: 2 0 5 7 1 6 4 3 9 8

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To achieve this in bash, you can use a combination of commands to list the files in `foo/`, obtain their sizes, sort them by the least significant digit of their size, and then extract the filenames. Here's a way to do it:

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ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1,1n -k2,2 | awk '{print $2}'
However, the above command does not directly sort the files by the least significant digit of their sizes. To sort the files by the least significant digit of their sizes and then by the full size if you want that as a secondary sort criterion, you can use the following approach:
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ls -l foo/ | awk 'NR>1 {print $5, $9}' | sort -k1,1n | awk '{print $2}' | while read filename; do
  echo "$(stat -c %s foo/"$filename" | awk '{print substr($1,length($1),1)}') $filename";
done | sort -k1,1n | cut -d' ' -f2-
However, this might not work perfectly if filenames contain special characters like spaces. To handle filenames more robustly (including those with special characters), you can use the following approach:
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#!/bin/bash

while IFS= read -r -d '' file; do
    size=$(stat --format="%s" "$file")
    least_significant_digit=$(echo $size | grep -o . | tail -1)
    echo "$least_significant_digit $file"
done < <(find foo/ -type f -print0) | sort -k1,1n -k2,2 | awk '{print substr($0, index($0, $2))}'
This script does the following: 1. Uses `find foo/ -type f -print0` to list all files under `foo/`, including those with special characters in their names, and outputs them with a null character as a delimiter. 2. For each file, it calculates the file size using `stat --format="%s"`. 3. Extracts the least significant digit of the size. 4. Prints the least significant digit followed by the full path of the file. 5. Sorts the output by the least significant digit (and then by the full path to keep it consistent for files with the same least significant digit). 6. Finally, it prints the filenames, removing the leading digits and space. Please note, if you only want the filenames without the path, you can modify the `awk` command at the end to specifically print out only the filename. For complex manipulation or formatting, you might need to adjust the command accordingly.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

while IFS= read -r -d '' file; do
    size=$(stat --format="%s" "$file")
    least_significant_digit=$(echo $size | grep -o . | tail -1)
    echo "$least_significant_digit $file"
done < <(find foo/ -type f -print0) | sort -k1,1n -k2,2 | awk '{print substr($0, index($0, $2))}'

Run Code Interpreter

Running the following program:

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#!/bin/bash

while IFS= read -r -d '' file; do
    size=$(stat --format="%s" "$file")
    least_significant_digit=$(echo $size | grep -o . | tail -1)
    echo "$least_significant_digit $file"
done < <(find foo/ -type f -print0) | sort -k1,1n -k2,2 | awk '{print substr($0, index($0, $2))}'
And got the output: foo/2 foo/0 foo/5 foo/7 foo/1 foo/6 foo/4 foo/3 foo/9 foo/8

PyFunc

Resulting in output: foo/2 foo/0 foo/5 foo/7 foo/1 foo/6 foo/4 foo/3 foo/9 foo/8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To achieve the sorting of files in `foo/` by the least significant digit of their size and then output just the file names, you can use a combination of shell commands. The `ls` command alone won't suffice for this sort of customized sorting. Instead, you'll need to use `stat` to get the file sizes, `sort` to sort by the desired criteria, and `awk` or `cut` for parsing and formatting the output. Here's how you can do it:

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#!/bin/bash

# Navigate to the directory (if needed, remove if you're already in the correct directory)
cd foo/

# List files, get their sizes, sort by the least significant digit, and extract the names
stat --format="%s %n" * | sort -k1,1n -k2,2 | awk '{ size=$1; name=$2; least_significant_digit=size%10; print least_significant_digit, name }' | sort -n | cut -d" " -f2-
Here's what each part does: 1. `stat --format="%s %n" *`: This command lists all files (`*` for all files in the current directory) and prints their size (`%s`) and name (`%n`). Adjust the path if you're not running it from within the target directory. 2. `sort -k1,1n -k2,2`: This initial sort is a safeguard in case you want a secondary sort condition (e.g., by name or full size if the least significant digits are equal). It sorts the output numerically by the first field (size) and then by the second field (name) if needed. This step might be optional based on your specific needs. 3. `awk '{ size=$1; name=$2; least_significant_digit=size%10; print least_significant_digit, name }'`: `awk` processes each line, calculates the least significant digit of the size, and prints it along with the file name. 4. `sort -n`: This sorts the output from the `awk` command numerically, based on the least significant digit of the file size. 5. `cut -d" " -f2-`: Finally, `cut` is used to remove the least significant digit from the output, leaving only the file names. This will give you a list of file names sorted by the least significant digit of their file sizes. If you want to include hidden files, you may need to adjust the glob patterns or use different options/tools depending on the shell environment and its version.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

# Navigate to the directory (if needed, remove if you're already in the correct directory)
cd foo/

# List files, get their sizes, sort by the least significant digit, and extract the names
stat --format="%s %n" * | sort -k1,1n -k2,2 | awk '{ size=$1; name=$2; least_significant_digit=size%10; print least_significant_digit, name }' | sort -n | cut -d" " -f2-

Run Code Interpreter

Running the following program:

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#!/bin/bash

# Navigate to the directory (if needed, remove if you're already in the correct directory)
cd foo/

# List files, get their sizes, sort by the least significant digit, and extract the names
stat --format="%s %n" * | sort -k1,1n -k2,2 | awk '{ size=$1; name=$2; least_significant_digit=size%10; print least_significant_digit, name }' | sort -n | cut -d" " -f2-
And got the output: 2 0 5 7 1 6 4 3 9 8

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To achieve the listing of files in `foo/` directory, sorted by the least significant digit of their size and then output just the file names (without paths or sizes), you can use the following approach in bash. This task requires a bit of command-line creativity, combining `ls`, `awk`, and `sort` commands, among possible other utilities. Here's a step-by-step approach using `ls`, `awk`, `sort`, and `cut`: 1. **List files with their sizes**: Use `ls` with the `-l` and `-S` options to list files along with their sizes. The `-S` option is not necessary for the sorting requirement but is often used in size-related listings. Since we're focusing on the least significant digit, we won't use `-S` in this solution. 2. **Extract the filename and size**: You can use `awk` to print the filename and its size. 3. **Sort by the least significant digit of their size**: Use `sort` based on the custom requirement. 4. **Extract the sorted filenames**: Finally, use `cut` or `awk` to extract and display only the filenames. Here is a command that combines these steps. This command assumes that you are dealing with regular files (not directories, symbolic links, etc.) and that filenames do not contain newline characters:

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find foo/ -type f -printf "%s %f\n" | awk '{print $1 " " $NF}' | sort -k1,1n -k2,2 | awk '{print substr($1, length($1), 1) " " $2}' | sort -n | cut -d' ' -f2-
Here's what each part does: - `find foo/ -type f -printf "%s %f\n"`: Lists all files in `foo/` with their sizes and names. - `awk '{print $1 " " $NF}'`: This is actually redundant in this context since `find`'s `-printf` already formats the output as needed. It's kept here for clarity or in case you need to adjust the output format. - `sort -k1,1n -k2,2`: This first sort is redundant given the final sorting step; initially, it was intended to sort files by size then name, but the final requirement focuses solely on the least significant digit. - `awk '{print substr($1, length($1), 1) " " $2}'`: Extracts the least significant digit of the size and the filename. - `sort -n`: Sorts the results numerically based on the least significant digit. - `cut -d' ' -f2-`: Extracts and displays the filenames, excluding the leading digit. Remember, this solution assumes file sizes are listed in bytes by `find`, and filenames do not have spaces. Handling filenames with spaces or newline characters would require a more robust delimiter handling between each step.

Extract Code

I extracted the following code from that output:

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find foo/ -type f -printf "%s %f\n" | awk '{print $1 " " $NF}' | sort -k1,1n -k2,2 | awk '{print substr($1, length($1), 1) " " $2}' | sort -n | cut -d' ' -f2-

Run Code Interpreter

Running the following program:

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find foo/ -type f -printf "%s %f\n" | awk '{print $1 " " $NF}' | sort -k1,1n -k2,2 | awk '{print substr($1, length($1), 1) " " $2}' | sort -n | cut -d' ' -f2-
And got the output: 2 0 5 7 1 6 4 3 9 8

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True