I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can use the following command to list all files in the "foo" directory and sort them by the least significant digit of their size:
1 | ls -Sl foo/ | awk '{print $9}' |
I extracted the following code from that output:
1 | ls -Sl foo/ | awk '{print $9}' |
Running the following program:
1 | ls -Sl foo/ | awk '{print $9}' |
0
1
5
3
7
4
6
9
2
8
Resulting in output: 0 1 5 3 7 4 6 9 2 8
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can use the following command to list all files in the "foo/" directory and sort them by the least significant digit of their size:
1 | ls -l foo/ | awk '{print $9}' | sort -k 5 |
I extracted the following code from that output:
1 | ls -l foo/ | awk '{print $9}' | sort -k 5 |
Running the following program:
1 | ls -l foo/ | awk '{print $9}' | sort -k 5 |
0
1
2
3
4
5
6
7
8
9
Resulting in output: 0 1 2 3 4 5 6 7 8 9
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can use the following command to list all files in the `foo/` directory and sort them by the least significant digit of their size:
1 | ls -lS foo/ | awk '{print $9}' | sort -nk1 |
I extracted the following code from that output:
1 | ls -lS foo/ | awk '{print $9}' | sort -nk1 |
Running the following program:
1 | ls -lS foo/ | awk '{print $9}' | sort -nk1 |
0
1
2
3
4
5
6
7
8
9
Resulting in output: 0 1 2 3 4 5 6 7 8 9
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this by using the `ls` command with the `-S` flag to sort by size and then piping the output to `awk` to print only the file names. Here's the command you can use:
1 | ls -S foo/ | awk '{print $9}' |
I extracted the following code from that output:
1 | ls -S foo/ | awk '{print $9}' |
Running the following program:
1 | ls -S foo/ | awk '{print $9}' |
Resulting in output:
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can use the following command in bash to list all files in the directory "foo/" and sort them by the least significant digit of their size:
1 | ls -lS foo/ | awk '{print $9}' | sed 's/.*[0-9]\([0-9]\)$/\1/' | sort | awk '!seen[$0]++' |
I extracted the following code from that output:
1 | ls -lS foo/ | awk '{print $9}' | sed 's/.*[0-9]\([0-9]\)$/\1/' | sort | awk '!seen[$0]++' |
Running the following program:
1 | ls -lS foo/ | awk '{print $9}' | sed 's/.*[0-9]\([0-9]\)$/\1/' | sort | awk '!seen[$0]++' |
0
1
2
3
4
5
6
7
8
9
Resulting in output: 0 1 2 3 4 5 6 7 8 9
Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8
: False