I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this by using the following command:
1 | ls -S foo/ | sort -n -k1.1 | awk '{print $9}' |
I extracted the following code from that output:
1 | ls -S foo/ | sort -n -k1.1 | awk '{print $9}' |
Running the following program:
1 | ls -S foo/ | sort -n -k1.1 | awk '{print $9}' |
Resulting in output:
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this by using the following command in bash:
1 | ls -lS foo/ | awk '{print $9}' |
I extracted the following code from that output:
1 | ls -lS foo/ | awk '{print $9}' |
Running the following program:
1 | ls -lS foo/ | awk '{print $9}' |
0
1
5
3
7
4
6
9
2
8
Resulting in output: 0 1 5 3 7 4 6 9 2 8
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can achieve this by using the `ls` command with the `-S` flag to sort by file size, and then piping the output to `awk` to extract and print only the file names. Here's the command you can use:
1 | ls -S foo/ | awk '{print $9}' |
I extracted the following code from that output:
1 | ls -S foo/ | awk '{print $9}' |
Running the following program:
1 | ls -S foo/ | awk '{print $9}' |
Resulting in output:
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can use the following command to achieve this:
1 | ls -S foo/ | awk '{print $NF}' |
I extracted the following code from that output:
1 | ls -S foo/ | awk '{print $NF}' |
Running the following program:
1 | ls -S foo/ | awk '{print $NF}' |
0
1
5
3
7
4
6
9
2
8
Resulting in output: 0 1 5 3 7 4 6 9 2 8
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: False
I have setup the docker container to run the model evaluation.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.
You can use the following command to achieve this:
1 | ls -lS foo/ | awk '{print $9}' | sed 's/foo\///' | sort -n |
I extracted the following code from that output:
1 | ls -lS foo/ | awk '{print $9}' | sed 's/foo\///' | sort -n |
Running the following program:
1 | ls -lS foo/ | awk '{print $9}' | sed 's/foo\///' | sort -n |
0
1
2
3
4
5
6
7
8
9
Resulting in output: 0 1 2 3 4 5 6 7 8 9
Testing if the previous output equals the string 2 0 5 7 1 6 4 3 9 8
: False