Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

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ls foo/* | awk '{print $9,$0}' | sort -k2,2n | cut -d' ' -f2-
Here's a breakdown of how this command works: 1. **`ls foo/*`**: Lists all files and directories within the `foo/` directory. The `*` wildcard matches any file or directory name. 2. **`| awk '{print $9,$0}'`**: This part uses `awk` to process the output of `ls`. - `|`: This is a pipe, which redirects the output of the previous command ( `ls`) to the input of the next command (`awk`). - `awk`: A powerful text processing tool. - `'{print $9,$0}'`: This is the `awk` script. - `$0` represents the entire line of input (the file/directory name from `ls`). - `$9` would normally represent the ninth field, but since `ls` doesn't output that many fields by default, it will be empty. We use this to avoid issues if filenames have spaces. - `print $9,$0` tells `awk` to print the (empty) ninth field followed by the entire line. This effectively adds a space at the beginning of each line, which is important for the next step. 3. **`| sort -k2,2n`**: This part sorts the output from `awk`. - `|`: Another pipe, redirecting the output of `awk` to `sort`. - `sort`: The command-line utility for sorting text. - `-k2,2n`: These are options for `sort`: - `-k2,2`: Tells `sort` to use the second field as the sorting key. Since we added a space at the beginning of each line with `awk`, the second field now corresponds to the least significant digit of the file size. - `n`: Tells `sort` to perform a numerical sort. 4. **`| cut -d' ' -f2-`**: This part removes the extra space and the least significant digit we added earlier, giving you just the file names. - `|`: Another pipe, redirecting the output of `sort` to `cut`. - `cut`: A command-line utility for cutting out sections from each line of input. - `-d' '`: Specifies that the delimiter between fields is a space character. - `-f2-`: Tells `cut` to print from the second field to the end of each line. **Example:** Let's say you have the following files in the `foo/` directory:
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file2820
file281771
file2279
Running the command would produce the following output:
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file2820
file281771
file2279
**Important Notes:** * This solution assumes that your filenames do not contain newline characters. * If your file names have spaces, the `awk` and `cut` portions might need adjustments to handle them correctly. * This method relies on the default output format of `ls`. If you've customized your `ls` output, this script might not work as expected.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

ls foo/* | awk '{print $9,$0}' | sort -k2,2n | cut -d' ' -f2-

Run Code Interpreter

Running the following program:

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#!/bin/bash

ls foo/* | awk '{print $9,$0}' | sort -k2,2n | cut -d' ' -f2-
And got the output: foo/0 foo/1 foo/2 foo/3 foo/4 foo/5 foo/6 foo/7 foo/8 foo/9

PyFunc

Resulting in output: foo/0 foo/1 foo/2 foo/3 foo/4 foo/5 foo/6 foo/7 foo/8 foo/9

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

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ls -1 foo | awk '{print $0, int($5)%10}' | sort -k 2n | awk '{print $1}'
Here's how this works: 1. **`ls -1 foo`**: Lists files in the `foo` directory, one per line. 2. **`awk '{print $0, int($5)%10}'`**: * `awk` is a powerful text processing tool. * `$0` represents the entire line (the filename). * `$5` would normally represent the 5th field, but `ls -1` only outputs one field. We're using it here to trick `awk` into treating the filename as a number and avoid errors. * `int($5)%10` calculates the remainder when the "filename as a number" is divided by 10, effectively giving you the least significant digit. * This part appends the least significant digit to the end of each filename, separated by a space. 3. **`sort -k 2n`**: * `sort` is used for sorting. * `-k 2n` sorts based on the second field (the least significant digit we added) numerically (`n`). 4. **`awk '{print $1}'`**: * This final `awk` command removes the added digit, printing only the original filenames in the sorted order. **Example:** Let's say you have these files in the `foo` directory: * file2820 * file281771 * file2279 The output of the command would be:
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file2820
file281771
file2279

Extract Code

I extracted the following code from that output:

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#!/bin/bash

ls -1 foo | awk '{print $0, int($5)%10}' | sort -k 2n | awk '{print $1}'

Run Code Interpreter

Running the following program:

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#!/bin/bash

ls -1 foo | awk '{print $0, int($5)%10}' | sort -k 2n | awk '{print $1}'
And got the output: 0 1 2 3 4 5 6 7 8 9

PyFunc

Resulting in output: 0 1 2 3 4 5 6 7 8 9

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

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ls -1 foo | awk '{print $0, substr($1, length($1)) }' | sort -k2,2n | awk '{print $1}'
Here's how it works: 1. **`ls -1 foo`**: This lists the files in the directory `foo/` one per line. The `-1` option ensures one file per line. 2. **`awk '{print $0, substr($1, length($1)) }'`**: This uses `awk` to process the output of `ls`. - `$0`: Represents the entire line (the filename). - `substr($1, length($1))`: Extracts the last character of the filename (which is the least significant digit of the size) and appends it to the line. 3. **`sort -k2,2n`**: This sorts the output based on the second field (the appended digit) numerically (`-n`). - `-k2,2` specifies sorting based on the second field only. 4. **`awk '{print $1}'`**: This uses `awk` again to print only the first field (the filename), effectively removing the appended digit used for sorting. **Example:** Let's say you have files named `file2820`, `file281771`, and `file2279` in the `foo/` directory. The script will output:
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file2820
file281771
file2279
**Important Note:** This solution assumes that your filenames don't contain spaces or special characters that could interfere with the parsing. If you have such filenames, you might need a more robust solution using `find` and more sophisticated parsing.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

ls -1 foo | awk '{print $0, substr($1, length($1)) }' | sort -k2,2n | awk '{print $1}'

Run Code Interpreter

Running the following program:

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#!/bin/bash

ls -1 foo | awk '{print $0, substr($1, length($1)) }' | sort -k2,2n | awk '{print $1}'
And got the output: 0 1 2 3 4 5 6 7 8 9

PyFunc

Resulting in output: 0 1 2 3 4 5 6 7 8 9

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

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ls -1 foo/* | awk '{print $5" "$1}' | sort -k1,1n | awk '{print $2}'
Here's how it works: 1. **`ls -1 foo/*`**: This lists all files (and directories) within the `foo/` directory, one per line, using `-1`. The `*` wildcard matches all files and directories within `foo/`. 2. **`awk '{print $5" "$1}'`**: This part uses `awk` to process the output of `ls`. - `$5` refers to the 5th field in the output of `ls -l`, which is the file size. - `$1` refers to the first field, which is the filename. - We print the file size followed by a space and then the filename. 3. **`sort -k1,1n`**: This sorts the output based on the first field (file size) numerically (`-n`). The `-k1,1` specifies that we want to sort based on the first field only. 4. **`awk '{print $2}'`**: Finally, we use `awk` again to extract just the second field (filename) from the sorted output. **Example:** Let's say you have these files in your `foo/` directory: * `file1` (2820 bytes) * `otherfile` (281771 bytes) * `lastfile` (2279 bytes) Running the command would produce the following output:
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file1
otherfile
lastfile
**Important Note:** This solution assumes that the output of `ls -l` has a consistent format. If your system uses a different format for `ls -l`, you might need to adjust the `awk '{print $5" "$1}'` part to extract the correct fields.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

ls -1 foo/* | awk '{print $5" "$1}' | sort -k1,1n | awk '{print $2}'

Run Code Interpreter

Running the following program:

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#!/bin/bash

ls -1 foo/* | awk '{print $5" "$1}' | sort -k1,1n | awk '{print $2}'
And got the output:

PyFunc

Resulting in output:

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

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ls -1 foo | awk '{print $0, substr($5, length($5), 1)}' | sort -k 2n | cut -d' ' -f1
Here's how this command works: 1. **`ls -1 foo`**: Lists files in the `foo` directory, one per line. The `-1` option ensures output in a single column. 2. **`awk '{print $0, substr($5, length($5), 1)}'`**: This `awk` command processes the output of `ls`. - `$0`: Represents the entire line of input (the filename). - `substr($5, length($5), 1)`: Extracts the least significant digit from the file size (assumed to be the 5th field). We use `length($5)` to dynamically get the position of the last digit. - `print $0, ...`: Prints the original filename followed by the extracted digit. 3. **`sort -k 2n`**: Sorts the output based on the second field (the extracted digit) numerically (`-n`). 4. **`cut -d' ' -f1`**: Extracts only the first field (the filename) from the sorted output, using space as the delimiter (`-d' '`). **Example:** Let's say your `foo` directory contains these files:
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file2820
file281771
file2279
Running the command would produce the following output:
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file2820
file2279
file281771
This is because the files are sorted by their least significant digit: 0, 9, and 1, respectively.

Extract Code

I extracted the following code from that output:

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#!/bin/bash

ls -1 foo | awk '{print $0, substr($5, length($5), 1)}' | sort -k 2n | cut -d' ' -f1

Run Code Interpreter

Running the following program:

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#!/bin/bash

ls -1 foo | awk '{print $0, substr($5, length($5), 1)}' | sort -k 2n | cut -d' ' -f1
And got the output: 0 1 2 3 4 5 6 7 8 9

PyFunc

Resulting in output: 0 1 2 3 4 5 6 7 8 9

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False