Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory, sort them based on the least significant digit of their size, and display only the file names, you can use the following Bash command: 

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ls -1 foo/* | awk '{print system("stat -c \"%s %n\" \""$0"\""),$0}' | sort -n -k1.9 | cut -d' ' -f2-
Let's break down the command: 1. `ls -1 foo/*`: Lists all files in the `foo/` directory, one file per line. 2. `awk '{print system("stat -c \"%s %n\" \""$0"\""),$0}'`: For each file, it uses the `stat` command to retrieve the file size and name. The `system()` function in `awk` executes the `stat` command and prints the output. The `%s` format specifier is used to get the file size, and `%n` is used to get the file name. The file name is also printed separately using `$0`. 3. `sort -n -k1.9`: Sorts the output numerically based on the 9th character of the first field (file size). The `-n` option sorts numerically, and `-k1.9` specifies the sorting key starting from the 9th character of the first field. 4. `cut -d' ' -f2-`: Removes the file sizes from the output and displays only the file names. The `-d' '` option sets the delimiter to a space, and `-f2-` selects the second field and all subsequent fields (file names). The output will be the file names sorted based on the least significant digit of their size. Example output: 
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file1
otherfile
lastfile
Note: This command assumes that the file names do not contain spaces. If your file names have spaces, you may need to modify the command accordingly.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

ls -1 foo/* | awk '{print system("stat -c \"%s %n\" \""$0"\""),$0}' | sort -n -k1.9 | cut -d' ' -f2-

Run Code Interpreter

Running the following program: 

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#!/bin/bash

ls -1 foo/* | awk '{print system("stat -c \"%s %n\" \""$0"\""),$0}' | sort -n -k1.9 | cut -d' ' -f2-
And got the output: foo/0 foo/1 foo/2 foo/3 foo/4 foo/5 foo/6 foo/7 foo/8 foo/9 foo/8 foo/0 foo/1 foo/2 foo/3 foo/4 foo/5 foo/6 foo/7 foo/9

PyFunc

Resulting in output: foo/0 foo/1 foo/2 foo/3 foo/4 foo/5 foo/6 foo/7 foo/8 foo/9 foo/8 foo/0 foo/1 foo/2 foo/3 foo/4 foo/5 foo/6 foo/7 foo/9

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory and sort them by the least significant digit of their size in Bash, you can use a combination of the `find` command, `awk`, and `sort`. Here's the command: 

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find foo/ -type f -print0 | xargs -0 ls -l | awk '{print $5, $9}' | sort -n -k1.1 | awk '{print $2}'
Let's break down the command: 1. `find foo/ -type f -print0`: This command finds all regular files in the `foo/` directory and prints their file paths, separating them with a null character (`\0`) instead of newlines. 2. `xargs -0 ls -l`: The `xargs` command takes the output of the previous command (file paths) and passes them as arguments to the `ls -l` command, which lists the files in long format, including their sizes. 3. `awk '{print $5, $9}'`: This `awk` command extracts the fifth field (file size) and the ninth field (file name) from the `ls -l` output. 4. `sort -n -k1.1`: The `sort` command sorts the lines numerically (`-n`) based on the first field (`-k1`) starting from the first character (`.1`). This effectively sorts the files by the least significant digit of their size. 5. `awk '{print $2}'`: Finally, this `awk` command extracts the second field (file name) from the sorted output, giving you the file names sorted by the least significant digit of their size. The output will be the file names sorted by the least significant digit of their size, like this: 
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file1
otherfile
lastfile
Note: This command assumes that the file names do not contain spaces. If your file names have spaces, you may need to modify the `awk` commands accordingly.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

find foo/ -type f -print0 | xargs -0 ls -l | awk '{print $5, $9}' | sort -n -k1.1 | awk '{print $2}'

Run Code Interpreter

Running the following program: 

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#!/bin/bash

find foo/ -type f -print0 | xargs -0 ls -l | awk '{print $5, $9}' | sort -n -k1.1 | awk '{print $2}'
And got the output: foo/8 foo/2 foo/9 foo/6 foo/4 foo/7 foo/3 foo/5 foo/1 foo/0

PyFunc

Resulting in output: foo/8 foo/2 foo/9 foo/6 foo/4 foo/7 foo/3 foo/5 foo/1 foo/0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory, sorted by the least significant digit of their size, you can use the following command in Bash: 

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ls foo/ | while read file; do
  size=$(stat -c %s "foo/$file")
  printf "%d %s\n" $((size % 10)) "$file"
done | sort -n | cut -d' ' -f2
Here's how the command works: 1. `ls foo/` lists all the files in the `foo/` directory. 2. The output of `ls` is piped (`|`) to a `while` loop, which reads each file name one by one. 3. Inside the loop, `stat -c %s "foo/$file"` is used to get the size of each file in bytes. The `-c` option specifies the format, and `%s` is the format specifier for the file size. 4. `printf "%d %s\n" $((size % 10)) "$file"` prints the least significant digit of the file size (obtained by taking the modulo 10 of the size) followed by the file name, separated by a space. The `%d` format specifier is used for the digit, and `%s` is used for the file name. 5. The output of the `while` loop is then piped to the `sort` command with the `-n` option, which sorts the lines numerically based on the least significant digit. 6. Finally, the `cut` command with the `-d' ' -f2` option is used to extract only the file names from the sorted output. The `-d' '` option specifies the space character as the delimiter, and `-f2` selects the second field (the file name). The final output will be the file names sorted based on the least significant digit of their size. For example, if the `foo/` directory contains the following files: - `file1` (size: 2820 bytes) - `otherfile` (size: 281771 bytes) - `lastfile` (size: 2279 bytes) The command will output: 
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lastfile
file1
otherfile
This is because the least significant digits of the file sizes are: - `lastfile`: 9 - `file1`: 0 - `otherfile`: 1 And the files are sorted based on these digits in ascending order.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

ls foo/ | while read file; do
  size=$(stat -c %s "foo/$file")
  printf "%d %s\n" $((size % 10)) "$file"
done | sort -n | cut -d' ' -f2

Run Code Interpreter

Running the following program: 

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#!/bin/bash

ls foo/ | while read file; do
  size=$(stat -c %s "foo/$file")
  printf "%d %s\n" $((size % 10)) "$file"
done | sort -n | cut -d' ' -f2
And got the output: 2 0 5 7 1 6 4 3 9 8

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory and sort them based on the least significant digit of their size, you can use a combination of the `find` command, `awk`, and `sort`. Here's how you can achieve this: 

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find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.${#1} | awk '{print $2}'
Let's break down the command: 1. `find foo/ -type f -printf "%f\t%s\n"`: This command finds all regular files (`-type f`) in the `foo/` directory and prints the filename (`%f`) followed by a tab (`\t`) and the file size (`%s`) for each file, with each entry on a new line (`\n`). 2. `awk '{print $2, $1}'`: This `awk` command swaps the order of the columns, so the file size comes first, and the filename comes second. This is necessary for the sorting step. 3. `sort -n -k1.${#1}`: This `sort` command sorts the lines numerically (`-n`) based on the first column (`-k1`), starting from the last character of the first column (`.${#1}`). This effectively sorts the lines based on the least significant digit of the file size. 4. `awk '{print $2}'`: Finally, this `awk` command prints only the second column, which contains the filenames. The output will be the filenames sorted based on the least significant digit of their size. For example, if the `foo/` directory contains the following files: - `file1` with size 2820 - `otherfile` with size 281771 - `lastfile` with size 2279 The command will output: 
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file1
lastfile
otherfile
This output reflects the sorting based on the least significant digit of the file sizes.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.${#1} | awk '{print $2}'

Run Code Interpreter

Running the following program: 

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#!/bin/bash

find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.${#1} | awk '{print $2}'
And got the output: sort: character offset is zero: invalid field specification '1.0'

PyFunc

Resulting in output: sort: character offset is zero: invalid field specification '1.0'

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory and sort them by the least significant digit of their size, you can use the following command in bash: 

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ls -1 foo/ | while read file; do
    size=$(stat -c %s "foo/$file")
    printf "%d\t%s\n" $((size % 10)) "$file"
done | sort -n | cut -f2-
Here's how the command works: 1. `ls -1 foo/`: Lists all files in the `foo/` directory, one file per line. 2. `while read file; do ... done`: Reads each file name into the `file` variable and performs the subsequent commands for each file. 3. `size=$(stat -c %s "foo/$file")`: Retrieves the size of the file using the `stat` command and stores it in the `size` variable. 4. `printf "%d\t%s\n" $((size % 10)) "$file"`: Prints the least significant digit of the file size (obtained by `size % 10`) and the file name, separated by a tab character. 5. `sort -n`: Sorts the output numerically based on the least significant digit of the file size. 6. `cut -f2-`: Removes the first field (least significant digit) from the output, leaving only the file names. The command will output the file names sorted by the least significant digit of their size, without showing the actual sizes. For example, if the `foo/` directory contains the following files: - file1 (size: 2820) - otherfile (size: 281771) - lastfile (size: 2279) The output will be: 
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file1
lastfile
otherfile
Note that this command assumes the file names do not contain newline characters or tabs. If your file names contain such characters, you may need to modify the command accordingly.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

ls -1 foo/ | while read file; do
    size=$(stat -c %s "foo/$file")
    printf "%d\t%s\n" $((size % 10)) "$file"
done | sort -n | cut -f2-

Run Code Interpreter

Running the following program: 

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#!/bin/bash

ls -1 foo/ | while read file; do
    size=$(stat -c %s "foo/$file")
    printf "%d\t%s\n" $((size % 10)) "$file"
done | sort -n | cut -f2-
And got the output: 2 0 5 7 1 6 4 3 9 8

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True