Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory and sort them based on the least significant digit of their size, you can use a combination of the `find` command, `awk`, and `sort`. Here's how you can achieve this: 

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find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.1 | awk '{print $2}'
Let's break down the command: 1. `find foo/ -type f -printf "%f\t%s\n"`: This command finds all regular files (`-type f`) in the `foo/` directory and prints their filenames (`%f`) and sizes (`%s`) separated by a tab character (`\t`). 2. `awk '{print $2, $1}'`: This `awk` command swaps the order of the columns, putting the size first and the filename second. 3. `sort -n -k1.1`: This `sort` command sorts the lines numerically (`-n`) based on the first character of the first field (`-k1.1`), which effectively sorts by the least significant digit of the size. 4. `awk '{print $2}'`: Finally, this `awk` command prints only the second column, which contains the filenames. The output will be the filenames sorted based on the least significant digit of their size, like this: 
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file1
otherfile
lastfile
The files with sizes ending in the same digit will be grouped together in the output, and within each group, the files will be sorted based on their full sizes.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.1 | awk '{print $2}'

Run Code Interpreter

Running the following program: 

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#!/bin/bash

find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.1 | awk '{print $2}'
And got the output: 8 2 9 6 4 7 3 5 1 0

PyFunc

Resulting in output: 8 2 9 6 4 7 3 5 1 0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory and sort them by the least significant digit of their size, you can use a combination of `find`, `awk`, and `sort` commands in bash. Here's how you can achieve this: 

1
find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.1 | awk '{print $2}'
Let's break down the command: 1. `find foo/ -type f -printf "%f\t%s\n"`: This command finds all regular files (`-type f`) in the `foo/` directory and prints their filenames (`%f`) followed by a tab character (`\t`) and their sizes (`%s`) on separate lines (`\n`). 2. `awk '{print $2, $1}'`: This command takes the output from the `find` command and swaps the order of the columns. It prints the size (`$2`) followed by a space and then the filename (`$1`). 3. `sort -n -k1.1`: This command sorts the lines numerically (`-n`) based on the first field (`-k1`) starting from the first character (`.1`). This effectively sorts the lines based on the least significant digit of the file sizes. 4. `awk '{print $2}'`: Finally, this command takes the sorted output and prints only the second field (`$2`), which is the filename. The final output will be the filenames sorted by the least significant digit of their sizes, without the file sizes. For example, if the `foo/` directory contains the following files: - `file1` (size: 2820) - `otherfile` (size: 281771) - `lastfile` (size: 2279) The command will output: 
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file1
lastfile
otherfile
Note that this command assumes that the filenames do not contain whitespace characters. If your filenames contain spaces or other special characters, you may need to modify the command accordingly.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.1 | awk '{print $2}'

Run Code Interpreter

Running the following program: 

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3
#!/bin/bash

find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.1 | awk '{print $2}'
And got the output: 8 2 9 6 4 7 3 5 1 0

PyFunc

Resulting in output: 8 2 9 6 4 7 3 5 1 0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory and sort them by the least significant digit of their size, you can use a combination of the `find` command, `awk`, and `sort`. Here's the command: 

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find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.1 | awk '{print $2}'
Explanation: 1. `find foo/ -type f`: This lists all the files (not directories) in the `foo/` directory. 2. `-printf "%f\t%s\n"`: This prints the filename (`%f`) and size (`%s`) separated by a tab character (`\t`). 3. `awk '{print $2, $1}'`: This swaps the order of the filename and size, so the size comes first. 4. `sort -n -k1.1`: This sorts the lines numerically (`-n`) based on the first field (`-k1`) and considers only the first character of the first field (`.1`), effectively sorting by the least significant digit of the size. 5. `awk '{print $2}'`: This prints only the second field, which is now the filename. The final output will be the filenames sorted by the least significant digit of their size, like this: 
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file1
otherfile
lastfile
Note: If you have filenames containing spaces or other special characters, you may need to modify the command slightly to handle those cases properly.

Extract Code

I extracted the following code from that output: 

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2
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#!/bin/bash

find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.1 | awk '{print $2}'

Run Code Interpreter

Running the following program: 

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2
3
#!/bin/bash

find foo/ -type f -printf "%f\t%s\n" | awk '{print $2, $1}' | sort -n -k1.1 | awk '{print $2}'
And got the output: 8 2 9 6 4 7 3 5 1 0

PyFunc

Resulting in output: 8 2 9 6 4 7 3 5 1 0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory and sort them based on the least significant digit of their size, you can use a combination of the `ls` command, `awk`, and `sort`. Here's the command: 

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ls -l foo/ | awk '{print $9, $5}' | sort -k2,2 -k1,1 | awk '{print $1}'
Let's break down the command: 1. `ls -l foo/`: Lists all files in the `foo/` directory with detailed information, including the file size. 2. `awk '{print $9, $5}'`: Extracts the file name (`$9`) and file size (`$5`) from the `ls` output. 3. `sort -k2,2 -k1,1`: Sorts the output based on two fields. The `-k2,2` option sorts based on the second field (file size) as the primary key, and `-k1,1` sorts based on the first field (file name) as the secondary key. 4. `awk '{print $1}'`: Extracts only the file names from the sorted output. The result will be a list of file names sorted based on the least significant digit of their size. For example, if you have the following files in the `foo/` directory: 
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foo/file1   (size: 2820)
foo/otherfile   (size: 281771)
foo/lastfile   (size: 2279)
The output of the command will be: 
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2
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lastfile
file1
otherfile
Note that this command assumes the file names do not contain spaces. If your file names have spaces, you may need to modify the `awk` commands accordingly.

Extract Code

I extracted the following code from that output: 

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3
#!/bin/bash

ls -l foo/ | awk '{print $9, $5}' | sort -k2,2 -k1,1 | awk '{print $1}'

Run Code Interpreter

Running the following program: 

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3
#!/bin/bash

ls -l foo/ | awk '{print $9, $5}' | sort -k2,2 -k1,1 | awk '{print $1}'
And got the output: 2 9 6 4 7 8 3 5 1 0

PyFunc

Resulting in output: 2 9 6 4 7 8 3 5 1 0

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory, sorted by the least significant digit of their size, you can use a combination of the `find` command, `awk`, `sort`, and `cut`. Here's the command: 

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find foo/ -type f -printf "%s %p\n" | awk '{print $1 % 10, $2}' | sort -n | cut -d' ' -f2- | awk -F/ '{print $NF}'
Let's break down the command: 1. `find foo/ -type f -printf "%s %p\n"`: This command finds all regular files in the `foo/` directory and prints their size (`%s`) and full path (`%p`) on separate lines. 2. `awk '{print $1 % 10, $2}'`: This `awk` command takes the output from the `find` command and calculates the least significant digit of the file size using the modulo operator (`% 10`). It then prints the least significant digit followed by the file path. 3. `sort -n`: This command sorts the output from the previous `awk` command numerically based on the least significant digit. 4. `cut -d' ' -f2-`: This command removes the least significant digit from the sorted output, leaving only the file paths. 5. `awk -F/ '{print $NF}'`: Finally, this `awk` command extracts just the file names from the file paths by splitting the paths on the forward slash (`/`) and printing the last field (`$NF`). The final output will be a list of file names in the `foo/` directory, sorted based on the least significant digit of their size. For example, if the `foo/` directory contains the following files: - `file1` (size: 2820 bytes) - `otherfile` (size: 281771 bytes) - `lastfile` (size: 2279 bytes) The command will output: 
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file1
lastfile
otherfile
Note: Make sure to replace `foo/` with the actual directory path you want to list files from.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

find foo/ -type f -printf "%s %p\n" | awk '{print $1 % 10, $2}' | sort -n | cut -d' ' -f2- | awk -F/ '{print $NF}'

Run Code Interpreter

Running the following program: 

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#!/bin/bash

find foo/ -type f -printf "%s %p\n" | awk '{print $1 % 10, $2}' | sort -n | cut -d' ' -f2- | awk -F/ '{print $NF}'
And got the output: 2 0 5 7 1 6 4 3 9 8

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True