Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list all files in the `foo/` directory, sorted by the least significant digit of their size, and display only the file names, you can use a combination of `ls`, `stat`, and `sort` commands in bash. Here's a one-liner that accomplishes this: 

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ls -1 foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s {})" "{}"' | sort -k1.${#1} | cut -d' ' -f2-
Let's break down this command: 1. `ls -1 foo/`: Lists files in the `foo/` directory, one per line. 2. `xargs -I {} bash -c '...'`: Runs a bash command for each file. 3. `printf "%s %s\n" "$(stat -c %s {})" "{}"`: Prints the file size and filename. 4. `sort -k1.${#1}`: Sorts based on the last character of the first field (file size). 5. `cut -d' ' -f2-`: Removes the file size, leaving only the filename. This command will output the filenames sorted by the least significant digit of their size. If you want to include hidden files (those starting with a dot), you can modify the `ls` command: 
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ls -1A foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s {})" "{}"' | sort -k1.${#1} | cut -d' ' -f2-
Note: This method assumes that the filenames don't contain spaces. If they do, you might need a more complex solution.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

ls -1 foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s {})" "{}"' | sort -k1.${#1} | cut -d' ' -f2-

Run Code Interpreter

Running the following program: 

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#!/bin/bash

ls -1 foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s {})" "{}"' | sort -k1.${#1} | cut -d' ' -f2-
And got the output: sort: character offset is zero: invalid field specification '1.0' stat: cannot statx '0': No such file or directory xargs: bash: terminated by signal 13

PyFunc

Resulting in output: sort: character offset is zero: invalid field specification '1.0' stat: cannot statx '0': No such file or directory xargs: bash: terminated by signal 13

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list files in the `foo/` directory, sorted by the least significant digit of their size, and display only the file names, you can use a combination of `ls`, `stat`, and `sort` commands in bash. Here's a one-liner that accomplishes this: 

1
ls -1 foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s {})" "{}"' | sort -k1 -n -t '' | cut -d' ' -f2-
Here's a breakdown of what this command does: 1. `ls -1 foo/`: Lists files in the `foo/` directory, one per line. 2. `xargs -I {} bash -c '...'`: Runs a bash command for each file. 3. `stat -c %s {}`: Gets the size of each file. 4. `printf "%s %s\n" "$(stat -c %s {})" "{}"`: Prints the file size and filename. 5. `sort -k1 -n -t ''`: Sorts based on the last digit of the file size. - `-k1`: Sort based on the first field (file size) - `-n`: Numeric sort - `-t ''`: Use an empty string as the field separator, effectively sorting by the last character 6. `cut -d' ' -f2-`: Removes the file size, leaving only the filename. This command will output just the filenames, sorted as you requested. For example: 
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file1
otherfile
lastfile
Note: This method assumes that the filenames don't contain spaces. If they do, you might need to modify the command to handle spaces in filenames properly.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

ls -1 foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s {})" "{}"' | sort -k1 -n -t '' | cut -d' ' -f2-

Run Code Interpreter

Running the following program: 

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#!/bin/bash

ls -1 foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s {})" "{}"' | sort -k1 -n -t '' | cut -d' ' -f2-
And got the output: sort: empty tab stat: cannot statx '0': No such file or directory xargs: bash: terminated by signal 13

PyFunc

Resulting in output: sort: empty tab stat: cannot statx '0': No such file or directory xargs: bash: terminated by signal 13

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To accomplish this in bash, you can use a combination of `ls`, `awk`, and `sort`. Here's a command that will do what you're asking: 

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ls -l foo/ | awk '{print $5 " " $9}' | sort -k1.${#1} -n | awk '{print $2}'
Let's break this down: 1. `ls -l foo/`: This lists the contents of the foo/ directory in long format. 2. `awk '{print $5 " " $9}'`: This extracts the file size (5th field) and filename (9th field) from the ls output. 3. `sort -k1.${#1} -n`: This sorts based on the last digit of the first field (file size). - `-k1.${#1}` specifies to sort based on the last character of the first field. - `-n` specifies a numeric sort. 4. `awk '{print $2}'`: This prints only the second field (filename) from the sorted output. If you want to handle hidden files as well, you can modify the command slightly: 
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ls -la foo/ | awk 'NR>1 {print $5 " " $9}' | sort -k1.${#1} -n | awk '{print $2}'
The `NR>1` in the first `awk` command skips the first line of `ls -la` output, which is the total block count. Note: This method assumes that filenames don't contain spaces. If you need to handle filenames with spaces, the command would need to be more complex. Also, be aware that this method reads the entire directory contents into memory, so it might not be suitable for directories with a very large number of files.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

ls -l foo/ | awk '{print $5 " " $9}' | sort -k1.${#1} -n | awk '{print $2}'

Run Code Interpreter

Running the following program: 

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#!/bin/bash

ls -l foo/ | awk '{print $5 " " $9}' | sort -k1.${#1} -n | awk '{print $2}'
And got the output: sort: character offset is zero: invalid field specification '1.0'

PyFunc

Resulting in output: sort: character offset is zero: invalid field specification '1.0'

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list files in the `foo/` directory, sorted by the least significant digit of their size, and display only the file names, you can use a combination of `ls`, `stat`, and `sort` commands in bash. Here's a one-liner that accomplishes this: 

1
ls -1 foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s foo/{})" "{}"' | sort -k1.${#1} | cut -d' ' -f2-
Here's a breakdown of what this command does: 1. `ls -1 foo/`: Lists the files in the `foo/` directory, one per line. 2. `xargs -I {} bash -c '...'`: Runs a bash command for each file. 3. `printf "%s %s\n" "$(stat -c %s foo/{})" "{}"`: For each file, prints its size followed by its name. 4. `sort -k1.${#1}`: Sorts based on the last character of the first field (which is the file size). `${#1}` expands to the length of the first argument, effectively selecting the last digit. 5. `cut -d' ' -f2-`: Removes the size information, leaving only the file names. This command will output the file names sorted by the least significant digit of their sizes, as requested. For example, if you have these files with their sizes: - file1 (2820 bytes) - otherfile (281771 bytes) - lastfile (2279 bytes) The output would be: 
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file1
otherfile
lastfile
Note: This method assumes that all files have at least one digit in their size. If you have empty files (0 bytes), you might need to adjust the command to handle that case.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

ls -1 foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s foo/{})" "{}"' | sort -k1.${#1} | cut -d' ' -f2-

Run Code Interpreter

Running the following program: 

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3
#!/bin/bash

ls -1 foo/ | xargs -I {} bash -c 'printf "%s %s\n" "$(stat -c %s foo/{})" "{}"' | sort -k1.${#1} | cut -d' ' -f2-
And got the output: sort: character offset is zero: invalid field specification '1.0' xargs: bash: terminated by signal 13

PyFunc

Resulting in output: sort: character offset is zero: invalid field specification '1.0' xargs: bash: terminated by signal 13

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

LLM Generation

Query

In bash how do I list all files in foo/ but sort the files by the least significant digit of their size so 2820 comes first and then 281771 and finally 2279. I want just the file names e.g., file1 otherfile lastfile.

Output

To list files in a directory sorted by the least significant digit of their size in bash, you can use the `ls` command combined with `sort` and some text processing. Here's a command that should do what you're asking: 

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ls -l foo/ | tail -n +2 | awk '{print $5 " " $9}' | sed 's/^[0-9]*\([0-9]\) /\1 /' | sort -n | cut -d' ' -f2
Let's break this down: 1. `ls -l foo/`: List files in long format in the foo/ directory. 2. `tail -n +2`: Skip the first line (total count) of the ls output. 3. `awk '{print $5 " " $9}'`: Extract the file size and filename. 4. `sed 's/^[0-9]*\([0-9]\) /\1 /'`: Keep only the least significant digit of the file size. 5. `sort -n`: Sort numerically based on the least significant digit. 6. `cut -d' ' -f2`: Extract only the filename. This command will output just the filenames, sorted as you requested. If you want to include hidden files (those starting with a dot), you can modify the first part of the command: 
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ls -la foo/ | tail -n +4 | awk '{print $5 " " $9}' | sed 's/^[0-9]*\([0-9]\) /\1 /' | sort -n | cut -d' ' -f2
Note: This method assumes that the file sizes are in bytes. If the `ls` output uses human-readable sizes (like K, M, G), you'll need a more complex solution. Also, be aware that this method may not work correctly for very large files (over 2^63 bytes) due to limitations in some versions of `ls`.

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

ls -l foo/ | tail -n +2 | awk '{print $5 " " $9}' | sed 's/^[0-9]*\([0-9]\) /\1 /' | sort -n | cut -d' ' -f2

Run Code Interpreter

Running the following program: 

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#!/bin/bash

ls -l foo/ | tail -n +2 | awk '{print $5 " " $9}' | sed 's/^[0-9]*\([0-9]\) /\1 /' | sort -n | cut -d' ' -f2
And got the output: 2 0 5 7 1 6 4 3 9 8

PyFunc

Resulting in output: 2 0 5 7 1 6 4 3 9 8

Regex Evaluation

Testing if the previous output matches the regex 2.*0.*5.*7.*1.*6.*4.*3.*9.*8: True