Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

LLM Generation

Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

Output

You can use the `grep` command with the `-L` (or `--files-without-match`) option to list files that do not contain a certain pattern. To ignore case, use the `-i` option. Here's the command to list all files in the current directory that do not contain "asdf" in their contents (case-insensitive): 

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grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$" | xargs -I{} ls -1 "{}" > /dev/null && echo "Files without 'asdf':" && ls -1 $(grep -vFf <(grep -ril --exclude-dir=.git -e "asdf" . | sed 's|/||' | grep -v "/$") .)
This command does the following: 1. `grep -ril --exclude-dir=.git -e "asdf" .`: Searches the current directory (excluding the `.git` directory) for files containing "asdf" (case-insensitive). The `-r` flag makes it recursive, and `-l` lists only the file names. 2. `grep -v "/$"`: Removes any files with a trailing slash, as they represent directories, not files. 3. `xargs -I{} ls -1 "{}" > /dev/null`: Confirms that the file names produced by the previous command do not contain any issues that would prevent them from being processed. 4. `echo "Files without 'asdf':"`: Prints a heading for the list of files without "asdf". 5. `ls -1 $(grep -vFf <(grep -ril --exclude-dir=.git -e "asdf" . | sed 's|/||' | grep -v "/$") .)`: Lists the files in the current directory that do not contain "asdf" in their contents. The `grep -vFf` command uses a list of file names obtained from the first `grep` command to exclude files containing "asdf". The `<(command)` syntax is called process substitution, which allows the output of a command to be used as a file name.

Extract Code

I extracted the following code from that output: 

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grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$" | xargs -I{} ls -1 "{}" > /dev/null && echo "Files without 'asdf':" && ls -1 $(grep -vFf <(grep -ril --exclude-dir=.git -e "asdf" . | sed 's|/||' | grep -v "/$") .)

Run Code Interpreter

Running the following program: 

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grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$" | xargs -I{} ls -1 "{}" > /dev/null && echo "Files without 'asdf':" && ls -1 $(grep -vFf <(grep -ril --exclude-dir=.git -e "asdf" . | sed 's|/||' | grep -v "/$") .)
And got the output: Files without 'asdf': archive11882.tar archive245976.tar asdf hello lower main.sh setup.py there this grep: .: Is a directory

Check if all of the following conditions are true:

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string lower: True

Final Answer: False

Substring Evaluation

Testing if the previous output contains the string asdf: True

Substring Evaluation

Testing if the previous output contains the string this: True

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string there: True

Final Answer: False

Substring Evaluation

Testing if the previous output contains the string hello: True

Final Answer: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

LLM Generation

Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

Output

You can use the `grep` command to search for files that do not contain a certain pattern. In this case, you can use the `-L` or `--files-without-match` option to list only the files that do not contain the pattern "asdf", and combine it with the `-i` or `--ignore-case` option to ignore case. Here is an example command that should do what you're looking for: 

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grep -ril --include=\* -L "asdf" .
Explanation of the options: * `-r` or `-R` : recursively search the directory and its subdirectories * `-i` : ignore case * `-L` : list only the files that do not contain the pattern * `--include=*` : include all files in the search (without this option, grep would only search files that have certain extensions) * `.` : search in the current working directory Note that this command may take some time to run if you have a large number of files in your working directory, especially if you are recursively searching subdirectories.

Extract Code

I extracted the following code from that output: 

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grep -ril --include=\* -L "asdf" .

Run Code Interpreter

Running the following program: 

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grep -ril --include=\* -L "asdf" .
And got the output: ./this ./hello ./asdf

Check if all of the following conditions are true:

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string lower: False

Final Answer: True

Substring Evaluation

Testing if the previous output contains the string asdf: True

Substring Evaluation

Testing if the previous output contains the string this: True

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string there: False

Final Answer: True

Substring Evaluation

Testing if the previous output contains the string hello: True

Final Answer: True

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

LLM Generation

Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

Output

You can use the `grep` command with the `-L` (or `--files-without-match`) option to list files that don't contain a certain pattern. To ignore case, you can use the `-i` option. Here's the command you can use to list all files in the current working directory that don't contain the string "asdf" (case-insensitive): 

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grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$" | xargs -I{} ls -l {} > /dev/null && ls -la | grep -vFxf <(grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$")
Explanation: 1. `grep -ril --exclude-dir=.git -e "asdf" .`: This command searches for the string "asdf" (case-insensitive) in the current directory recursively (`-r`) and outputs the file names only (`-l`). The `--exclude-dir=.git` option excludes the `.git` directory to avoid searching for the pattern in the Git repository. 2. `grep -v "/$"`: This command filters out directories from the output of the previous command, as `grep -l` outputs the names of both files and directories that contain the pattern. 3. `xargs -I{} ls -l {} > /dev/null`: This command expands the output of the previous command and passes each file name as an argument to the `ls -l` command, which shows the detailed information about each file. The output is redirected to `/dev/null` to discard it. This step is necessary to avoid an "Argument list too long" error when there are many files in the directory. 4. `ls -la`: This command lists all files and directories in the current directory, including hidden files (`-a`) and shows detailed information (`-l`). 5. `grep -vFxf <(grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$")`: This command filters out the files that contain the string "asdf" from the output of the previous command. The `-v` option inverts the match, the `-F` option tells `grep` to interpret the pattern as a list of fixed strings (instead of regular expressions), and the `-x` option tells `grep` to match the whole line. The pattern file is created by enclosing the `grep` command in `<()` and redirecting its output to a process substitution. Note: This command may not work correctly if the file names contain newline characters or other special characters that are interpreted by the shell. To handle such cases, you may need to use a more complex script that processes the file names one by one.

Extract Code

I extracted the following code from that output: 

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grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$" | xargs -I{} ls -l {} > /dev/null && ls -la | grep -vFxf <(grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$")

Run Code Interpreter

Running the following program: 

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grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$" | xargs -I{} ls -l {} > /dev/null && ls -la | grep -vFxf <(grep -ril --exclude-dir=.git -e "asdf" . | grep -v "/$")
And got the output: total 60 drwxr-xr-x 2 root root 4096 Feb 14 02:59 . drwxr-xr-x 1 root root 4096 Feb 14 02:58 .. -rw-rw-r-- 1 root root 10240 Feb 14 02:59 archive642915.tar -rw-rw-r-- 1 root root 10240 Feb 14 02:58 archive94072.tar -rw-r--r-- 1 root root 8 Feb 14 02:58 asdf -rw-r--r-- 1 root root 14 Feb 14 02:58 hello -rw-r--r-- 1 root root 14 Feb 14 02:58 lower -rw-r--r-- 1 root root 176 Feb 14 02:59 main.sh -rw-r--r-- 1 root root 255 Feb 14 02:58 setup.py -rw-r--r-- 1 root root 14 Feb 14 02:58 there -rw-r--r-- 1 root root 14 Feb 14 02:58 this

Check if all of the following conditions are true:

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string lower: True

Final Answer: False

Substring Evaluation

Testing if the previous output contains the string asdf: True

Substring Evaluation

Testing if the previous output contains the string this: True

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string there: True

Final Answer: False

Substring Evaluation

Testing if the previous output contains the string hello: True

Final Answer: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

LLM Generation

Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

Output

You can use the `grep` command with the `-L` or `--files-without-match` option to list files that do not contain a specific pattern. In this case, you want to search for files that don't contain the pattern "asdf" in a case-insensitive manner. Here's the command: 

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grep -rILi "asdf" . | grep -v "/$"
Explanation: 1. `grep -rILi "asdf" .`: This searches the current directory (`.`) recursively (`-r`) for files that do not contain the pattern "asdf" (`-L`) in a case-insensitive manner (`-i`). The output will be the names of files that do not contain the pattern. 2. `| grep -v "/$"`: This pipes the output of the previous command to another `grep` command, which filters out any files in subdirectories. The `-v` option inverts the match, so it only shows lines that do not contain the pattern "/$". The pattern "/$" matches lines that end with a slash, which indicates a directory or a file in a subdirectory. Note: If you want to exclude hidden files (files starting with a dot), you can add `--exclude-dir=.*/` before the `.` in the first `grep` command: 
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grep -rILi --exclude-dir=.*/ "asdf" . | grep -v "/$"

Extract Code

I extracted the following code from that output: 

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#!/bin/bash

main() {
  grep -rILi --exclude-dir=.*/ "asdf" . | grep -v "/$"
}

main "$@"

Run Code Interpreter

Running the following program: 

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#!/bin/bash

main() {
  grep -rILi --exclude-dir=.*/ "asdf" . | grep -v "/$"
}

main "$@"
And got the output:

Check if all of the following conditions are true:

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string lower: False

Final Answer: True

Substring Evaluation

Testing if the previous output contains the string asdf: False

Substring Evaluation

Testing if the previous output contains the string this: False

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string there: False

Final Answer: True

Substring Evaluation

Testing if the previous output contains the string hello: False

Final Answer: False

Docker Setup

I have setup the docker container to run the model evaluation.

Initial Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

LLM Generation

Query

In bash list all files in cwd that don't contain asdf in the contents (case-ignore)

Output

API request failed with status code 500

Extract Code

I extracted the following code from that output: 

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#include <iostream>

int main() {
  std::cout << "Hello, world!" << std::endl;
  return 0;
}

Run Code Interpreter

Running the following program: 

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#include <iostream>

int main() {
  std::cout << "Hello, world!" << std::endl;
  return 0;
}
And got the output: main.sh: line 4: syntax error near unexpected token `(' main.sh: line 4: `int main() {'

Check if all of the following conditions are true:

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string lower: False

Final Answer: True

Substring Evaluation

Testing if the previous output contains the string asdf: False

Substring Evaluation

Testing if the previous output contains the string this: False

Check this condition is not true:

Substring Evaluation

Testing if the previous output contains the string there: False

Final Answer: True

Substring Evaluation

Testing if the previous output contains the string hello: False

Final Answer: False